字符串模拟赛T2

// source code from laekov for c0x17
#define PRID "fkqh"
#include <cstdio>
#include <cstring>
#include <algorithm>

using namespace std;

const int maxn = ;

int n, l[maxn], q[maxn], vx[maxn], vy[maxn];
char a[maxn];

void manacher() {
    l[] = ;
    for (int i = , j = ; i < (n << ) - ; ++ i) {
        int r = ((j + ) >> ) + l[j] - ;
        int p = i >> , q = i - p;
        l[i] = (r >= q) ? min(r - q + , l[(j << ) - i]) : ;
        while (p - l[i] >=  && q + l[i] < n && a[p - l[i]] == a[q + l[i]])
            ++ l[i];
        if (q + l[i] -  > r)
            j = i;
    }
}

#define getLeft(x) (((x)>>1)-l[x]+1)
#define getRight(x) ((((x)+1)>>1)+l[x]-1)

void dp(bool d) {
    static int q[maxn];
    int hd = , tl = ;
    if (!d) {
        for (int i = ; i < n; ++ i) {
            if (!tl || getRight(i << ) > getRight(q[tl - ]))
                q[tl ++] = (i << );
            while (getRight(q[hd]) < i)
                ++ hd;
            vx[i] = (i << ) - q[hd] + ;
            if (i < n -  && getRight((i << ) + ) > getRight(q[tl - ]))
                q[tl ++] = (i << ) + ;
        }
    }
    else {
        for (int i = n - ; i >= ; -- i) {
            if (!tl || getLeft(i << ) < getLeft(q[tl - ]))
                q[tl ++] = (i << );
            while (getLeft(q[hd]) > i)
                ++ hd;
            vy[i] = q[hd] - (i << ) + ;
            if (i && getLeft((i << ) -) < getLeft(q[tl - ]))
                    q[tl ++] = (i << ) - ;
        }
    }
}

int main(int argc, char* args[]) {
    if (argc <  || strcmp(args[], "-nf")) {
        freopen(PRID ".in", "r", stdin);
        freopen(PRID ".out", "w", stdout);
    }
    scanf("%s", a);
    n = strlen(a);
    manacher();
    dp();
    dp();
    int ans = ;
    for (int i = ; i < n; ++ i)
        ans = max(ans, vx[i - ] + vy[i]);
    printf("%d\n", ans);
}