How do I create a zip file?(转)
Creating a zip file is a task that can easily be accomplished by using the classes ZipOutputStream and ZipEntry in the java.util.zip package.
First of all, I'm going to present to you a complete code snippet that will create a zip file containing all the files of a specified directory. The resulting zip file has the same name as the given directory, with the .zip extention. The archive will be a valid zip file which can be opened with almost all standard zip archivers, such as WinZip.
Here is the complete code - read on, after the code I'll explain some parts in detail.
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException; import java.util.zip.CRC32;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream; public class CreateZipFile
{ private final int BUFFER_SIZE = 4096; public void addFileToZip(ZipOutputStream zos, File file)
{
byte [] data = new byte[BUFFER_SIZE];
int len; FileInputStream fis = null;
try
{
ZipEntry entry = new ZipEntry(file.getName());
entry.setSize(file.length());
entry.setTime(file.lastModified()); zos.putNextEntry(entry);
fis = new FileInputStream(file); CRC32 crc32 = new CRC32();
while ((len = fis.read(data)) > -1)
{
zos.write(data, 0, len);
crc32.update(data, 0, len);
}
entry.setCrc(crc32.getValue()); zos.closeEntry();
}
catch (IOException ioe)
{
ioe.printStackTrace();
}
finally
{
try
{
if (fis != null)
{
fis.close();
}
}
catch (IOException ioe)
{
ioe.printStackTrace();
}
}
} public void createZipFile(String directory)
{
File dir = new File(directory);
if (dir.isDirectory())
{
File [] files = dir.listFiles();
if (files != null)
{
File zip = new File(dir.getName() + ".zip"); FileOutputStream fos = null;
ZipOutputStream zos = null; try
{
fos = new FileOutputStream(zip);
zos = new ZipOutputStream(fos);
zos.setMethod(ZipOutputStream.DEFLATED); for (int i = 0; i < files.length; i++)
{
if (files[i].isFile())
{
System.out.println("Zipping " + files[i].getName());
addFileToZip(zos, files[i]);
}
}
}
catch (FileNotFoundException fnfe)
{
fnfe.printStackTrace();
}
finally
{
if (zos != null)
{
try
{
zos.close();
}
catch (IOException ioe)
{
ioe.printStackTrace();
}
}
if (fos != null)
{
try
{
fos.close();
}
catch (IOException ioe)
{
ioe.printStackTrace();
}
}
}
}
}
else
{
System.out.println(dir.getName() + " is not a directory");
}
} public static void main(String [] args)
{
if (args.length == 1)
{
CreateZipFile czf = new CreateZipFile();
czf.createZipFile(args[0]);
}
else
{
System.out.println("usage: java CreateZipFile directory");
}
} }
The steps that you need to take in order to create a zip file are the following:
- open an OutputStream (for example a FileOutputStream)
- open a ZipOutputStream
- prepare a ZipEntry for each file you would like to add to the zip
- write the file data to the prepared ZipEntry
- close the ZipEntry
- repeat steps 3 through 5 for each additional file you'd like to add
- close the ZipOutputStream
- close the OutputStream
Let's have a look at steps 3 through 5, which need to be repeated for each file.
ZipEntry entry = new ZipEntry(file.getName());
entry.setSize(file.length());
entry.setTime(file.lastModified());
A new ZipEntry is created, the name, size and time of the zipped entity are set. Please note that the CRC32 value is not set at this moment. We'll see later on why this is.
zos.putNextEntry(entry);
fis = new FileInputStream(file);
The entry has now been added to a ZipOutputStream which was passed to this method as an argument. An InputStream is opened to read the contents of the file we would like to zip.
CRC32 crc32 = new CRC32();
while ((len = fis.read(data)) > -1)
{
zos.write(data, 0, len);
crc32.update(data, 0, len);
}
entry.setCrc(crc32.getValue());
We did not set the CRC32 value when we created the ZipEntry. Now we can make up for this: while we add the data to the ZipOutputStream, we calculate the CRC32 value. The benefit of this approach is that we only need to read the contents of the file once, whereas we would have had to read the file twice should we have wanted to do this up front.
zos.closeEntry();
After all this, we only need to close the ZipEntry we added to the ZipOutputStream. We are now ready to add another entry, or we can close the zip file at this point.
Perhaps a final note on the BUFFER_SIZE I used in this example. It is possible to use a smaller or larger buffer size in the example, but please note that setting a size that's too big or too small will hurt performance.
http://jcsnippets.atspace.com/java/input-output/create-zip-file.html
How do I create a zip file?(转)的更多相关文章
- How to create a zip file in NetSuite SuiteScript 2.0 如何在现有SuiteScript中创建和下载ZIP压缩文档
Background We all knows that: NetSuite filecabinet provided a feature to download a folder to a zip ...
- How do I create zip file in Servlet for download?
原文链接:https://kodejava.org/how-do-i-create-zip-file-in-servlet-for-download/ The example below is a s ...
- Java ZIP File Example---refernce
In this tutorial we are going to see how to ZIP a file in Java. ZIP is an archive file format that e ...
- zip file 压缩文件
有时候我们希望 upload 文件后自动压缩, 可以节省空间. 可以使用微软提供的压缩代码 Install-Package System.IO.Compression.ZipFile -Version ...
- ionic build Android错误记录 error in opening zip file
0.写在前头 运行 :cordova requirements Requirements check results for android: Java JDK: installed 1.8.0 An ...
- 记一个mvn奇怪错误: Archive for required library: 'D:/mvn/repos/junit/junit/3.8.1/junit-3.8.1.jar' in project 'xxx' cannot be read or is not a valid ZIP file
我的maven 项目有一个红色感叹号, 而且Problems 存在 errors : Description Resource Path Location Type Archive for requi ...
- 解决: org.iq80.leveldb.DBException: IO error: C:\data\trie\000945.sst: Could not create random access file.
以太坊MPT树的持久化层是采用了leveldb数据库,然而在抽取MPT树代码运行过程中,进行get和write操作时却发生了错误: Caused by: org.fusesource.leveldbj ...
- linux下解压大于4G文件提示error: Zip file too big错误的解决办法
error: Zip file too big (greater than 4294959102 bytes)错误解决办法.zip文件夹大于4GB,在centos下无法正常unzip,需要使用第三方工 ...
- maven install 读取jar包时出错;error in opening zip file
错误信息: [INFO] ------------------------------------------------------------------------ [ERROR] Failed ...
随机推荐
- 关于负数的isdigit()判断
-->the start 今天写作业的时候突然想到,一直使用isdigit()方法来处理用户的输入选择是不是数字,但是如果用户输入的是负数呢,会不会导致bug? 然后我就试了一下,居然不报错.. ...
- 关于php判断中文字符的问题
在网上找了好多例子,还是这个靠谱点: UTF-8匹配: 在javascript中,要判断字符串是中文是很简单的.比如: var str = "php编程"; if (/^[\u4e ...
- Android Studio安装教程
Google在2013 I/O大会上发布Android Studio之后,广大Android开发者欢欣鼓舞,不过很快就有人出现问题,Android Studio无法安装,或者安装后无法启动,这篇文章就 ...
- Ext的异步请求(二级级联动态加载下拉列表)
页面: <tr> <td class="label" width="300" >作业计划项模板</td> <td> ...
- asp.net 中将汉字转换成拼音
/// <summary> /// 获取汉字的全拼音 /// </summary> /// <param name="x">传汉字的字符串< ...
- 将表中null值替换成想要的值、查询某一列值为null
用到ISNULL()函数 例如:SELECT 其他列名,ISNULL(列名,替换值)as 重命名 from 表名 (简单参考:http://www.cnblogs.com/netsa/archive ...
- BZOJ 1179: [Apio2009]Atm( tarjan + 最短路 )
对于一个强连通分量, 一定是整个走或者不走, 所以tarjan缩点然后跑dijkstra. ------------------------------------------------------ ...
- js获取网页屏幕可见区域高度
document.body.clientWidth ==> BODY对象宽度 document.body.clientHeight ==> BODY对象高度 document.docume ...
- 终于懂了:Delphi消息的Result完全是生造出来的,不是Windows消息自带的(Delphi对Windows编程体系的改造越大,学习收获就越大)——消息是否继续传递就看这个Result
Windows中,消息使用统一的结构体(MSG)来存放信息,其中message表明消息的具体的类型, 而wParam,lParam是其最灵活的两个变量,为不同的消息类型时,存放数据的含义也不一样. t ...
- android怎样实现自动点击功能
一个按钮之类的控件的自动点击的话,可以定时调用 button.performClick();