Swiftly语言学习1

单纯值：

1.let常量声明，var声明变量（同时宣布福值，编译器会自己主动判断出类型）

var myVariable = 42

myVariable 50

let myConstant = 42

let implicitInteger = 70

let implicitDouble = 70.0

let explicitDouble:Double = 70

声明类型时在“量”后面加上“：”然后写上类型的名字。

（值永远不会隐式转换，须要转换请显示转换“类型（量）”）

更简单的办法将值转换成字符串：\（量）

let label = "The width is"

let width = 94

let widthLabel = label + string(width)

let apples = 3

let oranges = 5

let appleSummary = "I have \(apples) apples."

let fruitSummary = "I have \(apples + oranges) pieces of fruit"

2.“[]”创建数组和字典，key或者下标取值

var shoppingList = ["catfish","water","tulips","blue paint"]

shoppingList[1] = "bottle of water"

var occupations = ["Malcolm":"Captain","KayLee":"Mechanic"]

occupations["Jayne"] = "Public Relations"

空数组和空字典声明

let emptyArray  = String[]()

let emptyDictionary = Dictionary<String,Float>()

假设类型信息能够别判断出来。你能够用[]和[:]来创建空数组和空字典，就想你声明变量或者给函数传递參数的时候一样

shoppingList = []

控制流

1.if,switch进行条件操作。for-in,for,while,do-while进行循环（包裹条件和循环变量括号能够省略。可是语句体的大括号是必须的）

let individualScores = [75,43,103,87,12]

var teamScore = 0

for score in individualScores{

if score>50{

teamScore += 3

}

else

{

teamScore += 1

}

}

if语句的条件必须是布尔值，一个可选的值可能是一个详细的值或者是nil。表示值缺失。在类型后面加上一个问号来标记这个变量的值是可选的。

var optionalString : String? = "Hello"

optionalString == nil

var optionalName:String?="John Appleseed"

var greeting = "Hello!"

if let name = optionalName{

greeting = "Hello, \(name)"

}

switch支持随意类型的数据以及各种比較操作

let vegetable = "red pepper"

switch vegetable{

case "celery":

let vegetableComment = "Add some raisins and make ants on a log."

case "cucumber","watercress":

let vegetableComment = "That would make a good tea sandwich."

case let x where x.hasSuffix("pepper"):

let vegetableComment = "Is it a spicy\(x)?

"

default:

let vegetableComment = "Everything tastes good in soup."

}

使用for - in 来遍历字典。需呀两个变量来表示每一个键值对

let interestingNumbers = {

"Prime":[2,3,5,7,11,13],

"Fibonacci":[1,1,2,3,5,8],

"Square":[1,4,9,16,25],

]

var largest = 0

for(kind,numbers) in interestingNumbers{

for number in numbers{

if number > largest{

largest = number

}

}

}

largest

var n = 2

while n < 100{

n = n*2

}

var m = 2

do{

m = m*2

}while m < 100

var firstForLoop = 0

for i in 0...3{

firstForLoop += i

}

var secondForLoop = 0

for var i= 0;i < 3;++i{

secondForLoop += 1

}

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