剑指offer，双指针法，vector输出不完美

原因：由于在第一个res push_back给allRes的时候allRes的列已经确定，所以在输出的时候会输出一些多余的东西,在输出的时候不好处理

#include <iostream>
#include "algorithm"
#include "cmath"
#include "string"
#include <vector>
using namespace std;

int main()
{
        int sum=;

        vector<vector<int> > allRes;
        int phigh = ,plow = ;

        while(phigh > plow){
            int cur = (phigh + plow) * (phigh - plow + ) / ;
            if( cur < sum)
                phigh++;

            if(cur == sum){
                vector<int> res;
                for(int i = plow; i<=phigh; i++)
                    res.push_back(i);
                allRes.push_back(res);
                plow++;
                //vector<int>().swap(res);

    res.clear();
    }

            if(cur > sum)
                plow++;
        }
//        for( vector<vector<int> >::iterator it=allRes.begin();it!=allRes.end();it++){error cout
//            cout<<*it<<endl;
//        }
        for(int i=;i<allRes.size();i++){//right cout
        for(int j=;j<allRes[].size();j++){
            cout<<allRes[i][j]<<" ";
        }cout<<'\n';
    }
}

直接用二维数组进行替代，输出更好控制

#include <iostream>
#include "algorithm"
#include "cmath"
#include "string"
#include <vector>
using namespace std;

int main()
{
        int sum=;

        int allRes[][]={};
        int phigh = ,plow = ;
        int t=;
        while(phigh > plow){
            int cur = (phigh + plow) * (phigh - plow + ) / ;
            if( cur < sum)
                phigh++;

            if(cur == sum){
                for(int j=plow;j<=phigh;j++){
                allRes[t][j-plow]=j;
                }t++;
                plow++;
                //vector<int>().swap(res);

    //res.clear();
    }

            if(cur > sum)
                plow++;
        }
//        for( vector<vector<int> >::iterator it=allRes.begin();it!=allRes.end();it++){error cout
//            cout<<*it<<endl;
//        }
        int f=;
        for(int i=;i<;i++){//right cout
        if(f==) break;
        for(int j=;j<;j++){
            if(allRes[i][]==){
                f=;break;
            }
            if(allRes[i][j])
            cout<<allRes[i][j]<<" ";

        }cout<<'\n';
    }
}