poj 4438 Hunters
Hunters
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1588 Accepted Submission(s):
1194
no preys can escape from them. However, they both think that its hunting skill
is better than the other. So they need a match.
In their match, the targets
are two animals, a tiger and a wolf. They both know that the tiger is living in
the south of the forest and the wolf is living in the north of the forest. They
decide that the one who kills the tiger scores X points and who kills the wolf
scores Y points. If the one who kills both tiger and wolf scores X+Y
points.
Before the match starts, Alice is in the east of the forest and Bob
is in the west of the forest. When the match starts, Alice and Bob will choose
one of the preys as targets. Because they haven't known the other's choice,
maybe they choose the same target. There will be two situations:
(1) If they
choose different targets, they both are sure of killing their respective
targets.
(2) If they choose the same target, the probability of Alice killing
the target is P, and the probability of Bob killing it is 1-P. Then they will
hunt for the other prey, also the probability of Alice killing it is P and the
probability of Bob killing it is 1-P.
But Alice knows about Bob. She knows
that the probability of Bob choosing tiger as his first target is Q, and the
probability of choosing wolf is 1-Q. So that Alice can decide her first target
to make her expected score as high as possible.
(1≤T≤10000), the number of test cases.
Then T test cases follow. Each test
case contains X, Y, P, Q in one line. X and Y are integers and 1≤X,
Y≤1000000000. P and Q are decimals and 0≤P, Q≤1, and there are at most two
digits after decimal point.
choose and the highest expected score she can get, in one line, separated by a
space. The expected score should be rounded to the fourth digit after decimal
point. It is guaranteed that Alice will have different expected score between
choosing tiger and wolf.
2 1 0.5 0.5
2 1 0 1
7 7 0.32 0.16
wolf 1.0000
tiger 6.5968
#define _CRT_SECURE_NO_DEPRECATE
#include<iostream>
#include<algorithm>
#include<string>
#include<set>
#include<map>
#include<vector>
#include<queue>
using namespace std;
const int N_MAX = +;
double P, Q,X,Y;
int main() {
int T;
scanf("%d",&T);
while (T--) {
scanf("%lf%lf%lf%lf", &X, &Y, &P, &Q);
double ext_1 = ( - Q)*X + Q*(X*P + Y*P);
double ext_2 = Q*Y + ( - Q)*(Y*P + X*P);
if (ext_1 > ext_2) {
printf("tiger %.4lf\n", ext_1);
}
else
printf("wolf %.4lf\n",ext_2);
}
return ;
}
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