Java中List的排序和List的MAp

这里是一个类中类去实现条件优先排序的问题

package com.sun;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;

public class Demo {

	public Demo() {
		// TODO Auto-generated constructor stub
	}

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub

		int a= 0;
		Dob db  = new Dob();
		Dob db1  = new Dob();
		Dob db2  = new Dob();
		db.setName("sun");
		db.setAge(20);
		db.setSex(3);

		db1.setName("zhi");
		db1.setAge(22);
		db1.setSex(1);

		db2.setName("yan");
		db2.setAge(21);
		db2.setSex(2);
		List<Dob> as = new ArrayList<Dob>();
		System.out.println("as="+as.size());
		as.add(db);
		as.add(db1);
		as.add(db2);

		 Collections.sort(as, new Comparator<Dob>() {
//比较。如果年龄不同先比较年龄 ，相同就比较性别
	            public int compare(Dob arg0, Dob arg1) {
	            	int flg = arg0.getAge().compareTo(arg1.getAge());
	            	if(flg==0){
	            		 return arg0.getSex().compareTo(arg1.getSex());
	            	}else{
	            		 return arg0.getAge().compareTo(arg1.getAge());
	            	}

	            }

	        });

		for (Dob p : as) {
            System.out.println(p.getName());
            System.out.println(p.getAge());
        }

System.out.println("as="+as.size());

	}

}
	class Dob {
		public String  name;

		public Integer age;

		public Integer sex;

		public String getName() {
			return name;
		}
		public void setName(String name) {
			this.name = name;
		}
		public Integer getAge() {
			return age;
		}
		public void setAge(Integer age) {
			this.age = age;
		}
		public Integer getSex() {
			return sex;
		}
		public void setSex(Integer sex) {
			this.sex = sex;
		}

}

　　LIst中的MAp

 public void listSort(List<Map<String,Object>> resultList) throws Exception{
        // resultList是需要排序的list，其内放的是Map
        // 返回的结果集
        Collections.sort(resultList,new Comparator<Map<String,Object>>() {

         public int compare(Map<String, Object> o1,Map<String, Object> o2) {

          //o1，o2是list中的Map，可以在其内取得值，按其排序，此例为升序，s1和s2是排序字段值
             //String FileNumber = GetFileKeyNumber(fileInfo.getKey(),2,2);

             Map.Entry<String, Object>  fileInfo1 = null;
             Map.Entry<String, Object>  fileInfo2 = null;
             Integer s1 = 0;
             Integer s2 = 0;
             Iterator<Map.Entry<String, Object>> fileMap = o1.entrySet().iterator();
             while (fileMap.hasNext()) {
               fileInfo1 = fileMap.next();
               s1 = Integer.parseInt(GetFileKeyNumber(fileInfo1.getValue().toString(),2,2));
             }

             Iterator<Map.Entry<String, Object>> fileMap2 = o2.entrySet().iterator();
             while (fileMap2.hasNext()) {
               fileInfo2 = fileMap2.next();
               s2 = Integer.parseInt(GetFileKeyNumber(fileInfo2.getValue().toString(),2,2));
             }

          if(s1>s2) {
           return 1;
          }else {
           return -1;
          }
         }
        });

       }