GUID获取16位19位22位的唯一字符串

/// <summary>

/// 根据GUID获取16位的唯一字符串

/// </summary>

/// <param name=\"guid\"></param>

/// <returns></returns>

public static string GuidTo16String()

{

long i = 1;

foreach (byte b in Guid.NewGuid().ToByteArray())

i *= ((int)b + 1);

return string.Format("{0:x}", i - DateTime.Now.Ticks);

}

/// <summary>

/// 根据GUID获取19位的唯一数字序列

/// </summary>

/// <returns></returns>

public static long GuidToLongID()

{

byte[] buffer = Guid.NewGuid().ToByteArray();

return BitConverter.ToInt64(buffer, 0);

}

/// <summary>

/// 生成22位唯一的数字 并发可用

/// </summary>

/// <returns></returns>

public static string GenerateUniqueID()

{

System.Threading.Thread.Sleep(1); //保证yyyyMMddHHmmssffff唯一

Random d = new Random(BitConverter.ToInt32(Guid.NewGuid().ToByteArray(), 0));

string strUnique = DateTime.Now.ToString("yyyyMMddHHmmssffff") + d.Next(1000, 9999);

return strUnique;

}