Add Digits

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.

代码:

public class Solution {
    public int addDigits(int num) {
        return 1+(num-1)%9;
    }
}