67. Add Binary

Easy

Given two binary strings, return their sum (also a binary string).

The input strings are both non-empty and contains only characters 1 or 0.

Example 1:

Input: a = "11", b = "1"
Output: "100"

Example 2:

Input: a = "1010", b = "1011"
Output: "10101"
package leetcode.easy;

public class AddBinary {
@org.junit.Test
public void test() {
String a1 = "11";
String b1 = "1";
String a2 = "1010";
String b2 = "1011";
System.out.println(addBinary(a1, b1));
System.out.println(addBinary(a2, b2));
} public String addBinary(String a, String b) {
StringBuffer buffer = new StringBuffer();
int sum = 0;
int carry = 0;
for (int i = a.length() - 1, j = b.length() - 1; i >= 0 || j >= 0; i--, j--) {
sum = carry;
if (i >= 0) {
sum += a.charAt(i) - '0';
}
if (j >= 0) {
sum += b.charAt(j) - '0';
}
buffer.append(sum % 2);
carry = sum / 2;
}
if (carry != 0) {
buffer.append(carry);
}
return buffer.reverse().toString();
}
}

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