Identity Card

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2696    Accepted Submission(s): 1048

Problem Description
Do you own an ID card?You must have a identity card number in your family's Household Register. From the ID card you can get specific personal information of everyone. The number has 18 bits,the first 17 bits contain special specially meanings:the first 6 bits represent the region you come from,then comes the next 8 bits which stand for your birthday.What do other 4 bits represent?You can Baidu or Google it. Here is the codes which represent the region you are in.   However,in your card,maybe only 33 appears,0000 is replaced by other numbers. Here is Samuel's ID number 331004198910120036 can you tell where he is from?The first 2 numbers tell that he is from Zhengjiang Province,number 19891012 is his birthday date (yy/mm/dd).
 
Input
Input will contain 2 parts: A number n in the first line,n here means there is n test cases. For each of the test cases,there is a string of the ID card number.
 
Output
Based on the table output where he is from and when is his birthday. The format you can refer to the Sample Output.
 
Sample Input
1
330000198910120036
 
Sample Output
He/She is from Zhejiang,and his/her birthday is on 10,12,1989 based on the table.
 
Author
Samuel
 

水题:给你身份证号让你找信息;注意string不能用scanf输入。。。

代码:

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstring>
#include<cmath>
#include<queue>
#include<stack>
#include<vector>
#include<map>
#include<string>
using namespace std;
const int INF=0x3f3f3f3f;
const double PI=acos(-1.0);
#define mem(x,y) memset(x,y,sizeof(x))
#define SI(x) scanf("%d",&x)
#define SL(x) scanf("%lld",&x)
#define PI(x) printf("%d",x)
#define PL(x) printf("%lld",x)
#define P_ printf(" ")
#define T_T while(T--)
typedef long long LL;
map<string,string>mp;
int main(){
int T,y,m,d;
string s;
SI(T);
mp["33"]="Zhejiang";
mp["11"]="Beijing";
mp["71"]="Taiwan";
mp["81"]="Hong Kong";
mp["82"]="Macao";
mp["54"]="Tibet";
mp["21"]="Liaoning";
mp["31"]="Shanghai";
T_T{
//scanf("%s",s.c_str());
cin>>s;
printf("He/She is from %s,and his/her birthday is on %s,%s,%s based on the table.\n",mp[s.substr(0,2)].c_str(),s.substr(10,2).c_str(),s.substr(12,2).c_str(),s.substr(6,4).c_str());
//cout<<"He/She is from "<<mp[s.substr(0,2)]<<",and his/her birthday is on "<<s.substr(10,2)<<","<<s.substr(12,2)<<","<<s.substr(6,4)<<" based on the table."<<endl;
}
return 0;
}

  

Identity Card(水题)的更多相关文章

  1. hdu 2629 Identity Card (字符串解析模拟题)

    这题是一个字符串模拟水题,给12级学弟学妹们找找自信的,嘿嘿; 题目意思就是要你讲身份证的上的省份和生日解析出来输出就可以了: http://acm.hdu.edu.cn/showproblem.ph ...

  2. poj 1003:Hangover(水题,数学模拟)

    Hangover Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 99450   Accepted: 48213 Descri ...

  3. HDU 4772 Zhuge Liang's Password (2013杭州1003题,水题)

    Zhuge Liang's Password Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/O ...

  4. HDOJ 2317. Nasty Hacks 模拟水题

    Nasty Hacks Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Tota ...

  5. ACM :漫漫上学路 -DP -水题

    CSU 1772 漫漫上学路 Time Limit: 1000MS   Memory Limit: 131072KB   64bit IO Format: %lld & %llu Submit ...

  6. ytu 1050:写一个函数,使给定的一个二维数组(3×3)转置,即行列互换(水题)

    1050: 写一个函数,使给定的一个二维数组(3×3)转置,即行列互换 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 154  Solved: 112[ ...

  7. [poj2247] Humble Numbers (DP水题)

    DP 水题 Description A number whose only prime factors are 2,3,5 or 7 is called a humble number. The se ...

  8. gdutcode 1195: 相信我这是水题 GDUT中有个风云人物pigofzhou,是冰点奇迹队的主代码手,

    1195: 相信我这是水题 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 821  Solved: 219 Description GDUT中有个风云人 ...

  9. BZOJ 1303 CQOI2009 中位数图 水题

    1303: [CQOI2009]中位数图 Time Limit: 1 Sec  Memory Limit: 162 MBSubmit: 2340  Solved: 1464[Submit][Statu ...

随机推荐

  1. 鼠标经过图片时变换的两种方法--css+div及javascript应用

    javascript方式:    熟悉使用document.getElementById()取得节点对象 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTM ...

  2. 一个php创建webservice,并通过c#调用的真实实例

    最近需要用php创建webservice供C#和JAVA来调用,通过3天的搜索和尝试,终于成功在C#下调用,JAVA的调用还没开始,为防止忘记,在这里记录下来全过程. 本文参考了许多文章,文中也采用了 ...

  3. English words

    英语指路常用单词 the one-way street单行道traffic light红绿灯 fork road三叉路口intersection/crossroad 十字路口T road 丁字路口in ...

  4. 高精度 java的一些题

    poj 1001 Exponentiation import java.util.*; import java.math.*; public class Main { public static vo ...

  5. 製程能力介紹(SPC introduction) ─ Ck之製程能力解釋

    Ck之製程能力解釋 a=M-X: 代表規格中心(也就是製程之期望中心)與實際製造出來之群體中心的距離. b=T/2: 代表規格的一半. 所以,當Ck=a/b=M-X/(T/2)以文字來說明就是:實際作 ...

  6. Silverlight第三方控件专题

    原文http://www.cnblogs.com/nasa/archive/2008/12/01/1344927.html 这里我收集整理了目前网上silverlight第三方控件的专题,若果有所遗漏 ...

  7. Robot Framework作者建议如何选择自动化测试框架

    本文摘自:InfoQ中文站http://www.infoq.com/cn/news/2012/06/robot-author-suggest-autotest Robot Framework作者建议如 ...

  8. css样式实现字体删除线效果

    <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content ...

  9. 使用CSS3伸缩盒实现图片垂直居中

    用CSS实现图片垂直居中的方法有很多,针对移动端设备可以用CSS3伸缩盒来实现图片垂直居中. 代码如下: <div class="box"> <img src=& ...

  10. JavaScript之充实文档的内容

    1.我们在平时的开发中会碰到一些缩略语如:XML,HTML,API等专业术语:为了能使用户,更好的了解术语的意思,我们通常会给<abbr></abbr>标签加一个title属性 ...