Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.

Example:

Input: [-2,1,-3,4,-1,2,1,-5,4],
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.

Follow up:

If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.

/**
* @param {number[]} nums
* @return {number}
*/
var maxSubArray = function(nums) {
if (!nums.length) {
return null;
} let start = end = -1;
let crtDiff = maxDiff = Number.NEGATIVE_INFINITY; for (let i = 0; i < nums.length; i++) { crtDiff = Math.max(nums[i], crtDiff + nums[i])
maxDiff = Math.max(crtDiff, maxDiff);
} return maxDiff;
};

To locate the sub array:

var maxSubArray = function(nums) {
if (!nums.length) {
return null;
} let start = end = -1;
let crtDiff = maxDiff = Number.NEGATIVE_INFINITY; for (let i = 0; i < nums.length; i++) { crtDiff = Math.max(nums[i], crtDiff + nums[i])
maxDiff = Math.max(crtDiff, maxDiff);
if (crtDiff === maxDiff) {
if (nums[i] === crtDiff) {
start = end = i;
} if (maxDiff > nums[i] && start < 0) {
start = end = i;
} else if (maxDiff > nums[i] && start >= 0) {
end = i;
}
}
}
const sub = nums.slice(start, end + 1)
return maxDiff;
};
// [ 4, -1, 2, 1 ] sum 6

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