Codeforces Beta Round #42 (Div. 2)
Codeforces Beta Round #42 (Div. 2)
http://codeforces.com/contest/43
A
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define maxn 1000005
typedef long long ll;
typedef unsigned long long ull; string str;
map<string,int>mp; int main(){
#ifndef ONLINE_JUDGE
// freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
int n;
cin>>n;
for(int i=;i<=n;i++){
cin>>str;
mp[str]++;
}
string ans;
int Max=;
for(map<string,int>::iterator it=mp.begin();it!=mp.end();it++){
if(Max < it->second){
Max = it->second;
ans = it->first;
}
}
cout<<ans<<endl;
}
B
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define maxn 1000005
typedef long long ll;
typedef unsigned long long ull; string s1,s2;
map<char,int>mp; int main(){
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
getline(cin,s1);
getline(cin,s2);
for(int i=;i<s1.length();i++){
mp[s1[i]]++;
}
int flag=;
for(int i=;i<s2.length();i++){
if(s2[i]==' ') continue;
if(mp[s2[i]]){
mp[s2[i]]--;
}
else{
flag=;
}
}
if(!flag) cout<<"YES"<<endl;
else cout<<"NO"<<endl; }
C
cf的评测机是真的快。。。写了个n^2的假算法都过了。。。正解应该是:sum(num%3==0)/2+min(sum(num%3==1),sum(num%3==2))
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define maxn 1000005
typedef long long ll;
typedef unsigned long long ull; ll a[]; int book[]; bool Check(ll a,ll b){
ll tmpa=a;
ll tmpb=b;
while(tmpa){
tmpb=tmpb*+tmpa%;
tmpa/=;
}
if(tmpb%==) return true;
tmpa=a;
tmpb=b;
while(tmpb){
tmpa=tmpa*+tmpb%;
tmpb/=;
}
if(tmpa%==) return true;
return false;
} int main(){
#ifndef ONLINE_JUDGE
// freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
int n;
cin>>n;
for(int i=;i<=n;i++) cin>>a[i];
int ans=;
for(int i=;i<=n;i++){
if(!book[i]){
for(int j=i+;j<=n;j++){
if(!book[j])
if(Check(a[i],a[j])){
ans++;
book[j]=;
break;
}
}
}
}
cout<<ans<<endl; }
D
模拟
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define maxn 1000005
typedef long long ll;
typedef unsigned long long ull; int main(){
#ifndef ONLINE_JUDGE
// freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
int n,m,i,j;
scanf("%d%d",&n,&m);
if((n%==&&m%==)||(n==&&m>)||(m==&&n>)){
printf("1\n%d %d 1 1\n",n,m);
for(i=;i<=n;i++){
if(i%==)
for(j=;j<=m;j++)printf("%d %d\n",i,j);
else
for(j=m;j>;j--)printf("%d %d\n",i,j);
}
printf("1 1\n");
}
else if(n%==){
printf("0\n1 1\n");
for(i=;i<=n;i++){
if(i%==)
for(j=;j<=m;j++)printf("%d %d\n",i,j);
else
for(j=m;j>;j--)printf("%d %d\n",i,j);
}
for(i=n;i>;i--)printf("%d 1\n",i);
}
else{
printf("0\n1 1\n");
for(i=;i<=m;i++){
if(i%==)
for(j=;j<=n;j++)printf("%d %d\n",j,i);
else
for(j=n;j>;j--)printf("%d %d\n",j,i);
}
for(i=m;i>;i--)printf("1 %d\n",i);
} }
E
模拟
#include<bits/stdc++.h>
using namespace std;
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define sqr(x) ((x)*(x))
#define pb push_back
#define maxn 1000005
typedef long long ll;
typedef unsigned long long ull; int n,s,t[][],k[],v[][],ans; int main(){
#ifndef ONLINE_JUDGE
// freopen("input.txt","r",stdin);
#endif
std::ios::sync_with_stdio(false);
scanf("%d%d",&n,&s);
for (int i=;i<=n;i++){
scanf("%d",&k[i]);
for (int j=;j<=k[i];j++){
scanf("%d%d",&v[i][j],&t[i][j]);
t[i][j]+=t[i][j-];
t[i][k[i]+]=<<;
}
}
for (int i=;i<n;i++)
for (int j=i+;j<=n;j++){
int t1=,t2=,x1=,x2=,tmp=,tmp2=-;
while (t1<=k[i] || t2<=k[j]){
int tmp1=min(t[i][t1],t[j][t2]);
x1+=(tmp1-tmp)*v[i][t1];
x2+=(tmp1-tmp)*v[j][t2];
if (t[i][t1]<t[j][t2]) t1++;else t2++;
if (x1>x2 && tmp2==) ans++;
if (x1<x2 && tmp2==) ans++;
if (x1>x2) tmp2=;
if (x1<x2) tmp2=;
tmp=tmp1;
}
}
printf("%d\n",ans);
}
Codeforces Beta Round #42 (Div. 2)的更多相关文章
- Codeforces Beta Round #80 (Div. 2 Only)【ABCD】
Codeforces Beta Round #80 (Div. 2 Only) A Blackjack1 题意 一共52张扑克,A代表1或者11,2-10表示自己的数字,其他都表示10 现在你已经有一 ...
- Codeforces Beta Round #83 (Div. 1 Only)题解【ABCD】
Codeforces Beta Round #83 (Div. 1 Only) A. Dorm Water Supply 题意 给你一个n点m边的图,保证每个点的入度和出度最多为1 如果这个点入度为0 ...
- Codeforces Beta Round #79 (Div. 2 Only)
Codeforces Beta Round #79 (Div. 2 Only) http://codeforces.com/contest/102 A #include<bits/stdc++. ...
- Codeforces Beta Round #77 (Div. 2 Only)
Codeforces Beta Round #77 (Div. 2 Only) http://codeforces.com/contest/96 A #include<bits/stdc++.h ...
- Codeforces Beta Round #76 (Div. 2 Only)
Codeforces Beta Round #76 (Div. 2 Only) http://codeforces.com/contest/94 A #include<bits/stdc++.h ...
- Codeforces Beta Round #75 (Div. 2 Only)
Codeforces Beta Round #75 (Div. 2 Only) http://codeforces.com/contest/92 A #include<iostream> ...
- Codeforces Beta Round #74 (Div. 2 Only)
Codeforces Beta Round #74 (Div. 2 Only) http://codeforces.com/contest/90 A #include<iostream> ...
- Codeforces Beta Round #73 (Div. 2 Only)
Codeforces Beta Round #73 (Div. 2 Only) http://codeforces.com/contest/88 A 模拟 #include<bits/stdc+ ...
- Codeforces Beta Round #72 (Div. 2 Only)
Codeforces Beta Round #72 (Div. 2 Only) http://codeforces.com/contest/84 A #include<bits/stdc++.h ...
随机推荐
- Vue.js Failed to resolve filter: key
转自:https://stackoverflow.com/questions/35835214/vue-js-failed-to-resolve-filter-key I am following t ...
- 深度学习原理与框架-RNN网络架构-RNN网络 1.RNN的前向传播 2.RNN的反向传播
对于神经网络而言,每一个样本的输入与输入直接都是独立的,即预测的结果之间并没有联系 而对于RNN而言:不仅仅是有当前的输入,而且上一层的隐藏层也将进行输入,用于进行结果的预测.因此每一个输入都与之前的 ...
- FB4.6项目迁移到4.7时 embed报错问题
问题: 从FB4.6或更早版本移植到4.7的项目Embed标签,比如 [Embed(source="assets/BtnPlay.png")] ,会报错 解决 方案: 4.7E ...
- rtmp推流开源代码备注一下
https://github.com/runner365/AnyRTC-RTMP https://github.com/runner365
- Leetcode 题解 reverse List II
这个题确实太容易错了. 我已经做了2遍了,之前都是套用reverse List 1中的函数. 现在尝试用新方法,在一个函数里完成,结果又错了. 事实证明,永远不要想当然!!!白板编程真的是要求,你对每 ...
- 高并发架构技术|缓存失效、缓存穿透问题 PHP 代码解决
问题描述 缓存失效: 引起这个原因的主要因素是高并发下,我们一般设定一个缓存的过期时间时,可能有一些会设置5分钟啊,10分钟这些:并发很高时可能会出在某一个时间同时生成了很多的缓存,并且过期时间在同一 ...
- 正则表达式(Python)
课题 使用正则表达式匹配字符串 使用正则表达式 "\d{3}-(\d{4})-\d{2}" 匹配字符串 "123-4567-89" 返回匹配结果:'" ...
- angularjs 与 UEditor开发,添加directive,保证加载顺序正常
'use strict'; angular.module('app.core').directive('ueditor', [function () { return { restrict: 'A', ...
- 吴裕雄 oracle 函数、触发器和包编程
- SAP 000 客户端初始登录
Solution 在SAP系统DB中删除账号SAP*,SAP系统会自动创建SAP*这个账号,然后初始密码是“PASS”,这样就获得Client 000 SAP*账号. Step by Step 以Or ...