http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=2497

题意:给出顶点数,边数及节点s,判断s是否包含在所有的环中;

思路:并查集的应用,在除s节点以外的节点中,取出有公共源点的节点放到一个集合中,若还能形成环说明s不能经过所有的环,否则s能经过所有的环;

 #include<stdio.h>
#include<string.h> int set[],n,m,s; int find(int x)
{
if(set[x] != x)
set[x] = find(set[x]);
return set[x];
} int main()
{
int u,v;
while(~scanf("%d %d %d",&n,&m,&s))
{
int flag = ;
for(int i = ; i <= n; i++)
set[i] = i; for(int i = ; i <= m; i++)
{
scanf("%d %d",&u,&v);
if(u != s && v != s)
{
int tu = find(u);
int tv = find(v);
if(tu == tv)
flag = ;
set[tu] = tv;
}
}
if(flag == )
printf("YES\n");
else printf("NO\n");
}
return ;
}

A Simple problem的更多相关文章

  1. POJ 3468 A Simple Problem with Integers(线段树 成段增减+区间求和)

    A Simple Problem with Integers [题目链接]A Simple Problem with Integers [题目类型]线段树 成段增减+区间求和 &题解: 线段树 ...

  2. POJ 3468 A Simple Problem with Integers(线段树/区间更新)

    题目链接: 传送门 A Simple Problem with Integers Time Limit: 5000MS     Memory Limit: 131072K Description Yo ...

  3. poj 3468:A Simple Problem with Integers(线段树,区间修改求和)

    A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 58269   ...

  4. ACM: A Simple Problem with Integers 解题报告-线段树

    A Simple Problem with Integers Time Limit:5000MS Memory Limit:131072KB 64bit IO Format:%lld & %l ...

  5. poj3468 A Simple Problem with Integers (线段树区间最大值)

    A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 92127   ...

  6. POJ3648 A Simple Problem with Integers(线段树之成段更新。入门题)

    A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 53169 Acc ...

  7. BZOJ-3212 Pku3468 A Simple Problem with Integers 裸线段树区间维护查询

    3212: Pku3468 A Simple Problem with Integers Time Limit: 1 Sec Memory Limit: 128 MB Submit: 1278 Sol ...

  8. POJ 3468 A Simple Problem with Integers(线段树区间更新区间查询)

    A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 92632   ...

  9. A Simple Problem with Integers(树状数组HDU4267)

    A Simple Problem with Integers Time Limit: 5000/1500 MS (Java/Others) Memory Limit: 32768/32768 K (J ...

  10. A Simple Problem with Integers

    A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 77964 Acc ...

随机推荐

  1. Android read-only file system解决方法

    adb shell su - mount -o rw,remount /system

  2. Driving the Activity Lifecycle

    Before Robolectric 2.2, most tests created Activities by calling constructors directly, (new MyActiv ...

  3. magic_quotes_gpc、mysql_real_escape_string、addslashes的区别及用法

    本篇文章,主要先重点说明magic_quotes_gpc.mysql_real_escape_string.addslashes 三个函数方法的含义.用法,并举例说明.然后阐述下三者间的区别.关系.一 ...

  4. Spring中的创建与销毁

    在bean中添加属性init-method="方法名" destroy-method="方法名" init-method        该方法是由spring容 ...

  5. opencv 常用函数介绍

    ××××××××××××××××××××××××××××××××××××××× CvScalar imgmean,imgstd; double imgmax,imgmin; cvAvgSdv(img, ...

  6. 关于ASP.NET Session State Server

    最近公司开发的一个网站因为访问量增大,需要添加多台Web Server来进行负载均衡. 但是在做负载均衡前需要将一些原来固定存储在单台机器上的东西分离出来,使之能单独存在在一个独立的机器上,其中就有S ...

  7. Linux下安装SVN服务(CentOS7下)

    1. 安装 centos(我这里使用的是CentOS7)下yum命令即可方便的完成安装 测试安装是否成功: 2. 建立版本库 创建svn数据目录(subversion默认是把/var/svn作为数据根 ...

  8. CentOS 6.5 IP 设置

    DEVICE=eth0TYPE=EthernetUUID=7d6d54e0-054d-472b-8cc1-080f16ef36c1ONBOOT=yesNM_CONTROLLED=yesBOOTPROT ...

  9. PHP 关于MongoDB的操作

    <?php header("Content-type:text/html;charset=utf-8"); $m = new MongoClient(); // 连接 $db ...

  10. CSS实现DIV三角形

    本文内容收集来自网络 #triangle-up { width:; height:; border-left: 50px solid transparent; border-right: 50px s ...