RepeatedDNASequences BestTime_to_Buy_and_SellStockIV

/**
 * @Author: weblee
 * @Email: likaiweb@163.com
 * @Blog: http://www.cnblogs.com/lkzf/
 * @Time: 2015年2月18日上午10:03:42
 *
 *************        function description ***************
 *
 ****************************************************
 */

public class BestTime_to_Buy_and_SellStockIV {
    public int maxProfit(int k, int[] prices) {
    if (prices.length == 0) {
        return 0;
    }

    if (k >= prices.length) {
        return solveMaxProfit(prices);
    }

    /*
     * 局部最优值是比较前一天并少交易一次的全局最优加上大于0的差值，
     * 和前一天的局部最优加上差值后相比，两者之中取较大值，
     * 而全局最优比较局部最优和前一天的全局最优
     */
    int[] global = new int[k + 1];
    int[] local = new int[k + 1];

    for (int i = 0; i < prices.length - 1; ++i) {
        int diff = prices[i + 1] - prices[i];

        for (int j = k; j >= 1; --j) {
        local[j] = Math.max(global[j - 1] + Math.max(diff, 0), local[j]
            + diff);

        global[j] = Math.max(global[j], local[j]);
        }
    }

    return global[k];
    }

    public static int solveMaxProfit(int[] prices) {
    int result = 0;

    for (int i = 1; i < prices.length; i++) {
        if (prices[i] - prices[i - 1] > 0) {
        result += (prices[i] - prices[i - 1]);
        }
    }

    return result;
    }

}

package com.weblee.Medium;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
import java.util.Map;

/**
 * @Author: weblee
 * @Email: likaiweb@163.com
 * @Blog: http://www.cnblogs.com/lkzf/
 * @Time: 2015年2月18日上午9:20:12
 *
 *************        function description ***************
 *
 ****************************************************
 */

public class RepeatedDNASequences {
    public List<String> findRepeatedDnaSequences(String s) {
    Map<Integer, Integer> map = new HashMap<Integer, Integer>();
    List<String> result = new ArrayList<String>();

    if (s.length() <= 10) {
        return result;
    }

    // encode
    char[] convert = new char[26];
    convert[0] = 0;
    convert[2] = 1;
    convert[6] = 2;
    convert[19] = 3;

    int hashValue = 0;

    /*
     * the first 10 characters string
     */
    for (int pos = 0; pos < 10; ++pos) {
        hashValue <<= 2;
        hashValue |= convert[s.charAt(pos) - 'A'];
    }

    // first 10-letter-long sequences encode -> value
    map.put(hashValue, 1);

    // remove duplicate
    HashSet<Integer> set = new HashSet<>();

    for (int pos = 10; pos < s.length(); ++pos) {
        // left 2 bit, equal to multiply 4
        hashValue <<= 2;
        // the 2 right bit valued encode of s.char(pos)
        hashValue |= convert[s.charAt(pos) - 'A'];
        // 最高两位置0
        hashValue &= ~(0x300000);

        if (!map.containsKey(hashValue)) {
        map.put(hashValue, 1);
        } else {
        if (!set.contains(hashValue)) {
            // 10-letter-long sequences
            result.add(s.substring(pos - 9, pos + 1));

            set.add(hashValue);
        }

        map.replace(hashValue, 1 + map.get(hashValue));
        }
    }

    return result;
    }

}