Codeforces - 1191B - Tokitsukaze and Mahjong - 模拟

https://codeforces.com/contest/1191/problem/B

小心坎张听的情况。

#include<bits/stdc++.h>
using namespace std;

string s[3];
int main() {
#ifdef Yinku
    freopen("Yinku.in", "r", stdin);
    //freopen("Yinku.out", "w", stdout);
#endif // Yinku
    while(cin >> s[0] >> s[1] >> s[2]) {
        if(s[0] == s[1] && s[1] == s[2]) {
            //刻子
            puts("0");
        } else if(s[0] == s[1] || s[0] == s[2] || s[1] == s[2]) {
            puts("1");
        } else {
            //顺子
            int cntm = 0, cntp = 0, cnts = 0;
            for(int i = 0; i < 3; i++) {
                if(s[i][1] == 'm')
                    cntm++;
                else if(s[i][1] == 'p')
                    cntp++;
                else
                    cnts++;
            }
            if(cntm == 3 || cntp == 3 || cnts == 3) {
                sort(s, s + 3);
                int lx = 0;
                if(abs(s[0][0] - s[1][0]) == 1)
                    lx++;
                if(abs(s[1][0] - s[2][0]) == 1)
                    lx++;
                if(lx)
                    printf("%d\n", 2 - lx);
                else {
                    if(abs(s[0][0] - s[1][0]) == 2)
                        lx++;
                    if(abs(s[1][0] - s[2][0]) == 2)
                        lx++;
                    puts(lx ? "1" : "2");
                }
            } else if(cntm == 1 && cntp == 1 && cnts == 1) {
                puts("2");
            } else  {
                char c = 'm';
                if(cntp == 2)
                    c = 'p';
                else if(cnts == 2)
                    c = 's';
                vector<string> vs;
                for(int i = 0; i < 3; i++) {
                    if(s[i][1] == c)
                        vs.push_back(s[i]);
                }
                if(abs(vs[0][0] - vs[1][0]) <= 2) {
                    puts("1");
                } else {
                    puts("2");
                }
            }
        }
    }
}