Python小代码_5_二维矩阵转置

使用列表推导式实现二维矩阵转置

matrix = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
print(matrix)
matrix_t = [[row[col] for row in matrix] for col in range(len(matrix[0]))]
print(matrix_t)

#输出结果
#[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
#[[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]

使用内置函数 zip() 秩代、map() 和 list() 映射实现二维矩阵转置

matrix = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
print(matrix)
matrix_t = list(map(list, zip(* matrix)))
print(matrix_t)

#输出结果
#[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
#[[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]