479. Second Max of Array【easy】

Find the second max number in a given array.

Notice

You can assume the array contains at least two numbers.

 

Example

Given [1, 3, 2, 4], return 3.

Given [1, 2], return 1.

解法一：

 public class Solution {
     /**
      * @param nums: An integer array.
      * @return: The second max number in the array.
      */
     public int secondMax(int[] nums) {
         int first = Math.max(nums[0], nums[1]);
         int second = Math.min(nums[0], nums[1]);  

         for (int i = 2; i < nums.length; i++) {
             if (nums[i] > first) {
                 second = first;
                 first = nums[i];
             } else if (nums[i] > second) {
                 second = nums[i];
             }
         }
         return second;
     }
 } 

从数组前两位找到first大和second大的，从i=2开始遍历，不断找当前first大和second大。