LeetCode: Integer to Roman 解题报告
Integer to Roman
Given an integer, convert it to a roman numeral.
Input is guaranteed to be within the range from 1 to 3999.

SOLUTION 1:
从大到小的贪心写法。从大到小匹配,尽量多地匹配当前的字符。
罗马数字对照表:
http://literacy.kent.edu/Minigrants/Cinci/romanchart.htm
package Algorithms.string;
public class IntToRoman {
public String intToRoman(int num) {
int nums[] = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
String[] romans = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
StringBuilder sb = new StringBuilder();
int i = 0;
// 使用贪心法。尽量拆分数字
while (i < nums.length) {
if (num >= nums[i]) {
sb.append(romans[i]);
num -= nums[i];
} else {
i++;
}
}
return sb.toString();
}
}
2015.1.12 redo:
public String intToRoman(int num) {
int[] nums = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
/*
1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1
"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X" IX V, IV, I
*/
String[] strs = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
int i = 0;
StringBuilder sb = new StringBuilder();
// greedy.
while (i < nums.length) {
// bug 1: should use ">="
if (num >= nums[i]) {
sb.append(strs[i]);
// bug 2: should remember to reduce the nums[i].
num -= nums[i];
} else {
i++;
}
}
return sb.toString();
}
请至主页君GITHUB:
https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/string/IntToRoman.java
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