Educational Codeforces Round 12 C. Simple Strings 贪心
C. Simple Strings
题目连接:
http://www.codeforces.com/contest/665/problem/C
Description
zscoder loves simple strings! A string t is called simple if every pair of adjacent characters are distinct. For example ab, aba, zscoder are simple whereas aa, add are not simple.
zscoder is given a string s. He wants to change a minimum number of characters so that the string s becomes simple. Help him with this task!
Input
The only line contains the string s (1 ≤ |s| ≤ 2·105) — the string given to zscoder. The string s consists of only lowercase English letters.
Output
Print the simple string s' — the string s after the minimal number of changes. If there are multiple solutions, you may output any of them.
Note that the string s' should also consist of only lowercase English letters.
Sample Input
aab
Sample Output
bab
Hint
题意
现在给你一个串,让你使得相邻的字符都不一样,要求修改的字符最少
问你最后的字符串长什么样
题解:
贪心,如果这个位置一样,那就变化就好了~
代码
#include<bits/stdc++.h>
using namespace std;
string s;
int main()
{
cin>>s;
s+='a';
for(int i=1;i<s.size()-1;i++)
{
if(s[i]==s[i-1])
{
for(int j=0;j<26;j++)
{
if(j+'a'==s[i-1]||(j+'a')==s[i+1])
continue;
s[i]=char(j+'a');
break;
}
}
}
for(int i=0;i<s.size()-1;i++)cout<<s[i];
cout<<endl;
}
Educational Codeforces Round 12 C. Simple Strings 贪心的更多相关文章
- Educational Codeforces Round 12 D. Simple Subset 最大团
D. Simple Subset 题目连接: http://www.codeforces.com/contest/665/problem/D Description A tuple of positi ...
- Educational Codeforces Round 12 B C题、
B. Shopping 题意:n个顾客,每个顾客要买m个物品,商场总共有k个物品,看hint就只知道pos(x)怎么算了,对于每一个Aij在k个物品中找到Aij的位置.然后加上这个位置对于的数值,然后 ...
- Codeforces Educational Codeforces Round 3 C. Load Balancing 贪心
C. Load Balancing 题目连接: http://www.codeforces.com/contest/609/problem/C Description In the school co ...
- Educational Codeforces Round 2 C. Make Palindrome 贪心
C. Make Palindrome Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/600/pr ...
- Educational Codeforces Round 12 F. Four Divisors 求小于x的素数个数(待解决)
F. Four Divisors 题目连接: http://www.codeforces.com/contest/665/problem/F Description If an integer a i ...
- Educational Codeforces Round 2 C. Make Palindrome —— 贪心 + 回文串
题目链接:http://codeforces.com/contest/600/problem/C C. Make Palindrome time limit per test 2 seconds me ...
- Educational Codeforces Round 12 E. Beautiful Subarrays 预处理+二叉树优化
链接:http://codeforces.com/contest/665/problem/E 题意:求规模为1e6数组中,连续子串xor值大于等于k值的子串数: 思路:xor为和模2的性质,所以先预处 ...
- Educational Codeforces Round 17 C. Two strings 打表二分
C. Two strings time limit per test 2 seconds memory limit per test 256 megabytes input standard inpu ...
- Educational Codeforces Round 12 E. Beautiful Subarrays 字典树
E. Beautiful Subarrays 题目连接: http://www.codeforces.com/contest/665/problem/E Description One day, ZS ...
随机推荐
- OkHttp与Cookie及Cookie的持久化
http://blog.csdn.net/u011150924/article/details/52780931 http://blog.csdn.net/chen19960724/article/d ...
- scandir函数的研究【笔记】
以下是本人的学习笔记,代码并非原创,均摘自官方源码,贴出来仅供学习记录用 scandir 的使用要注意内存泄漏的问题 scandir函数实现: vi ./uClibc-0.9.33.2/libc/mi ...
- linux 进程优先级 之设置实时进程 (另一种方式是设置nice值)【转】
转自:https://www.cnblogs.com/jkred369/p/6731353.html Linux内核的三种调度策略: 1,SCHED_OTHER 分时调度策略, 2,SCHED_FIF ...
- shell读取文件的每一行内容并输出【转】
写法一: #!/bin/bash while read line do echo $line done < file(待读取的文件) 写法二: #!/bin/bash cat file(待读取的 ...
- java实现ftp文件上传下载,解决慢,中文乱码,多个文件下载等问题
//文件上传 public static boolean uploadToFTP(String url,int port,String username,String password,String ...
- [ python ] 练习作业 - 3
1. 写出Python查找一个变量的顺序 提示:4中作用域的顺序 本地作用域(local) --> 当前作用域被嵌入的本地作用域(enclsing locals) --> 全局/模块作用域 ...
- java并发编程实战笔记---(第五章)基础构建模块
. 5.1同步容器类 1.同步容器类的问题 复合操作,加容器内置锁 2.迭代器与concurrentModificationException 迭代容器用iterator, 迭代过程中,如果有其他线程 ...
- 搜索关键词智能提示suggestion
转载自:stormbjm的专栏 题目详情:百度搜索框中,输入“北京”,搜索框下面会以北京为前缀,展示“北京爱情故事”.“北京公交”.“北京医院”等等搜索词,输入“结构之”,会提示“结构之法”,“结构之 ...
- Jmeter组件和属性(二)
Jmeter脚本开发原则 简单.正确.高效.简单:去除无关的组件,同时能复用的尽量复用.正确:对脚本或者业务正确性进行必要的判断,不能少也不能多.(200),业务错误的情况下,也可能返回200,必须用 ...
- es6js promise在ie中报错“未定义”
解决办法,我使用https://cdn.bootcss.com/es6-promise/4.1.1/es6-promise.auto.min.js直接引入在html中,也可以安装相应的babel-po ...