CodeForces760A

A. Petr and a calendar

time limit per test:2 seconds

memory limit per test:256 megabytes

input:standard input

output:standard output

Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

input

1 7

output

6

input

1 1

output

5

input

11 6

output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.

 //2017.01.31
 #include <iostream>
 #include <cstdio>
 #include <cstring>

 using namespace std;

 int mouth[] = {, , , , , , , , , , , , };

 int main()
 {
     int m, d;
     while(cin>>m>>d)
     {
         int ans = (mouth[m]-(-d+)-)/++;
         cout<<ans<<endl;
     }

     return ;
 }