A. Comparing Two Long Integers

题目连接:

http://www.codeforces.com/contest/616/problem/A

Description

You are given two very long integers a, b (leading zeroes are allowed). You should check what number a or b is greater or determine that they are equal.

The input size is very large so don't use the reading of symbols one by one. Instead of that use the reading of a whole line or token.

As input/output can reach huge size it is recommended to use fast input/output methods: for example, prefer to use scanf/printf instead of cin/cout in C++, prefer to use BufferedReader/PrintWriter instead of Scanner/System.out in Java. Don't use the function input() in Python2 instead of it use the function raw_input().

Input

The first line contains a non-negative integer a.

The second line contains a non-negative integer b.

The numbers a, b may contain leading zeroes. Each of them contains no more than 106 digits.

Output

Print the symbol "<" if a < b and the symbol ">" if a > b. If the numbers are equal print the symbol "=".

Sample Input

9

10

Sample Output

<

Hint

题意

给你两个带前导0的高精度数字,然后让你比大小。

题解:

模拟一下就好了,首先看数位,然后再看每一位的数字就行了

代码

#include<bits/stdc++.h>
using namespace std; string a,b;
int main()
{
cin>>a>>b;
int len1 = a.size(),len2 = b.size();
int la = 0,lb = 0;
while(a[la]=='0'&&la<len1)la++;
while(b[lb]=='0'&&lb<len2)lb++;
if(len1-la>len2-lb)return puts(">");
if(len1-la<len2-lb)return puts("<");
for(int i=la;i<len1;i++)
{
if(a[i]>b[i-la+lb])return puts(">");
if(a[i]<b[i-la+lb])return puts("<");
}
return puts("=");
}

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