Java [Leetcode 189]Rotate Array
题目描述:
Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7]
is rotated to [5,6,7,1,2,3,4]
.
Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
解题思路:
牺牲空间复杂度的话可以考虑开辟新的数组空间,然后依次移动即可;
本方法只用一个临时变量存放临时数据,然后依次的交换数据,如图所示:
但是注意会陷入局部循环的局面,这时将相应的下标后移一位。
public class Solution {
public void rotate(int[] nums, int k) {
int length = nums.length;
if(length == 0)
return;
k = k % length;
int head = 0, curIndex = 0, nextIndex;
int curValue = nums[0], nextValue;
for(int i = 0; i < length; i++){
if(curIndex == head && i > 0){ //finish a circle,move to another circle
curIndex++;
head++;
curValue = nums[curIndex];
}
nextIndex = (curIndex + k) % length;
nextValue = nums[nextIndex];
nums[nextIndex] = curValue;
curIndex = nextIndex;
curValue = nextValue;
}
}
}
代码如下:
Java [Leetcode 189]Rotate Array的更多相关文章
- Java for LeetCode 189 Rotate Array
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array ...
- LeetCode 189. Rotate Array (旋转数组)
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array ...
- [LeetCode] 189. Rotate Array 旋转数组
Given an array, rotate the array to the right by k steps, where k is non-negative. Example 1: Input: ...
- C#解leetcode 189. Rotate Array
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array ...
- Leetcode 189 Rotate Array stl
题意:将数组旋转k次,如将数组[1,2,3,4,5]旋转1次得到[2,3,4,5,1],将数组[1,2,3,4,5]旋转2次得到[3,4,5,1,2]..... 本质是将数组分成两部分a1,a2,.. ...
- 189. Rotate Array - LeetCode
Question 189. Rotate Array Solution 题目大意:数组中最后一个元素移到第一个,称动k次 思路:用笨方法,再复制一个数组 Java实现: public void rot ...
- <LeetCode OJ> 189. Rotate Array
189. Rotate Array Total Accepted: 55073 Total Submissions: 278176 Difficulty: Easy Rotate an array o ...
- 189. Rotate Array【easy】
189. Rotate Array[easy] Rotate an array of n elements to the right by k steps. For example, with n = ...
- 【LeetCode】Rotate Array
Rotate Array Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = ...
随机推荐
- 【BZOJ】【3196】Tyvj 1730 二逼平衡树
树套树 Orz zyf 学(co)习(py)了一下树套树的写法,嗯……就是线段树套平衡树. 具体实现思路就是:外部查询用的都是线段树,查询内部自己调用平衡树的操作. 抄抄代码有助理解= = 八中挂了… ...
- C#文件对话框,一次多选文件设置
OpenFileDialog ofd = new OpenFileDialog();ofd.Multiselect = true;if (ofd.ShowDialog() == DialogResul ...
- Roy Li的学习和成长自传
我不知道自己是什么时候从哪里来到这个世界上的,也许是石头里蹦出来的,也许是女娲捏出来的,上帝造出来的.上溯到我记忆的最前端,抱着我的好象 是一个女人,穿着白衣服,白得象石灰一样的那种.以至于后来我被告 ...
- 如何解决VS启动越来越慢
VS2013 用久后,现在启动和打开项目变得很慢 解决方案: A.清理缓存 VS2010清理缓存:启用vs2010命令行工具:在vs2010命令提示符下,执行devenv.exe /resetuser ...
- httpClient 入门实例
import java.io.File; import java.io.FileInputStream; import java.io.IOException; import java.io.Unsu ...
- 果盟广告SDK
// // GuomobWallView.h // GuoMobWallSample // // Created by keyrun on 14-1-21. // Copyright (c) 2014 ...
- Test a ; vs Test a( ) ;
一. Test a(); Test a; //前提声明了Test类 前者声明一个返回值为Test,名为a的函数,后者声明了Test类的一个对象(把Test当成int) struct Test{ ...
- HDU4670 Cube number on a tree 树分治
人生的第一道树分治,要是早点学我南京赛就不用那么挫了,树分治的思路其实很简单,就是对子树找到一个重心(Centroid),实现重心分解,然后递归的解决分开后的树的子问题,关键是合并,当要合并跨过重心的 ...
- utmp, wtmp, and lastlog 日志清除工具
utmp, wtmp, and lastlog 日志清除工具 http://blog.itpub.net/83980/viewspace-801664/
- Spring 3.0: Unable to locate Spring NamespaceHandler for XML schema namespace
被这个问题折磨着很久:参考: http://have23.iteye.com/blog/1340777 (cfx 与 spring 整合的时候出现的问题: org.springframework.be ...