C++红旗之更短形式：500多字符且无法遵守原题规则

Purpose and Scope

研究五星红旗C++代码生成问题的代码压缩方法。

没有最短,仅仅有更短.

已经尽力了。爱因斯坦的三个小板凳里，我这是第四个。

继续深入压缩代码的方法肯定非常诡异了。

Algorithms and Experiments

參考了: 基于Mathematica下的办法,原始的：

list=Table[#,{x,1,6,.2}]&@Manipulate[With[{p=Rest@pts,pt=First@pts},Graphics[{If[testpoint[p,pt],Cyan,Red],Polygon@p},PlotRange->2{{15,80},{-1,90}},ImageSize->{400,375},PlotLabel->Text[Style[If[testpoint[p,pt],"在当中","已出局"],FontFamily->"Arial",If[testpoint[p,pt],Red,Blue],30]]]],{ {pts,{3x{10,10},(*{-2,1/2},{-1,-1},{2,-3/2},{1,2},{0,1}*){100,160},{65,51},{157,119},{43,119},{135,51}}},Sequence@@(2 {{10,10},{100,100}}),Locator,LocatorAutoCreate->{4,Infinity}},SaveDefinitions->True,Initialization:>((*test if point pt inside polygon poly*)testpoint[poly_,pt_]:=Round[(Total@Mod[(#-RotateRight[#])&@(ArcTan@@(pt-#)&/@poly),2 Pi,-Pi]/2/Pi)]!=0)];
Export["testWindingy.gif",Flatten@{list,Reverse@(Rest@list)}]

输出这种图片为了好看：

The Latest C++ Code

// NOTE: compile with g++ filename.cpp -std=c++11
#include <iostream>
#include <cmath>
#include <cstdlib>
#include <vector>
//#include <functional>
#define DIM1 600
#define DIM2 400
//#define DM1 (DIM1-1)
//#define DM2 (DIM2-1)
//#define _sq(x) ((x)*(x)) // square
//#define _cb(x) abs((x)*(x)*(x)) // absolute value of cube
//#define _cr(x) (unsigned char)(pow((x),1.0/3.0)) // cube root

unsigned char GR(int,int);
unsigned char BL(int,int);

#define F float
F e=1.e-7,p=3.14;
unsigned char RD(int i,int j){
// YOUR CODE HERE
#define E for(int k=0;k<5;k++){
#define at(x,y)  abs(x)>e?x>e?

atan(y/x):y>0?atan(y/x)+p:atan(y/x)-p:y>0?

p/2:-p/2
return 255;
}

bool Q(int i,int j,int* x){
    F t[5],o;
    E
        t[k]=at((F)(x[k]-i),(F)(x[k+5]-j));
    }
    F tl=0.;
    E
    o=t[(k+1)%5]-t[k];
        o+=o<-p?p:o>p?

-p:0;
    tl+=o;
    }
    return abs(tl)>.5;
    };

unsigned char GR(int i,int j){
// YOUR CODE HERE
    int q[10]={100, 135, 43, 157, 65, 40, 149, 81, 81, 149},
        r[10]={184, 220, 183, 207, 205, 168, 181, 191, 161, 199},
        s[10]={183, 208, 204, 185, 220, 50, 22, 59, 27, 42},
        t[10]={221, 259, 229, 239, 252, 135, 133, 157, 120, 156},
        u[10]={220, 254, 237, 231, 258,83, 66, 100, 62, 89};
    return Q(i,j,q)||Q(i,j,r)||Q(i,j,s)||Q(i,j,t)||Q(i,j,u)?255:0;
}
unsigned char BL(int i,int j){
// YOUR CODE HERE
    return 0;
}

void pixel_write(int,int);
FILE *fp;
int main(){
fp = fopen("MathPic.ppm","wb");
fprintf(fp, "P6\n%d %d\n255\n", DIM1, DIM2);
for(int j=0;j<DIM2;j++)
for(int i=0;i<DIM1;i++)
pixel_write(i,j);
fclose(fp);
system("pause");
return 0;
}
void pixel_write(int i, int j){
static unsigned char color[3];
color[0] = RD(i,j)&255;
color[1] = GR(i,j)&255;
color[2] = BL(i,j)&255;
fwrite(color, 1, 3, fp);
}

Brief Summary

1. 长处。代码已经进一步压缩到500多字符。大大缩短；
2. 缺点，没有严格在特定地方写代码，为满足140x3段字符的要求。

输出尽管近似。也是正常的红旗：

从这里easy看出,Vietnam的flag就非常easy画,仅仅有一个五角星!



但是美帝的星条旗,据说50个州“每周一星”，难度似乎应该更高? 长处是它的50星仅仅有相对平移木有相对旋转,或者也easy?

1.

---

1. 【宽:A=1.0；长:B=1.9，C=0.5385（7/13,7条间纹的阔度）D=0.76（1.9×2/5,B的2/5）E=F=0.0538（C/10）G=H=0.0633（D/12）星的直径:K=0.0616条纹的宽度:L=0.0769（1/13）】
   
   ↩