A. Wizards' Duel
time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Harry Potter and He-Who-Must-Not-Be-Named engaged in a fight to the death once again. This time they are located at opposite ends of the corridor of length l. Two opponents simultaneously charge a deadly spell in the enemy. We know that the impulse of Harry's magic spell flies at a speed of p meters per second, and the impulse of You-Know-Who's magic spell flies at a speed of q meters per second.

The impulses are moving through the corridor toward each other, and at the time of the collision they turn round and fly back to those who cast them without changing their original speeds. Then, as soon as the impulse gets back to it's caster, the wizard reflects it and sends again towards the enemy, without changing the original speed of the impulse.

Since Harry has perfectly mastered the basics of magic, he knows that after the second collision both impulses will disappear, and a powerful explosion will occur exactly in the place of their collision. However, the young wizard isn't good at math, so he asks you to calculate the distance from his position to the place of the second meeting of the spell impulses, provided that the opponents do not change positions during the whole fight.

Input

The first line of the input contains a single integer l (1 ≤ l ≤ 1 000) — the length of the corridor where the fight takes place.

The second line contains integer p, the third line contains integer q (1 ≤ p, q ≤ 500) — the speeds of magical impulses for Harry Potter and He-Who-Must-Not-Be-Named, respectively.

Output

Print a single real number — the distance from the end of the corridor, where Harry is located, to the place of the second meeting of the spell impulses. Your answer will be considered correct if its absolute or relative error will not exceed 10 - 4.

Namely: let's assume that your answer equals a, and the answer of the jury is b. The checker program will consider your answer correct if .

Sample test(s)
input
100
50
50
output
50
input
199
60
40
output
119.4
Note

In the first sample the speeds of the impulses are equal, so both of their meetings occur exactly in the middle of the corridor.

sb模拟题

显然弹几次都是一样的

 #include<set>
#include<map>
#include<cmath>
#include<ctime>
#include<deque>
#include<queue>
#include<bitset>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<iostream>
#include<algorithm>
#define LL long long
#define inf 0x7fffffff
#define pa pair<int,int>
#define pi 3.1415926535897932384626433832795028841971
using namespace std;
inline LL read()
{
LL x=,f=;char ch=getchar();
while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
return x*f;
}
double l,a,b,t1;
int main()
{
scanf("%lf%lf%lf",&l,&a,&b);
t1=l/(a+b);
cout<<l-t1*b<<endl;
}

cf591A

cf591A Wizards' Duel的更多相关文章

  1. Codeforces Round #327 (Div. 2) A. Wizards' Duel 水题

    A. Wizards' Duel Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/591/prob ...

  2. codeforces 591A. Wizards' Duel 解题报告

    题目链接:http://codeforces.com/problemset/problem/591/A 题目意思:其实看下面这幅图就知道题意了,就是Harry 和 He-Who-Must-Not-Be ...

  3. Codeforces Round #327 (Div. 2)-Wizards' Duel

    题意: 在一条长度为l的走廊,两个人站在走廊的左右两端分别以p,q的速度走来,问他们相遇时离左端的距离是多少? 思路: 非常简单的暴力题,不解释. 代码如下: #include <iostrea ...

  4. CodeForces 591A Wizards' Duel

    水题 #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> us ...

  5. Codeforces Round #327 (Div. 2)

    题目传送门 水 A - Wizards' Duel 题目都没看清就写了,1e-4精度WA了一次... /************************************************ ...

  6. CF:322D - Ciel and Duel 贪心 或者 DP 我用的贪心 。。难道sort跟qsort是不一样的么?

    D. Ciel and Duel time limit per test 2 seconds memory limit per test 256 megabytes input standard in ...

  7. Codeforces Round #114 (Div. 1) B. Wizards and Huge Prize 概率dp

    B. Wizards and Huge Prize Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest ...

  8. Codeforces Round #114 (Div. 1) A. Wizards and Trolleybuses 物理题

    A. Wizards and Trolleybuses Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/conte ...

  9. [codeforces167B]Wizards and Huge Prize

    B. Wizards and Huge Prize time limit per test: 2 seconds memory limit per test: 256 megabytes input: ...

随机推荐

  1. 用crontab设置svn的定期更新任务

    本以为用crontab设置svn的定期更新任务是件非常容易的事情,实践后方才知道,其实并不那么容易.设置例行性工作如下:0 8 * * * /usr/bin/svn up /data/test第二天, ...

  2. POJ题目细究

    acm之pku题目分类 对ACM有兴趣的同学们可以看看 DP:  1011   NTA                 简单题  1013   Great Equipment     简单题  102 ...

  3. 什么是mimeType?

    因特网多媒体邮件扩展标示内容是什么格式.告诉浏览器或者server如何解析该数据http的请求和相应都含有一个mimeType字段 =>content-type(通用首部)

  4. css.day04

    1. box   盒子模型 <p>   <span>   <hr/>   <div> css+   div  p  span css+  xhtml b ...

  5. 抓取锁的sql语句-第三次修改

    CREATE OR REPLACE PROCEDURE SOLVE_LOCK AS V_SQL VARCHAR2(3000); --定义 v_sql 接受抓取锁的sql语句CUR_LOCK SYS_R ...

  6. MESH

    本文由博主(YinaPan)原创,转载请注明出处:http://www.cnblogs.com/YinaPan/p/Unity_meshtest.html  A class that allows c ...

  7. Reverse Interger

    Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 Have you ...

  8. 10_RHEL安装搜狗输入法

    首先需要安装相关源 1.加入EPEL源 EPEL7几乎是必备的源: $ sudo yum install epel-release 2.添加mosquito-myrepo源 mosquito-myre ...

  9. underscorejs-find学习

    2.5 find 2.5.1 语法: _.find(list, predicate, [context]) 2.5.2 说明: 对list集合的每个成员依次进行匹配(根据predicate迭代函数检测 ...

  10. 解决WebService本地访问正常,远程无法访问的问题

    发布webservice后部署到自己的服务器上,然后本机,外网远程访问都没事,在用户服务器上部署后只能本机访问,远端访问不了,通过网络搜索到下面方法,但改后仍然不行.原来在自己服务器部署时是在默认网站 ...