题目:

第一次刷的时候漏掉了这道题。

Given a sorted linked list, delete all duplicates such that each element appear only once.

For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.

代码:

/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if ( !head ) return head;
ListNode dummpy(-);
dummpy.next = head;
ListNode* pre = head;
ListNode* curr = head->next;
while (curr)
{
if ( curr->val!=pre->val )
{
pre = curr;
curr = curr->next;
}
else
{
pre->next = curr->next;
curr = curr->next;
}
}
return dummpy.next;
}
};

tips:

纠结了一下才AC。原因是第一次写的时候:

pre = curr;
curr = curr->next;

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