先找出可能在最短路上的边,图变成了一个DAG,然后在新图上DFS求答案就可以了。

#include<iostream>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<cstdio>
#include<queue>
#include<vector>
using namespace std; const int INF=0x7FFFFFFF;
const int maxn=;
int n,m,C1,C2,tot;
int Cmax;
int val[maxn];
struct Edge
{
int u,v,L;
}e[];
int f[];
vector<int>g[maxn];
int dis[][maxn]; int ans[maxn],cnt;
int sta[maxn]; int MIN1,MIN2; void init()
{
MIN1=MIN2=INF;
tot=;C1=;
for(int i=;i<=;i++) g[i].clear();
} void add(int a,int b,int c)
{
e[tot].u=a,e[tot].v=b,e[tot].L=c;
g[a].push_back(tot);
tot++;
} void read()
{
scanf("%d%d%d%d",&Cmax,&n,&C2,&m);
for(int i=;i<=n;i++) scanf("%d",&val[i]);
for(int i=;i<=m;i++)
{
int u,v,L; scanf("%d%d%d",&u,&v,&L);
add(u,v,L);
add(v,u,L);
}
} void SPFA(int f,int st)
{
for(int i=;i<=;i++) dis[f][i]=INF;
dis[f][st]=;
int flag[maxn]; memset(flag,,sizeof flag);
queue<int>Q; Q.push(st); flag[st]=;
while(!Q.empty())
{
int head= Q.front(); Q.pop(); flag[head]=;
for(int i=;i<g[head].size();i++)
{
int id=g[head][i];
if(dis[f][head]+e[id].L<dis[f][e[id].v])
{
dis[f][e[id].v]=dis[f][head]+e[id].L;
if(flag[e[id].v]==)
{
Q.push(e[id].v);
flag[e[id].v]=;
}
}
}
}
} void dfs(int x,int num1,int num2,int deep)
{
sta[deep]=x; if(x==C2)
{
if(num2<MIN2)
{
MIN2=num2;
MIN1=num1;
for(int i=;i<=deep;i++) ans[i]=sta[i];
tot=deep;
} else if(num2==MIN2&&num1<MIN1)
{
MIN2=num2;
MIN1=num1;
for(int i=;i<=deep;i++) ans[i]=sta[i];
tot=deep;
}
return;
} for(int i=;i<g[x].size();i++)
{
if(f[g[x][i]]==) continue;
int to=e[g[x][i]].v; if(val[to]==Cmax/) dfs(to,num1,num2,deep+);
else if(val[to]>Cmax/) dfs(to,num1+val[to]-Cmax/,num2,deep+);
else if(val[to]<Cmax/)
{
if(num1>Cmax/-val[to]) dfs(to,num1+val[to]-Cmax/,num2,deep+);
else dfs(to,,num2+Cmax/-val[to]-num1,deep+);
}
}
} void work()
{
int len=dis[][C2]; for(int i=;i<tot;i++)
if(dis[][e[i].u]+e[i].L+dis[][e[i].v]==len)
f[i]=; dfs(,,,); printf("%d ",MIN2);
for(int i=;i<=tot;i++)
{
if(i<tot) printf("%d->",ans[i]);
else printf("%d ",ans[i]);
}
printf("%d\n",MIN1);
} int main()
{
init();
read();
SPFA(,C1);
SPFA(,C2);
work();
return ;
}

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