Note: This is a companion problem to the System Design problem: Design TinyURL.

TinyURL is a URL shortening service where you enter a URL such as https://leetcode.com/problems/design-tinyurl and it returns a short URL such as http://tinyurl.com/4e9iAk.

Design the encode and decode methods for the TinyURL service. There is no restriction on how your encode/decode algorithm should work. You just need to ensure that a URL can be encoded to a tiny URL and the tiny URL can be decoded to the original URL.

Python:

class Codec:
def __init__(self):
self.__random_length = 6
self.__tiny_url = "http://tinyurl.com/"
self.__alphabet = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
self.__lookup = {} def encode(self, longUrl):
"""Encodes a URL to a shortened URL. :type longUrl: str
:rtype: str
"""
def getRand():
rand = []
for _ in xrange(self.__random_length):
rand += self.__alphabet[random.randint(0, len(self.__alphabet)-1)]
return "".join(rand) key = getRand()
while key in self.__lookup:
key = getRand()
self.__lookup[key] = longUrl
return self.__tiny_url + key def decode(self, shortUrl):
"""Decodes a shortened URL to its original URL. :type shortUrl: str
:rtype: str
"""
return self.__lookup[shortUrl[len(self.__tiny_url):]]

Python:Using sha256

from hashlib import sha256

class Codec:

    def __init__(self):
self._cache = {}
self.url = 'http://tinyurl.com/' def encode(self, long_url):
"""Encodes a URL to a shortened URL.
:type long_url: str
:rtype: str
"""
key = sha256(long_url.encode()).hexdigest()[:6]
self._cache[key] = long_url
return self.url + key def decode(self, short_url):
"""Decodes a shortened URL to its original URL.
:type short_url: str
:rtype: str
"""
key = short_url.replace(self.url, '')
return self._cache[key]

C++:

class Solution {
public:
Solution() : gen_((random_device())()) {
} // Encodes a URL to a shortened URL.
string encode(string longUrl) {
string key = getRand();
while (lookup_.count(key)) {
key = getRand();
}
lookup_[key] = longUrl;
return "http://tinyurl.com/" + key;
} // Decodes a shortened URL to its original URL.
string decode(string shortUrl) {
return lookup_[shortUrl.substr(tiny_url.length())];
} private:
string getRand() {
string random;
for (int i = 0; i < random_length; ++i) {
random += alphabet_[uniform_int_distribution<int>{0, alphabet_.length() - 1}(gen_)];
}
return random;
} const int random_length = 6;
const string tiny_url = "http://tinyurl.com/";
const string alphabet_ = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
default_random_engine gen_;
unordered_map<string, string> lookup_;
};

  

类似题目:

[LeetCode] 534. Design TinyURL 设计短网址

All LeetCode Questions List 题目汇总

  

[LeetCode] 535. Encode and Decode TinyURL 编码和解码短网址的更多相关文章

  1. 535 Encode and Decode TinyURL 编码和解码精简URL地址

    详见:https://leetcode.com/problems/encode-and-decode-tinyurl/description/ C++: class Solution { public ...

  2. [LeetCode] Encode and Decode TinyURL 编码和解码精简URL地址

    Note: This is a companion problem to the System Design problem: Design TinyURL. TinyURL is a URL sho ...

  3. 535. Encode and Decode TinyURL - LeetCode

    Question 535. Encode and Decode TinyURL Solution 题目大意:实现长链接加密成短链接,短链接解密成长链接 思路:加密成短链接+key,将长链接按key保存 ...

  4. LC 535. Encode and Decode TinyURL

    Note: This is a companion problem to the System Design problem: Design TinyURL. TinyURL is a URL sho ...

  5. 【Leetcode】535. Encode and Decode TinyURL

    Question: TinyURL is a URL shortening service where you enter a URL such as https://leetcode.com/pro ...

  6. 【LeetCode】535. Encode and Decode TinyURL 解题报告(Python & C++)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 方法一:数组 方法二:字典 日期 题目地址:https://l ...

  7. 535. Encode and Decode TinyURL

    ▶ 要求给出一种对 URL 网址进行压缩和解压的算法,例如 https://leetcode.com/problems/design-tinyurl ←→ http://tinyurl.com/4e9 ...

  8. 535. Encode and Decode TinyURL 长短URL

    [抄题]: TinyURL is a URL shortening service where you enter a URL such as https://leetcode.com/problem ...

  9. 535. Encode and Decode TinyURL(rand and srand)

    Note: This is a companion problem to the System Design problem: Design TinyURL. TinyURL is a URL sho ...

随机推荐

  1. jni接口

    https://www.jianshu.com/p/d4a502420a89 #pragma once /*DO NOT EDIT THIS FILE - it is machine generate ...

  2. Jquery的$(document).click() 在iphone手机上失效的问题

    click事件和 touchstart事件共存 安卓IOS手机都适用 $(document).on("click touchstart", ".demo", f ...

  3. [POJ2083] Fracal

    Description A fractal is an object or quantity that displays self-similarity, in a somewhat technica ...

  4. Beta之前-凡事预则立(校园帮-追光的人)

    所属课程 软件工程1916 作业要求 Beta之前-凡事预则立 团队名称 追光的人 作业目标 在Beta冲刺之前,提前做好准备和规划 议题 1.讨论组长是否重选的议题和结论. 2.下一阶段需要改进完善 ...

  5. Spring源码窥探之:扩展原理BeanFactoryPostProcessor

    BeanPostPorcessor是在bean创建对象初始化前后进行拦截工作,而BeanFactoryPostProcessor是Bean工厂的后置处理器,在Bean定义加载完成之后,Bean实例初始 ...

  6. Apache Solr < 8.2.0远程命令执行漏洞(CVE-2019-0193)

    介绍:Apache Solr 是一个开源的搜索服务器.Solr 使用 Java 语言开发,主要基于 HTTP 和 Apache Lucene 实现. 漏洞原因:此次漏洞出现在Apache Solr的D ...

  7. 持续集成学习4 jenkins常见功能

    一.节点选择 1.yum安装jdk yum install -y java-1.8.0 java-1.8.0-openjdk-devel 2.节点选择有三种方式 a.通过系统自带功能限制任务只能在这个 ...

  8. zzulioj - 2619: 小新的信息统计

    题目链接:http://acm.zzuli.edu.cn/problem.php?id=2619 题目描述        马上就要新生赛了,QQ群里正在统计所有人的信息,每个人需要从群里下载文件,然后 ...

  9. python学习笔记一: 《python3 input()函数》

    一.在学习之前需要先了解: 1.Python3.x 中 input() 函数接受一个标准输入数据,返回为 string 类型,即把任何输入看作str. 2.input可以用作文本输入,如用户名,密码框 ...

  10. Alibaba Nacos:搭建Nacos平台

    1.下载安装包 https://github.com/alibaba/nacos/releases 往下翻,找到压缩包下载. 2.解压 tar -xvf nacos-server-$version.t ...