将一幅图像取平均值缩小N倍实现方法

        /// <summary>
        /// 将图像缩小N倍
        /// </summary>
        /// <param name="source">原图数据</param>
        /// <param name="height">原图高度</param>
        /// <param name="width">原图宽度</param>
        /// <param name="scale">缩小倍数</param>
        /// <returns></returns>
        public static ushort[] ImgNarrow(ushort[] source, int height, int width,int scale)
        {
            if (Convert.ToBoolean(height % scale) || Convert.ToBoolean(width % scale))
            {
                throw new Exception("高宽必须为" + scale + "的倍数");
            }
            ushort[] dest = new ushort[height * width / (scale * scale)];
            int n = ;
            for (int y = ; y < height; y = y + scale)
            {
                for (int x = ; x < width; x = x + scale)
                {
                    int index = y * width + x;
                    int sum = ;
                    for (int i = ; i < scale; i++)
                    {
                        for (int j = ; j < scale; j++)
                        {
                            sum += source[index + i * width + j];
                        }
                    }
                    dest[n] = Convert.ToUInt16(sum / (scale * scale));
                    n++;
                }
            }
            return dest;
        }

原图是灰度数据，最终的目的是将图像缩小了N倍，然后取周围N*N个点的灰度平均值作为新图像的值，目前这个实现复杂度有点高，有更优解请评论回复