A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.
图解:
此题过程分为三个阶段,分别是 1、负责后面一个节点,并且将这个节点插入到原来链表中 2、复制后面一个节点的random指针。 3 拆分组合链表为两部分。
第一部分代码:
while(currentnode!=null){//复制节点,并且将节点插入到该节点的后面
RandomListNode clonenode=new RandomListNode(currentnode.label);
clonenode.next=currentnode.next;
currentnode.next=clonenode;
currentnode=clonenode.next;
}
第二部分 代码:
currentnode=head;
while(currentnode!=null){//复制随机指针。
RandomListNode clonenode=currentnode.next;
if(currentnode.random!=null){
clonenode.random=currentnode.random.next;//这里要指向随机指针的后一个,因为是复制滴啊,千万不要忘记了。
}
currentnode=clonenode.next;
}
第三部分代码:
RandomListNode cloneHead=head.next;
currentnode=head;
while(currentnode.next!=null){
RandomListNode temp=currentnode.next;
currentnode.next=temp.next;
currentnode=temp;
}
总的代码:
class RandomListNode {
int label;
RandomListNode next, random;
RandomListNode(int x) { this.label = x; }
};
public class Solution {
public RandomListNode copyRandomList(RandomListNode head) {
if(head==null)return null;
RandomListNode currentnode=head;
while(currentnode!=null){//复制节点,并且将节点插入到该节点的后面
RandomListNode clonenode=new RandomListNode(currentnode.label);
clonenode.next=currentnode.next;
currentnode.next=clonenode;
currentnode=clonenode.next;
}
currentnode=head;
while(currentnode!=null){//复制随机指针。
RandomListNode clonenode=currentnode.next;
if(currentnode.random!=null){
clonenode.random=currentnode.random.next;//这里要指向随机指针的后一个,因为是复制滴啊,千万不要忘记了。
}
currentnode=clonenode.next;
}
RandomListNode cloneHead=head.next;
currentnode=head;
while(currentnode.next!=null){
RandomListNode temp=currentnode.next;
currentnode.next=temp.next;
currentnode=temp;
}
return cloneHead;
}
}
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.的更多相关文章
- [Linked List]Copy List with Random Pointer
Total Accepted: 53943 Total Submissions: 209664 Difficulty: Hard A linked list is given such that ea ...
- [Algo] 131. Deep Copy Linked List With Random Pointer
Each of the nodes in the linked list has another pointer pointing to a random node in the list or nu ...
- [LeetCode] Copy List with Random Pointer 拷贝带有随机指针的链表
A linked list is given such that each node contains an additional random pointer which could point t ...
- BUG-FREE-For Dream
一直直到bug-free.不能错任何一点. 思路不清晰:刷两天. 做错了,刷一天. 直到bug-free.高亮,标红. 185,OA(YAMAXUN)--- (1) findFirstDuplicat ...
- LeetCode——Copy List with Random Pointer(带random引用的单链表深拷贝)
问题: A linked list is given such that each node contains an additional random pointer which could poi ...
- Leetcode Copy List with Random Pointer
A linked list is given such that each node contains an additional random pointer which could point t ...
- leetcode bugfree note
463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的 ...
- 【leetcode】Copy List with Random Pointer (hard)
A linked list is given such that each node contains an additional random pointer which could point t ...
- Copy List with Random Pointer [LeetCode]
A linked list is given such that each node contains an additional random pointer which could point t ...
随机推荐
- Mysql 学习
一.ubuntu下mysql的安装: 通过sudo apt-get install mysql-server 完成: 然后可以通过/etc/init.d/mysql 进行start/stop/rest ...
- Mybatis_mybatis常用jdbcType数据类型
MyBatis 通过包含的jdbcType类型 BIT FLOAT CHAR TIMESTAMP OTHER UNDEFINED ...
- 转 c# 日期函数[string.Format----GetDateTimeFormats]格式 .
DateTime dt = DateTime.Now;Label1.Text = dt.ToString();//2005-11-5 13:21:25Label2.Text = dt.ToFileTi ...
- JAVA操作COOKIE
JAVA操作COOKIE 1.设置Cookie Cookie cookie = new Cookie("key", "value"); cookie.setMa ...
- Solve error: Cannot open include file: 'X11/Xlocale.h': No such file or directory
When you use FLTK with VS2010, you may get the error: fatal error C1083: Cannot open include file: ' ...
- 根据CSV找出USBGroup中计算机对应的用户
<USB.CSV> Hostname,Username CNHZPD-TEST1,User1 CNHZLN-01234567,User2 $group = "CN=Enabl ...
- HDU 4417 Super Mario(主席树求区间内的区间查询+离散化)
Super Mario Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Tota ...
- HDU 1043 & POJ 1077 Eight(康托展开+BFS+预处理)
Eight Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 30176 Accepted: 13119 Special ...
- DS实验题 Floyd最短路径 & Prim最小生成树
题目: 提示: Floyd最短路径算法实现(未测试): // // main.cpp // Alg_Floyd_playgame // // Created by wasdns on 16/11/19 ...
- 推荐的PHP编码规范
推荐的PHP编码规范 发布时间: 2014-05-7 浏览次数:2754 分类: PHP教程 推荐的PHP编码规范 一 编辑器设置 1. 使用Tab缩进,不要使用空格 鉴于很多编辑器在保存文件时会自动 ...