"""
2 把一个浮点数分解成证书备份和小数部分
3 """
4 def divide(num):
5 intnum = int(num)
6 floatnum = int(num) - intnum
7 return (str(intnum),str(floatnum))
8
9 han_list = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
10 unit_list = ["千","佰","拾"]
11
12 def convert(num):
13 result = ""
14 num_len = len(num)
15 for i in range(num_len):
16 number = int(num[i])
17 if num_len == 4 and number != 0 and i <= 2:
18 result += han_list[number] + unit_list[i]
19 elif num_len == 3 and number != 0 and i <2:
20 result += han_list[number] + unit_list[i + 1]
21 elif num_len == 2 and number != 0 and i <1:
22 result += han_list[number] + unit_list[i + 2]
23 else:
24 result += han_list[number]
25 return result
26 def convert2(num):
27 lennum = len(num)
28 if lennum > 12:
29 print("数字太大无法转换!")
30 return
31 elif lennum > 8:
32 return convert(num[:-8]) + "亿"+\
33 convert(num[-8:-4]) + "万"+\
34 convert(num[-4:])
35 elif lennum > 4:
36 return convert(num[:-4]) + "万"+\
37 convert(num[-4:])
38 else:
else:
39 return convert(num)
40 number = input()
41 intnum,floatnum = divide(number)
42 result = convert2(intnum)+ "元"
43
44 print(result)

运行结果

123456789
壹亿贰千叁佰肆拾伍万陆千柒佰捌拾玖元
一开始想用if嵌套来实现这个功能,后俩发现程序量过于大,所以就换了一种思如,附上代码,这个代码只实现了8为以上数字的转换

 """
2 问题描述
3 将一个数字转换成人命币的读法,并且数字要求转换为对应的大写数字
4 思路分析
5 1.详见其整数和小数分离出来
6 2.中国习惯将数字每四位划分为一个区间
7 3.
8 """
9 list1 = []
10 def sever_number(number):
11 int_number = int(number)
12 float_number =int(number) - int_number
13 #将其转化为字符串,以进行切片
14 return (str(int_number),str(float_number))
15 list_han = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
16 list_unit = ["千","佰","拾"]
17
18 def hanstr(number):
19 global list1
20 if len(number) > 8:
21 sever1 = number[:-8]
22 for i in sever1:
23 num = int(i)
24 a = list_han[num]
25 list1.append(a)
26 if sever1.index(i) == (len(sever1) - 1):
27 list1.append(list_unit[0])
28 sever2 = number[-8:-4]
29 for i in sever2:
30 num = int(i)
31 a = list_han[num]
32 list1.append(a)
33 if sever2.index(i) == (len(sever2) - 1):
34 sever3 = number[-4:]
35 for i in sever3:
36 num = int(i)
37 a = list_han[num]
38 list1.append(a)
39 return
40 num = input()
41 int_number,float_number = sever_number(num)
42 hanstr(int_number)
43 for i in list1:
44 print(i,end = "")
45 print("\n")
46
47
~

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