LeetCode 037 Sudoku Solver

题目要求：Sudoku Solver

Write a program to solve a Sudoku puzzle by filling the empty cells.

Empty cells are indicated by the character '.'.

You may assume that there will be only one unique solution.

A sudoku puzzle...

...and its solution numbers marked in red.

分析：

参考网址：http://www.cnblogs.com/panda_lin/archive/2013/11/04/sudoku_solver.html

回溯法尝试所有解0_o

① 对于每个空位'.'，遍历1~9，check合理之后递归；

② check的时候，不用遍历整个数独，只需检查加入的行、列和块就足够了。

代码如下：

class Solution {
public:
    bool isValidSudoku(vector<vector<char> > &board, int x, int y) {
        int row, col;

        // Same value in the same column?
        for (row = 0; row < 9; ++row) {
            if ((x != row) && (board[row][y] == board[x][y])) {
                return false;
            }
        }

        // Same value in the same row?
        for (col = 0; col < 9; ++col) {
            if ((y != col) && (board[x][col] == board[x][y])) {
                return false;
            }
        }

        // Same value in the 3 * 3 block it belong to?
        for (row = (x / 3) * 3; row < (x / 3 + 1) * 3; ++row) {
            for (col = (y / 3) * 3; col < (y / 3 + 1) * 3; ++col) {
                if ((x != row) && (y != col) && (board[row][col] == board[x][y])) {
                    return false;
                }
            }
        }

        return true;
    }

    bool internalSolveSudoku(vector<vector<char> > &board) {
        for (int row = 0; row < 9; ++row) {
            for (int col = 0; col < 9; ++col) {
                if ('.' == board[row][col]) {
                    for (int i = 1; i <= 9; ++i) {
                        board[row][col] = '0' + i;

                        if (isValidSudoku(board, row, col)) {
                            if (internalSolveSudoku(board)) {
                                return true;
                            }
                        }

                        board[row][col] = '.';
                    }

                    return false;
                }
            }
        }

        return true;
    }

    void solveSudoku(vector<vector<char> > &board) {
        internalSolveSudoku(board);
    }
};