Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

Example 1:

Given nums = [1,1,1,2,2,3],

Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3 respectively.

It doesn't matter what you leave beyond the returned length.

Example 2:

Given nums = [0,0,1,1,1,1,2,3,3],

Your function should return length = 7, with the first seven elements of nums being modified to 0, 0, 1, 1, 2, 3 and 3 respectively.

It doesn't matter what values are set beyond the returned length.

 class Solution {
public int removeDuplicates(int[] nums) {
int m = 0;
for (int i=0;i<nums.length;i++)
if (m < 2 || nums[i] > nums[m-2])
nums[m++] = nums[i];
return m; }
}

80. Remove Duplicates from Sorted Array II(双指针)的更多相关文章

  1. LeetCode 80 Remove Duplicates from Sorted Array II [Array/auto] <c++>

    LeetCode 80 Remove Duplicates from Sorted Array II [Array/auto] <c++> 给出排序好的一维数组,如果一个元素重复出现的次数 ...

  2. 【LeetCode】80. Remove Duplicates from Sorted Array II (2 solutions)

    Remove Duplicates from Sorted Array II Follow up for "Remove Duplicates":What if duplicate ...

  3. [leetcode] 80. Remove Duplicates from Sorted Array II (Medium)

    排序数组去重题,保留重复两个次数以内的元素,不申请新的空间. 解法一: 因为已经排好序,所以出现重复的话只能是连续着,所以利用个变量存储出现次数,借此判断. Runtime: 20 ms, faste ...

  4. [LeetCode] 80. Remove Duplicates from Sorted Array II 有序数组中去除重复项之二

    Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twic ...

  5. [LeetCode] 80. Remove Duplicates from Sorted Array II 有序数组中去除重复项 II

    Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twic ...

  6. 【一天一道LeetCode】#80. Remove Duplicates from Sorted Array II

    一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Follow ...

  7. [LeetCode] 80. Remove Duplicates from Sorted Array II ☆☆☆(从有序数组中删除重复项之二)

    https://leetcode.com/problems/remove-duplicates-from-sorted-array-ii/discuss/27976/3-6-easy-lines-C% ...

  8. **80. Remove Duplicates from Sorted Array II 删除排序数组中的重复项 II

    1. 原始题目 给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素最多出现两次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件 ...

  9. LeetCode 80. Remove Duplicates from Sorted Array II (从有序序列里移除重复项之二)

    Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For exampl ...

随机推荐

  1. Spring web.xml中的配置

    转载博客:http://blog.163.com/zhangke_616/blog/static/191980492007994948206/ 在实际项目中spring的配置文件application ...

  2. vue组件定义方式

    一.全局组件 <div id="box"> {{msg}} <my-aaa></my-aaa> </div> var Home = ...

  3. C语言位操作--奇偶校验算法

    信息是以比特流的方式传输的,类似01000001.在传输过程中,有可能会发生错误,比如,我们存储了01000001,但是取出来却是01000000,即低位由0变成了1.为了检测到这种错误,我们可以通过 ...

  4. ruby 升级1.8.7到1.9.3

    rvm install ruby 1.9.3 ruby -v 如果还是1.8.7. rvm use 1.9.3 列出所有版本 rvm list 设置默认的版本 rvm --default use x. ...

  5. 使用Speech SDK 5.1文字转音频

    下载地址: http://www.microsoft.com/en-us/download/details.aspx?id=10121 SeppchSDK51.exe 语音合成引擎 SpeechSDK ...

  6. 使用HtmlAgilityPack解析html

    HtmlAgilityPack是.net下使用xPath来解析html的类库,可以方便的做html的页面分析处理 项目地址: http://htmlagilitypack.codeplex.com/ ...

  7. linux系统下网络主-备份策略之网卡bond技术

    操作系统:CentOS Linux release 7.1.1503 (Core) 网卡适配器: eno1.eno2 bonding类型:mode=1 (active-backup),主-备份策略 网 ...

  8. sprint boot 配置

    来源:https://docs.spring.io/spring-boot/docs/current-SNAPSHOT/reference/htmlsingle/#howto-configure-to ...

  9. iOS - Charles抓包数据

    一.Charles Charles破解版下载地址点我 1.1 Charles主要的功能 .截取Http.Https网络请求内容 .支持修改网络请求参数,方便调试 .支持网络请求的截取 并动态修改 1. ...

  10. POJ-2029 Get Many Persimmon Trees(动态规划)

    Get Many Persimmon Trees Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 3987 Accepted: 2 ...