package countPrimes204;
/*
* Description:
* Count the number of prime numbers less than a non-negative number, n.
*/
public class Solution {
//Time Limit Exceeded
/*
public static int countPrimes(int n) {
int number=0;
for (int i=0;i<n;i++)
if(IsPrime(i)==true)
number++;
return number;
}
public static boolean IsPrime(int n){
if (n <= 3)
return n > 1;
else if (n%2==0||n%3==0)
return false;
else{
for(int i=2;i<=Math.sqrt(n);i++){
if(n%i == 0)
return false;
}
}
return true;
}
*/ public static int countPrimes(int n) {
//boolean default is false
boolean[] IsPrime=new boolean[n];
int numPrime=0;
for (int i=2;i<n;i++){
if (IsPrime[i-1]==false){
numPrime++;
for(int j=2;i*j<n;j++)
IsPrime[i*j-1]=true;
}
}
return numPrime;
}
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println(countPrimes(15000000));
boolean[] IsPrime=new boolean[2];
System.out.println(IsPrime[0]);
}
//reference
public int countPrimes2(int n) {
boolean[] notPrime = new boolean[n];
int count = 0;
for (int i = 2; i < n; i++) {
if (notPrime[i] == false) {
count++;
for (int j = 2; i*j < n; j++) {
notPrime[i*j] = true;
}
}
}
return count;
}
}

LeetCode----204. Count Primes(Java)的更多相关文章

  1. [leetcode] 204. Count Primes 统计小于非负整数n的素数的个数

    题目大意 https://leetcode.com/problems/count-primes/description/ 204. Count Primes Count the number of p ...

  2. Java [Leetcode 204]Count Primes

    题目描述: Description: Count the number of prime numbers less than a non-negative number, n. 解题思路: Let's ...

  3. Java for LeetCode 204 Count Primes

    Description: Count the number of prime numbers less than a non-negative number, n. 解题思路: 空间换时间,开一个空间 ...

  4. [LeetCode] 204. Count Primes 质数的个数

    Count the number of prime numbers less than a non-negative number, n. Example: Input: 10 Output: 4 E ...

  5. [LeetCode] 204. Count Primes 计数质数

    Description: Count the number of prime numbers less than a non-negative number, n click to show more ...

  6. LeetCode 204. Count Primes (质数的个数)

    Description: Count the number of prime numbers less than a non-negative number, n. 题目标签:Hash Table 题 ...

  7. LeetCode 204 Count Primes

    Problem: Count the number of prime numbers less than a non-negative number, n. Summary: 判断小于某非负数n的质数 ...

  8. (easy)LeetCode 204.Count Primes

    Description: Count the number of prime numbers less than a non-negative number, n. Credits:Special t ...

  9. [LeetCode] 204. Count Primes 解题思路

    Count the number of prime numbers less than a non-negative number, n. 问题:找出所有小于 n 的素数. 题目很简洁,但是算法实现的 ...

  10. LeetCode - 204. Count Primes - 埃拉托斯特尼筛法 95.12% - (C++) - Sieve of Eratosthenes

    原题 原题链接 Description: Count the number of prime numbers less than a non-negative number, n. 计算小于非负数n的 ...

随机推荐

  1. SQLserver 表字段修改语句

    增加字段 ) 删除字段 ALTER TABLE table_NAME DROP COLUMN column_NAME 修改字段类型 ALTER TABLE table_name ALTER COLUM ...

  2. javaScript中的数据类型

    一.综述 javaScript中的数据类型分为两类: 简单类型:Boolean,Number,String 引用类型:Object 其他:undefined代表变量没有初始化,null代表引用类型为空 ...

  3. Install .NET Framework 4.5.2 on a Cloud Service Role

    October Guest OS rollout is starting today October 15 2015, and projected to be released on November ...

  4. Hadoop2.2.0 第一步完成MapReduce wordcount计算文本数量

    1.完成Hadoop2.2.0单机版环境搭建之后需要利用一个例子程序来检验hadoop2 的mapreduce的功能 //启动hdfs和yarn sbin/start-dfs.sh sbin/star ...

  5. decimal类型保留两位小数

    oj.PriceTop =Math.Round(Convert.ToDecimal(reader["PriceTop"]),2);

  6. session 实现保存用户信息

    index.jsp <body> <div style="margin: 0 auto; width: 500px; text-align: center;"&g ...

  7. [原创]java WEB学习笔记84:Hibernate学习之路-- -映射 一对一关系 ,基外键的方式实现

    本博客的目的:①总结自己的学习过程,相当于学习笔记 ②将自己的经验分享给大家,相互学习,互相交流,不可商用 内容难免出现问题,欢迎指正,交流,探讨,可以留言,也可以通过以下方式联系. 本人互联网技术爱 ...

  8. JS不兼容减号,css属性转驼峰写法

    <script> function changeFormat(str) { return str.replace(/-(\w)/g, function(k, r) { return r.t ...

  9. SpringMvc:视图和视图解析器

    请求处理方法执行完成后,最终返回一个ModelAndView对象,对于返回String,View或ModelMap等类型的处理方法,SpringMvc也会在内部将它们装配成一个ModelAndView ...

  10. C++多线程调试和测试的注意事项

    在一个程序中,这些独立运行的程序片断叫作“线程”(Thread),利用它编程的概念就叫作“多线程处理”.利用线程,用户可按下一个按钮,然后程序会立即作出响应,而不是让用户等待程序完成了当前任务以后才开 ...