Mysql-巧用join来优化sql
0. 准备相关表来进行接下来的测试
相关建表语句请看：https://github.com/YangBaohust/my_sql
user1表，取经组
+----+-----------+-----------------+---------------------------------+
| id | user_name | comment | mobile |
+----+-----------+-----------------+---------------------------------+
| 1 | 唐僧 | 旃檀功德佛 | 138245623,021-382349 |
| 2 | 孙悟空 | 斗战胜佛 | 159384292,022-483432,+86-392432 |
| 3 | 猪八戒 | 净坛使者 | 183208243,055-8234234 |
| 4 | 沙僧 | 金身罗汉 | 293842295,098-2383429 |
| 5 | NULL | 白龙马 | 993267899 |
+----+-----------+-----------------+---------------------------------+ user2表，悟空的朋友圈
+----+--------------+-----------+
| id | user_name | comment |
+----+--------------+-----------+
| 1 | 孙悟空 | 美猴王 |
| 2 | 牛魔王 | 牛哥 |
| 3 | 铁扇公主 | 牛夫人 |
| 4 | 菩提老祖 | 葡萄 |
| 5 | NULL | 晶晶 |
+----+--------------+-----------+ user1_kills表，取经路上杀的妖怪数量
+----+-----------+---------------------+-------+
| id | user_name | timestr | kills |
+----+-----------+---------------------+-------+
| 1 | 孙悟空 | 2013-01-10 00:00:00 | 10 |
| 2 | 孙悟空 | 2013-02-01 00:00:00 | 2 |
| 3 | 孙悟空 | 2013-02-05 00:00:00 | 12 |
| 4 | 孙悟空 | 2013-02-12 00:00:00 | 22 |
| 5 | 猪八戒 | 2013-01-11 00:00:00 | 20 |
| 6 | 猪八戒 | 2013-02-07 00:00:00 | 17 |
| 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 |
| 8 | 沙僧 | 2013-01-10 00:00:00 | 3 |
| 9 | 沙僧 | 2013-01-22 00:00:00 | 9 |
| 10 | 沙僧 | 2013-02-11 00:00:00 | 5 |
+----+-----------+---------------------+-------+ user1_equipment表，取经组装备
+----+-----------+--------------+-----------------+-----------------+
| id | user_name | arms | clothing | shoe |
+----+-----------+--------------+-----------------+-----------------+
| 1 | 唐僧 | 九环锡杖 | 锦斓袈裟 | 僧鞋 |
| 2 | 孙悟空 | 金箍棒 | 梭子黄金甲 | 藕丝步云履 |
| 3 | 猪八戒 | 九齿钉耙 | 僧衣 | 僧鞋 |
| 4 | 沙僧 | 降妖宝杖 | 僧衣 | 僧鞋 |
+----+-----------+--------------+-----------------+-----------------+
1. 使用left join优化not in子句
例子：找出取经组中不属于悟空朋友圈的人
+----+-----------+-----------------+-----------------------+
| id | user_name | comment | mobile |
+----+-----------+-----------------+-----------------------+
| 1 | 唐僧 | 旃檀功德佛 | 138245623,021-382349 |
| 3 | 猪八戒 | 净坛使者 | 183208243,055-8234234 |
| 4 | 沙僧 | 金身罗汉 | 293842295,098-2383429 |
+----+-----------+-----------------+-----------------------+
not in写法：
select * from user1 a where a.user_name not in (select user_name from user2 where user_name is not null);
left join写法：
首先看通过user_name进行连接的外连接数据集
select a.*, b.* from user1 a left join user2 b on (a.user_name = b.user_name);
+----+-----------+-----------------+---------------------------------+------+-----------+-----------+
| id | user_name | comment | mobile | id | user_name | comment |
+----+-----------+-----------------+---------------------------------+------+-----------+-----------+
| 2 | 孙悟空 | 斗战胜佛 | 159384292,022-483432,+86-392432 | 1 | 孙悟空 | 美猴王 |
| 1 | 唐僧 | 旃檀功德佛 | 138245623,021-382349 | NULL | NULL | NULL |
| 3 | 猪八戒 | 净坛使者 | 183208243,055-8234234 | NULL | NULL | NULL |
| 4 | 沙僧 | 金身罗汉 | 293842295,098-2383429 | NULL | NULL | NULL |
| 5 | NULL | 白龙马 | 993267899 | NULL | NULL | NULL |
+----+-----------+-----------------+---------------------------------+------+-----------+-----------+
可以看到a表中的所有数据都有显示，b表中的数据只有b.user_name与a.user_name相等才显示，其余都以null值填充，要想找出取经组中不属于悟空朋友圈的人，只需要在b.user_name中加一个过滤条件b.user_name is null即可。
select a.* from user1 a left join user2 b on (a.user_name = b.user_name) where b.user_name is null;
+----+-----------+-----------------+-----------------------+
| id | user_name | comment | mobile |
+----+-----------+-----------------+-----------------------+
| 1 | 唐僧 | 旃檀功德佛 | 138245623,021-382349 |
| 3 | 猪八戒 | 净坛使者 | 183208243,055-8234234 |
| 4 | 沙僧 | 金身罗汉 | 293842295,098-2383429 |
| 5 | NULL | 白龙马 | 993267899 |
+----+-----------+-----------------+-----------------------+
看到这里发现结果集中还多了一个白龙马，继续添加过滤条件a.user_name is not null即可。
select a.* from user1 a left join user2 b on (a.user_name = b.user_name) where b.user_name is null and a.user_name is not null;
2. 使用left join优化标量子查询
例子：查看取经组中的人在悟空朋友圈的昵称
+-----------+-----------------+-----------+
| user_name | comment | comment2 |
+-----------+-----------------+-----------+
| 唐僧 | 旃檀功德佛 | NULL |
| 孙悟空 | 斗战胜佛 | 美猴王 |
| 猪八戒 | 净坛使者 | NULL |
| 沙僧 | 金身罗汉 | NULL |
| NULL | 白龙马 | NULL |
+-----------+-----------------+-----------+
子查询写法：
select a.user_name, a.comment, (select comment from user2 b where b.user_name = a.user_name) comment2 from user1 a;
left join写法：
select a.user_name, a.comment, b.comment comment2 from user1 a left join user2 b on (a.user_name = b.user_name);
3. 使用join优化聚合子查询
例子：查询出取经组中每人打怪最多的日期
+----+-----------+---------------------+-------+
| id | user_name | timestr | kills |
+----+-----------+---------------------+-------+
| 4 | 孙悟空 | 2013-02-12 00:00:00 | 22 |
| 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 |
| 9 | 沙僧 | 2013-01-22 00:00:00 | 9 |
+----+-----------+---------------------+-------+
聚合子查询写法：
select * from user1_kills a where a.kills = (select max(b.kills) from user1_kills b where b.user_name = a.user_name);
join写法：
首先看两表自关联的结果集，为节省篇幅，只取猪八戒的打怪数据来看
select a.*, b.* from user1_kills a join user1_kills b on (a.user_name = b.user_name) order by 1;
+----+-----------+---------------------+-------+----+-----------+---------------------+-------+
| id | user_name | timestr | kills | id | user_name | timestr | kills |
+----+-----------+---------------------+-------+----+-----------+---------------------+-------+
| 5 | 猪八戒 | 2013-01-11 00:00:00 | 20 | 5 | 猪八戒 | 2013-01-11 00:00:00 | 20 |
| 5 | 猪八戒 | 2013-01-11 00:00:00 | 20 | 6 | 猪八戒 | 2013-02-07 00:00:00 | 17 |
| 5 | 猪八戒 | 2013-01-11 00:00:00 | 20 | 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 |
| 6 | 猪八戒 | 2013-02-07 00:00:00 | 17 | 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 |
| 6 | 猪八戒 | 2013-02-07 00:00:00 | 17 | 5 | 猪八戒 | 2013-01-11 00:00:00 | 20 |
| 6 | 猪八戒 | 2013-02-07 00:00:00 | 17 | 6 | 猪八戒 | 2013-02-07 00:00:00 | 17 |
| 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 | 5 | 猪八戒 | 2013-01-11 00:00:00 | 20 |
| 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 | 6 | 猪八戒 | 2013-02-07 00:00:00 | 17 |
| 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 | 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 |
+----+-----------+---------------------+-------+----+-----------+---------------------+-------+
可以看到当两表通过user_name进行自关联，只需要对a表的所有字段进行一个group by，取b表中的max(kills)，只要a.kills=max(b.kills)就满足要求了。sql如下
select a.* from user1_kills a join user1_kills b on (a.user_name = b.user_name) group by a.id, a.user_name, a.timestr, a.kills having a.kills = max(b.kills);
4. 使用join进行分组选择
例子：对第3个例子进行升级，查询出取经组中每人打怪最多的前两个日期
+----+-----------+---------------------+-------+
| id | user_name | timestr | kills |
+----+-----------+---------------------+-------+
| 3 | 孙悟空 | 2013-02-05 00:00:00 | 12 |
| 4 | 孙悟空 | 2013-02-12 00:00:00 | 22 |
| 5 | 猪八戒 | 2013-01-11 00:00:00 | 20 |
| 7 | 猪八戒 | 2013-02-08 00:00:00 | 35 |
| 9 | 沙僧 | 2013-01-22 00:00:00 | 9 |
| 10 | 沙僧 | 2013-02-11 00:00:00 | 5 |
+----+-----------+---------------------+-------+
在oracle中，可以通过分析函数来实现
select b.* from (select a.*, row_number() over(partition by user_name order by kills desc) cnt from user1_kills a) b where b.cnt <= 2;
很遗憾，上面sql在mysql中报错ERROR 1064 (42000): You have an error in your SQL syntax; 因为mysql并不支持分析函数。不过可以通过下面的方式去实现。
首先对两表进行自关联，为了节约篇幅，只取出孙悟空的数据
select a.*, b.* from user1_kills a join user1_kills b on (a.user_name=b.user_name and a.kills<=b.kills) order by a.user_name, a.kills desc;
+----+-----------+---------------------+-------+----+-----------+---------------------+-------+
| id | user_name | timestr | kills | id | user_name | timestr | kills |
+----+-----------+---------------------+-------+----+-----------+---------------------+-------+
| 4 | 孙悟空 | 2013-02-12 00:00:00 | 22 | 4 | 孙悟空 | 2013-02-12 00:00:00 | 22 |
| 3 | 孙悟空 | 2013-02-05 00:00:00 | 12 | 3 | 孙悟空 | 2013-02-05 00:00:00 | 12 |
| 3 | 孙悟空 | 2013-02-05 00:00:00 | 12 | 4 | 孙悟空 | 2013-02-12 00:00:00 | 22 |
| 1 | 孙悟空 | 2013-01-10 00:00:00 | 10 | 1 | 孙悟空 | 2013-01-10 00:00:00 | 10 |
| 1 | 孙悟空 | 2013-01-10 00:00:00 | 10 | 3 | 孙悟空 | 2013-02-05 00:00:00 | 12 |
| 1 | 孙悟空 | 2013-01-10 00:00:00 | 10 | 4 | 孙悟空 | 2013-02-12 00:00:00 | 22 |
| 2 | 孙悟空 | 2013-02-01 00:00:00 | 2 | 1 | 孙悟空 | 2013-01-10 00:00:00 | 10 |
| 2 | 孙悟空 | 2013-02-01 00:00:00 | 2 | 3 | 孙悟空 | 2013-02-05 00:00:00 | 12 |
| 2 | 孙悟空 | 2013-02-01 00:00:00 | 2 | 4 | 孙悟空 | 2013-02-12 00:00:00 | 22 |
| 2 | 孙悟空 | 2013-02-01 00:00:00 | 2 | 2 | 孙悟空 | 2013-02-01 00:00:00 | 2 |
+----+-----------+---------------------+-------+----+-----------+---------------------+-------+
从上面的表中我们知道孙悟空打怪前两名的数量是22和12，那么只需要对a表的所有字段进行一个group by，对b表的id做个count，count值小于等于2就满足要求，sql改写如下：
select a.* from user1_kills a join user1_kills b on (a.user_name=b.user_name and a.kills<=b.kills) group by a.id, a.user_name, a.timestr, a.kills having count(b.id) <= 2;
5. 使用笛卡尔积关联实现一列转多行
例子：将取经组中每个电话号码变成一行
原始数据：
+-----------+---------------------------------+
| user_name | mobile |
+-----------+---------------------------------+
| 唐僧 | 138245623,021-382349 |
| 孙悟空 | 159384292,022-483432,+86-392432 |
| 猪八戒 | 183208243,055-8234234 |
| 沙僧 | 293842295,098-2383429 |
| NULL | 993267899 |
+-----------+---------------------------------+
想要得到的数据：
+-----------+-------------+
| user_name | mobile |
+-----------+-------------+
| 唐僧 | 138245623 |
| 唐僧 | 021-382349 |
| 孙悟空 | 159384292 |
| 孙悟空 | 022-483432 |
| 孙悟空 | +86-392432 |
| 猪八戒 | 183208243 |
| 猪八戒 | 055-8234234 |
| 沙僧 | 293842295 |
| 沙僧 | 098-2383429 |
| NULL | 993267899 |
+-----------+-------------+
可以看到唐僧有两个电话，因此他就需要两行。我们可以先求出每人的电话号码数量，然后与一张序列表进行笛卡儿积关联，为了节约篇幅，只取出唐僧的数据
select a.id, b.* from tb_sequence a cross join (select user_name, mobile, length(mobile)-length(replace(mobile, ',', ''))+1 size from user1) b order by 2,1;
+----+-----------+---------------------------------+------+
| id | user_name | mobile | size |
+----+-----------+---------------------------------+------+
| 1 | 唐僧 | 138245623,021-382349 | 2 |
| 2 | 唐僧 | 138245623,021-382349 | 2 |
| 3 | 唐僧 | 138245623,021-382349 | 2 |
| 4 | 唐僧 | 138245623,021-382349 | 2 |
| 5 | 唐僧 | 138245623,021-382349 | 2 |
| 6 | 唐僧 | 138245623,021-382349 | 2 |
| 7 | 唐僧 | 138245623,021-382349 | 2 |
| 8 | 唐僧 | 138245623,021-382349 | 2 |
| 9 | 唐僧 | 138245623,021-382349 | 2 |
| 10 | 唐僧 | 138245623,021-382349 | 2 |
+----+-----------+---------------------------------+------+
a.id对应的就是第几个电话号码，size就是总的电话号码数量，因此可以加上关联条件(a.id <= b.size)，将上面的sql继续调整
select b.user_name, replace(substring(substring_index(b.mobile, ',', a.id), char_length(substring_index(mobile, ',', a.id-1)) + 1), ',', '') as mobile from tb_sequence a cross join (select user_name, concat(mobile, ',') as mobile, length(mobile)-length(replace(mobile, ',', ''))+1 size from user1) b on (a.id <= b.size);
6. 使用笛卡尔积关联实现多列转多行
例子：将取经组中每件装备变成一行
原始数据：
+----+-----------+--------------+-----------------+-----------------+
| id | user_name | arms | clothing | shoe |
+----+-----------+--------------+-----------------+-----------------+
| 1 | 唐僧 | 九环锡杖 | 锦斓袈裟 | 僧鞋 |
| 2 | 孙悟空 | 金箍棒 | 梭子黄金甲 | 藕丝步云履 |
| 3 | 猪八戒 | 九齿钉耙 | 僧衣 | 僧鞋 |
| 4 | 沙僧 | 降妖宝杖 | 僧衣 | 僧鞋 |
+----+-----------+--------------+-----------------+-----------------+
想要得到的数据：
+-----------+-----------+-----------------+
| user_name | equipment | equip_mame |
+-----------+-----------+-----------------+
| 唐僧 | arms | 九环锡杖 |
| 唐僧 | clothing | 锦斓袈裟 |
| 唐僧 | shoe | 僧鞋 |
| 孙悟空 | arms | 金箍棒 |
| 孙悟空 | clothing | 梭子黄金甲 |
| 孙悟空 | shoe | 藕丝步云履 |
| 沙僧 | arms | 降妖宝杖 |
| 沙僧 | clothing | 僧衣 |
| 沙僧 | shoe | 僧鞋 |
| 猪八戒 | arms | 九齿钉耙 |
| 猪八戒 | clothing | 僧衣 |
| 猪八戒 | shoe | 僧鞋 |
+-----------+-----------+-----------------+
union的写法：
select user_name, 'arms' as equipment, arms equip_mame from user1_equipment
union all
select user_name, 'clothing' as equipment, clothing equip_mame from user1_equipment
union all
select user_name, 'shoe' as equipment, shoe equip_mame from user1_equipment
order by 1, 2;
join的写法：
首先看笛卡尔数据集的效果，以唐僧为例
select a.*, b.* from user1_equipment a cross join tb_sequence b where b.id <= 3;
+----+-----------+--------------+-----------------+-----------------+----+
| id | user_name | arms | clothing | shoe | id |
+----+-----------+--------------+-----------------+-----------------+----+
| 1 | 唐僧 | 九环锡杖 | 锦斓袈裟 | 僧鞋 | 1 |
| 1 | 唐僧 | 九环锡杖 | 锦斓袈裟 | 僧鞋 | 2 |
| 1 | 唐僧 | 九环锡杖 | 锦斓袈裟 | 僧鞋 | 3 |
+----+-----------+--------------+-----------------+-----------------+----+
使用case对上面的结果进行处理
select user_name,
case when b.id = 1 then 'arms'
when b.id = 2 then 'clothing'
when b.id = 3 then 'shoe' end as equipment,
case when b.id = 1 then arms end arms,
case when b.id = 2 then clothing end clothing,
case when b.id = 3 then shoe end shoe
from user1_equipment a cross join tb_sequence b where b.id <=3;
+-----------+-----------+--------------+-----------------+-----------------+
| user_name | equipment | arms | clothing | shoe |
+-----------+-----------+--------------+-----------------+-----------------+
| 唐僧 | arms | 九环锡杖 | NULL | NULL |
| 唐僧 | clothing | NULL | 锦斓袈裟 | NULL |
| 唐僧 | shoe | NULL | NULL | 僧鞋 |
+-----------+-----------+--------------+-----------------+-----------------+
使用coalesce函数将多列数据进行合并
select user_name,
case when b.id = 1 then 'arms'
when b.id = 2 then 'clothing'
when b.id = 3 then 'shoe' end as equipment,
coalesce(case when b.id = 1 then arms end,
case when b.id = 2 then clothing end,
case when b.id = 3 then shoe end) equip_mame
from user1_equipment a cross join tb_sequence b where b.id <=3 order by 1, 2;
7. 使用join更新过滤条件中包含自身的表
例子：把同时存在于取经组和悟空朋友圈中的人，在取经组中把comment字段更新为"此人在悟空的朋友圈"
我们很自然地想到先查出user1和user2中user_name都存在的人，然后更新user1表，sql如下
update user1 set comment = '此人在悟空的朋友圈' where user_name in (select a.user_name from user1 a join user2 b on (a.user_name = b.user_name));
很遗憾，上面sql在mysql中报错：ERROR 1093 (HY000): You can't specify target table 'user1' for update in FROM clause，提示不能更新目标表在from子句的表。
那有没有其它办法呢？我们可以将in的写法转换成join的方式
select c.*, d.* from user1 c join (select a.user_name from user1 a join user2 b on (a.user_name = b.user_name)) d on (c.user_name = d.user_name);
+----+-----------+--------------+---------------------------------+-----------+
| id | user_name | comment | mobile | user_name |
+----+-----------+--------------+---------------------------------+-----------+
| 2 | 孙悟空 | 斗战胜佛 | 159384292,022-483432,+86-392432 | 孙悟空 |
+----+-----------+--------------+---------------------------------+-----------+
然后对join之后的视图进行更新即可
update user1 c join (select a.user_name from user1 a join user2 b on (a.user_name = b.user_name)) d on (c.user_name = d.user_name) set c.comment = '此人在悟空的朋友圈';
再查看user1，可以看到user1已修改成功
select * from user1;
+----+-----------+-----------------------------+---------------------------------+
| id | user_name | comment | mobile |
+----+-----------+-----------------------------+---------------------------------+
| 1 | 唐僧 | 旃檀功德佛 | 138245623,021-382349 |
| 2 | 孙悟空 | 此人在悟空的朋友圈 | 159384292,022-483432,+86-392432 |
| 3 | 猪八戒 | 净坛使者 | 183208243,055-8234234 |
| 4 | 沙僧 | 金身罗汉 | 293842295,098-2383429 |
| 5 | NULL | 白龙马 | 993267899 |
+----+-----------+-----------------------------+---------------------------------+
8. 使用join删除重复数据
首先向user2表中插入两条数据
insert into user2(user_name, comment) values ('孙悟空', '美猴王');
insert into user2(user_name, comment) values ('牛魔王', '牛哥');
例子：将user2表中的重复数据删除，只保留id号大的
+----+--------------+-----------+
| id | user_name | comment |
+----+--------------+-----------+
| 1 | 孙悟空 | 美猴王 |
| 2 | 牛魔王 | 牛哥 |
| 3 | 铁扇公主 | 牛夫人 |
| 4 | 菩提老祖 | 葡萄 |
| 5 | NULL | 晶晶 |
| 6 | 孙悟空 | 美猴王 |
| 7 | 牛魔王 | 牛哥 |
+----+--------------+-----------+
首先查看重复记录
select a.*, b.* from user2 a join (select user_name, comment, max(id) id from user2 group by user_name, comment having count(*) > 1) b on (a.user_name=b.user_name and a.comment=b.comment) order by 2;
+----+-----------+-----------+-----------+-----------+------+
| id | user_name | comment | user_name | comment | id |
+----+-----------+-----------+-----------+-----------+------+
| 1 | 孙悟空 | 美猴王 | 孙悟空 | 美猴王 | 6 |
| 6 | 孙悟空 | 美猴王 | 孙悟空 | 美猴王 | 6 |
| 2 | 牛魔王 | 牛哥 | 牛魔王 | 牛哥 | 7 |
| 7 | 牛魔王 | 牛哥 | 牛魔王 | 牛哥 | 7 |
+----+-----------+-----------+-----------+-----------+------+
接着只需要删除(a.id < b.id)的数据即可
delete a from user2 a join (select user_name, comment, max(id) id from user2 group by user_name, comment having count(*) > 1) b on (a.user_name=b.user_name and a.comment=b.comment) where a.id < b.id;
查看user2，可以看到重复数据已经被删掉了
select * from user2;
+----+--------------+-----------+
| id | user_name | comment |
+----+--------------+-----------+
| 3 | 铁扇公主 | 牛夫人 |
| 4 | 菩提老祖 | 葡萄 |
| 5 | NULL | 晶晶 |
| 6 | 孙悟空 | 美猴王 |
| 7 | 牛魔王 | 牛哥 |
+----+--------------+-----------+
总结：给大家就介绍到这里，大家有兴趣可以多造点数据，然后比较不同的sql写法在执行时间上的区别。本文例子取自于慕课网《sql开发技巧》。
Mysql-巧用join来优化sql的更多相关文章
- mysql补充（3）优化sql语句查询常用的30种方法
1.对查询进行优化,应尽量避免全表扫描,首先应考虑在 where 及 order by 涉及的列上建立索引. 2.应尽量避免在 where 子句中使用!=或<>操作符,否则将引擎放弃使用索 ...
- 「MySQL高级篇」explain分析SQL，索引失效&&常见优化场景
大家好,我是melo,一名大三后台练习生 专栏回顾 索引的原理&&设计原则 欢迎关注本专栏:MySQL高级篇 本篇速览 在我们上一篇文章中,讲到了索引的原理&&设计原则 ...
- mysql优化SQL语句的一般步骤及常用方法
一.优化SQL语句的一般步骤 1. 通过show status命令了解各种SQL的执行频率 mysqladmin extended-status 或: show [session|global]sta ...
- MySQL 5.7 优化SQL提升100倍执行效率的深度思考(GO)
系统环境:微软云Linux DS12系列.Centos6.5 .MySQL 5.7.10.生产环境,step1,step2是案例,精彩的剖析部分在step3,step4. 1.慢sql语句大概需要13 ...
- mysql优化sql语句
mysql优化sql语句 常见误区 www.2cto.com 误区1: count(1)和count(primary_key) 优于 count(*) 很多人为了统计记录条数,就使 ...
- 重新学习MySQL数据库12：从实践sql语句优化开始
版权声明:本文为博主原创文章,未经博主允许不得转载. https://blog.csdn.net/a724888/article/details/79394168 本文不堆叠网上海量的sql优化技巧或 ...
- MySQL 一次非常有意思的SQL优化经历:从30248.271s到0.001s
转载自:https://www.toutiao.com/i6668275333034148356 一.背景介绍 用的数据库是mysql5.6,下面简单的介绍下场景 课程表: 数据100条 学生表: 数 ...
- MySql（五）SQL优化-优化SQL语句的一般步骤
MySql(五)SQL优化-优化SQL语句的一般步骤 一.优化SQL语句的一般步骤 1.1 通过show status命令了解各种SQL的执行频率 1.2 定位执行效率较低的SQL语句 1.3 通过e ...
- mysql 开发进阶篇系列 1 SQL优化(show status命令)
一.概述 随着上线后,数据越来越多,很多sql语句开始显露出性能问题,本章介绍在mysql中优化sql语句的方法. 1. 通过show status 命令了解各种sql的执行频率 通过show [ ...
随机推荐
- scala刷LeetCode--26 删除排序数组中的重复项
一.题目描述 给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完 ...
- SpringBoot项目构建成jar运行后，如何正确读取resource下的文件
SpringBoot项目构建成jar运行后,如何正确读取resource下的文件 不管你使用的是SpringBoot 1.x还是SpringBoot2.x,在开Dev环境中使用eclipse.IEAD ...
- 【朝花夕拾】Android自定义View篇之（十）TouchSlop及VelocityTracker
前言 在Android事件中,有几个比较基本的概念和知识点需要掌握.比如,表示最小移动阈值的TouchSlop,追踪事件速度的VelocityTracker,用于检测手势的GestureDetecto ...
- 提升布局性能____Re-using Layouts with <include/>
可以再一个布局中通过"include"和"merge"元素进行复用其他的布局元素. 比如如下一个布局: <FrameLayout xmlns:androi ...
- MMM 状压dp学习记
状压dp学习记 by scmmm 开始日期 2019/7/17 前言 状压dp感觉很好理解(本质接近于爆搜但是又有广搜的感觉),综合了dp的高效性(至少比dfs,bfs优),又能解决普通dp难搞定的问 ...
- Java编程思想：一个小小的控制框架
这个实验我很喜欢,学到了非常多的东西: import java.util.ArrayList; import java.util.List; public class Test { public st ...
- request 中url拼接排序参数与签名算法
一.参数要求: { appId:应用在后台创建应用时分配的应用编号,与应用密钥一一对应 sign:按照当前请求参数名的字母序进行升序排列(排序时区分大小写,除sign外,其它值不为空的参数都参与签名) ...
- while 循环,运算符,字符串的格式化
1.while 关键字 (死循环) while 条件: 循环体 条件:只要条件是 Ture就可以循环. while 空格 条件 冒号 缩进 循环体 while else while 空格 条件 冒号 ...
- Tiny Counting
也许更好的阅读体验 样例一 输入 4 1 4 3 2 输出 3 样例二 输入 5 9 1 0 0 5 输出 8 题解 这是本人自己想了2个半小时才想出来的方法,稍稍有点复杂但是很好理解 题目的意思就是 ...
- C#3.0新增功能09 LINQ 标准查询运算符 02 查询表达式语法
连载目录 [已更新最新开发文章,点击查看详细] 某些使用更频繁的标准查询运算符具有专用的 C# 语言关键字语法,使用这些语法可以在查询表达式中调用这些运算符. 查询表达式是比基于方法的等效项更具 ...