1、题目描述

2、问题分析

使用map记录元素出现的次数。

3、代码

 vector<int> v;
map<int,int> m;
vector<int> findMode(TreeNode* root) {
if (root == NULL)
return v;
preOrder(root);
int n = ;
for(map<int,int>::iterator it = m.begin(); it != m.end(); it++) {
if (it->second >= n)
n = it->second;
} for(map<int, int>::iterator it = m.begin(); it != m.end(); it++) {
if (it->second == n)
v.push_back(it->first);
} return v;
} void preOrder(TreeNode *root)
{
if (root != NULL)
m[root->val]++;
else
return;
preOrder(root->left);
preOrder(root->right);
}

LeetCode题解之 Find Mode in Binary Search Tree的更多相关文章

  1. LeetCode题解之Insert into a Binary Search Tree

    1.题目描述 2.分析 插入算法. 3.代码 TreeNode* insertIntoBST(TreeNode* root, int val) { insert(root, val); return ...

  2. [LeetCode 题解]:Convert Sorted List to Binary Search Tree

    Given a singly linked list where elements are sorted in ascending order, convert it to a height bala ...

  3. [LeetCode] 108. Convert Sorted Array to Binary Search Tree 把有序数组转成二叉搜索树

    Given an array where elements are sorted in ascending order, convert it to a height balanced BST. Fo ...

  4. [LeetCode] 109. Convert Sorted List to Binary Search Tree 把有序链表转成二叉搜索树

    Given a singly linked list where elements are sorted in ascending order, convert it to a height bala ...

  5. [LeetCode] Lowest Common Ancestor of a Binary Search Tree 二叉搜索树的最小共同父节点

    Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BS ...

  6. LeetCode: Lowest Common Ancestor of a Binary Search Tree 解题报告

    https://leetcode.com/submissions/detail/32662938/ Given a binary search tree (BST), find the lowest ...

  7. LeetCode 108. Convert Sorted Array to Binary Search Tree (有序数组转化为二叉搜索树)

    Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题目 ...

  8. 【leetcode刷题笔记】Validate Binary Search Tree

    Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as ...

  9. 【leetcode刷题笔记】Recover Binary Search Tree

    Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing ...

随机推荐

  1. C语言最最最基础部分(a+b为例)

      此篇为C语言最基础的部分知识简单概括,对C语言有一定了解的同学建议绕道哦~另外,文底附有此文知识点详细了解的链接. 下面我们以“a+b”为例,分析这个程序的组成. #include<stdi ...

  2. web自动化测试---xpath方式定位页面元素

    在实际应用中,如果存在多个相同元素,包括属性相同时,一般会选用这种方式,当然如果定位属性唯一的话,也是可以使用的,不过这种方式没有像id,tag,name等容易理解,下面讲下xpath定位元素的方法 ...

  3. cannot download, /home/azhukov/go is a GOROOT, not a GOPATH

    问题详情: go环境安装好后,运行go代码也没有问题 下载govendor包的时候提示: cannot download, /home/azhukov/go is a GOROOT, not a GO ...

  4. Hystrix参数配置

    1.Hystrix参数配置文档  2.Hystrix参数配置示例 import org.springframework.beans.factory.annotation.Autowired; impo ...

  5. mysql遇见contains nonaggregated column 'information_schema.PROFILING.SEQ'异常

    报错如下:[Err] 1055 - Expression #1 of ORDER BY clause is not in GROUP BY clause and contains nonaggrega ...

  6. postgresql 清空数据表 truncate

    在 mysql 中如果需要清空表,只需要 TRUNCATE table_name; 即可,如果有自增的 id 字段,也会还原回 1, 但是 postgresql 与 mysql 稍有不同,postgr ...

  7. Java 容器源码分析之ConcurrentHashMap

    深入浅出ConcurrentHashMap(1.8) 前言 HashMap是我们平时开发过程中用的比较多的集合,但它是非线程安全的,在涉及到多线程并发的情况,进行put操作有可能会引起死循环,导致CP ...

  8. 经济学人使用Golang构建微服务历程回顾

    关键点 经济学人内容分发系统需要更大的灵活性,将内容传递给日益多样化的数字渠道.为了实现这一灵活性目标并保持高水平的性能和可靠性,平台从一个单体结构过渡到微服务体系结构. 用Go编写的服务是新系统的一 ...

  9. Angular2入门:TypeScript的类 - 定义、继承和作用域

    一.定义和继承 二.public.private和protected

  10. css布局------上下高度固定,中间高度自适应容器

    HTML <body> <div class="container"> <div class="header"></d ...