Palindrome Partitioning

Palindrome Partitioning

Given a string s, partition s such that every substring of the partition is a palindrome.

Return all possible palindrome partitioning of s.

For example, given s = "aab",
Return

  [
    ["aa","b"],
    ["a","a","b"]
  ]
参考了这个锅锅的，思路很清晰，用的类似DFS递归实现http://www.sjsjw.com/kf_code/article/033776ABA018056.asp

 import java.util.ArrayList;
 import java.util.List;

 public class Solution {

     public List<List<String>> partition(String s) {
         List<List<String>> result = new ArrayList<List<String>>();            //存放结果
         List<String> curList = new ArrayList<String>();                        //记录当前结果

         if(s.length() == 0)
             return result;
         getResult(result, curList, s);

         return result;
     }

     /**
      * 判断字符串是否为回文
      * @param str
      * @return
      */
     public boolean isPalindrom(String str){
         for(int i = 0, j = str.length() - 1; i < j; i++, j--){
             if(str.charAt(i) != str.charAt(j))
                 return false;
         }

         return true;
     }

     /**
      * 递归调用
      * @param curList
      * @param str
      */
     public void getResult(List<List<String>> result,List<String> curList, String str){
         if(str.length() == 0)
             result.add(new ArrayList<String>(curList));                //满足条件添加到结果集中,注意这里因为curList是引用，必须new一个新的list出来
         else{
             for(int i = 1; i <= str.length();i++){
                 String head = str.substring(0, i);
                 if(isPalindrom(head)){                                //子串是回文
                     curList.add(head);
                     getResult(result, curList, str.substring(i));
                     curList.remove(curList.size() - 1);
                 }
             }
         }
     }
 //    public void show(List<List<String>> list){
 //        for(List<String> list_temp : list){
 //            for(String string_temp : list_temp){
 //                System.out.print(string_temp + " ");
 //            }
 //            System.out.println();
 //        }
 //    }
 }