HDU 5188 背包

有N道题。要求得到最少W分

给出N道题的：每道题用时T。分数V，应在且必须在L时刻提交才干得分

问得到W分所用的最少的时间

以L-T排序，然后做01背包就可以

#include "stdio.h"
#include "algorithm"
#include "string.h"
using namespace std;

struct Mark
{
    int t,v,l,x;
}mark[40];

int dp[300010];

bool cmp(Mark a,Mark b)
{
   if (a.x!=b.x) return a.x<b.x;
     return a.l<b.l;
}
int Max(int a,int b)
{
    if (a<b) return b;
    else return a;
}
int main()
{
    int n,m,i,j,ans,up,sum,sum1;
    while (scanf("%d%d",&n,&m)!=EOF)
    {
        sum=sum1=up=0;
        for (i=1;i<=n;i++)
        {

            scanf("%d%d%d",&mark[i].t,&mark[i].v,&mark[i].l);
            sum+=mark[i].v;
            sum1+=mark[i].t;
            up=Max(up,mark[i].l);
            mark[i].x=mark[i].l-mark[i].t;
        }
        if (sum<m) {printf("zhx is naive!\n"); continue;}
        up=Max(up,sum1);
        sort(mark+1,mark+n+1,cmp);
        memset(dp,0,sizeof(dp));
        for (i=1;i<=n;i++)
            for (j=up;j>=mark[i].l ;j--)
            dp[j]=Max(dp[j],dp[j-mark[i].t]+mark[i].v);

        ans=up+1;
        for (i=0;i<=up;i++)
        if (dp[i]>=m) {ans=i;break;}
        if(ans==up+1) printf("zhx is naive!\n");
        else printf("%d\n",ans);
    }
    return 0;
}