leetcode第18题--Letter Combinations of a Phone Number

Problem：

Given a digit string, return all possible letter combinations that the number could represent.

A mapping of digit to letters (just like on the telephone buttons) is given below.

Input:Digit string "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].

Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.

想了半天不知道怎么做，对递归真心不熟悉。特意看了算法导论的两个优先搜索，即广度优先和深度优先 bfs 和 dfs，这题用到的是dfs方法。

void dfs(int len, string s, string t, vector<string> &ans)
{
    string ss[] = {"","","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"};
    if (len == s.size()) // 当t已经存够s长度个的时候就可以push到答案中并返回
    {
        ans.push_back(t);
        return;
    }
    for (int i = ; i < ss[s[len] -''].size(); ++i) // 进行深度优先搜索，len相当于depth
    {
        dfs(len + , s, t + ss[s[len] - ''][i], ans);
    }
}
vector<string> letterCombinations(string digits)
{
    vector<string> ans;
    ans.clear();
    if (digits.size() == )
    {
        ans.push_back("");
        return ans;
    }
    dfs(, digits, "", ans);// 从第零层temp str 为空开始往深处搜索
    return ans;
}