D. Yet Another Monster Killing Problem

You play a computer game. In this game, you lead a party of

Educational Codeforces Round 76 (Rated for Div. 2) D. Yet Another Monster Killing Problem 贪心的更多相关文章

  1. Educational Codeforces Round 76 (Rated for Div. 2) D. Yet Another Monster Killing Problem

    You play a computer game. In this game, you lead a party of mm heroes, and you have to clear a dunge ...

  2. Educational Codeforces Round 76 (Rated for Div. 2) E. The Contest

    Educational Codeforces Round 76 (Rated for Div. 2) E. The Contest(dp+线段树) 题目链接 题意: 给定3个人互不相同的多个数字,可以 ...

  3. Educational Codeforces Round 76 (Rated for Div. 2)E(dp||贪心||题解写法）

    题:https://codeforces.com/contest/1257/problem/E 题意:给定3个数组,可行操作:每个数都可以跳到另外俩个数组中去,实行多步操作后使三个数组拼接起来形成升序 ...

  4. Educational Codeforces Round 76 (Rated for Div. 2)

    传送门 A. Two Rival Students 签到. Code /* * Author: heyuhhh * Created Time: 2019/11/13 22:37:26 */ #incl ...

  5. Educational Codeforces Round 76 (Rated for Div. 2) E. The Contest dp

    E. The Contest A team of three programmers is going to play a contest. The contest consists of

  6. Educational Codeforces Round 76 (Rated for Div. 2) C. Dominated Subarray 水题

    C. Dominated Subarray Let's call an array

  7. Educational Codeforces Round 76 (Rated for Div. 2) B. Magic Stick 水题

    B. Magic Stick Recently Petya walked in the forest and found a magic stick. Since Petya really likes ...

  8. Educational Codeforces Round 76 (Rated for Div. 2) A. Two Rival Students 水题

    A. Two Rival Students There are

  9. Educational Codeforces Round 76 (Rated for Div. 2) D题

    题意: 给你n个关卡,每个关卡有一个怪物,怪物的攻击力为a[i],你有n个英雄,每个英雄有一个攻击力,和疲劳值,只要英雄的攻击力比怪物的高就算打过了,同时疲劳减一,一天只能出战一个英雄,一个英雄可以打 ...

随机推荐

  1. ProjectServer2010升级到ProjectServer2016,Sharepoint2010升级到Sharepoint2016第一章

    之后还原 Project Server 2010 数据库和包含 Project Web App 网站数据的 SharePoint 内容数据库,您可以运行数据和 Project Web App 网站集升 ...

  2. 一文解读Redis (转)

    本文由葡萄城技术团队编撰并首发 转载请注明出处:葡萄城官网,葡萄城为开发者提供专业的开发工具.解决方案和服务,赋能开发者. 引言 在Web应用发展的初期,那时关系型数据库受到了较为广泛的关注和应用,原 ...

  3. InnoDB On-Disk Structures（一）-- Tables (转载）

    转载.节选于https://dev.mysql.com/doc/refman/8.0/en/innodb-tables.html 1.InnoDB Architecture The following ...

  4. [Go]TCP服务中增加消息队列与工作池

    之前的处理中每一个连接都会创建一个主groutine , 每个连接中的主groutine中创建出读groutine 和写groutine 每个连接处理业务再单独开出一个groutine ,这样如果有1 ...

  5. Appium 1.15.1版本的appium-doctor不是内部或者外部命令的问题

    先讲一下整个app自动化环境的部署过程: 1.安装appium 2.安装nodejs 3.查看appium的环境是否完成 问题:安装appium和nodejs都没啥问题,直接到对应的官网下载然后安装即 ...

  6. November 24th, Week 48th, Sunday, 2019

    Once you replace negative thoughts with positive ones, you will start having positive results. 淘汰消极思 ...

  7. CMKAE简单实用指南

    CMake is an open-source, cross-platform family of tools designed to build, test and package software ...

  8. laravel中间件的使用

    简介HTTP 中间件提供了为过滤进入应用的 HTTP 请求提供了一套便利的机制.例如,Laravel 内置了一个中间件来验证用户是否经过授权,如果用户没有经过授权,中间件会将用户重定向到登录页面,否则 ...

  9. 这可能是最漂亮的Spring事务管理详解

    事务概念回顾 什么是事务? 事务是逻辑上的一组操作,要么都执行,要么都不执行. 事物的特性(ACID): 原子性: 事务是最小的执行单位,不允许分割.事务的原子性确保动作要么全部完成,要么完全不起作用 ...

  10. 【algo&ds】6.图及其存储结构、遍历

    1.什么是图 图表示"多对多"的关系 包含 一组顶点:通常用 V(Vertex)表示顶点集合 一组边:通常用 E(Edge)表示边的集合 边是顶点对:(v,w)∈ E,其中 v,w ...