C. Basketball Exercise

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Finally, a basketball court has been opened in SIS, so Demid has decided to hold a basketball exercise session. 2⋅n2⋅n students have come to Demid's exercise session, and he lined up them into two rows of the same size (there are exactly nn people in each row). Students are numbered from 11 to nn in each row in order from left to right.

Now Demid wants to choose a team to play basketball. He will choose players from left to right, and the index of each chosen player (excluding the first one taken) will be strictly greater than the index of the previously chosen player. To avoid giving preference to one of the rows, Demid chooses students in such a way that no consecutive chosen students belong to the same row. The first student can be chosen among all 2n2n students (there are no additional constraints), and a team can consist of any number of students.

Demid thinks, that in order to compose a perfect team, he should choose students in such a way, that the total height of all chosen students is maximum possible. Help Demid to find the maximum possible total height of players in a team he can choose.

Input

The first line of the input contains a single integer nn (1≤n≤1051≤n≤105) — the number of students in each row.

The second line of the input contains nn integers h1,1,h1,2,…,h1,nh1,1,h1,2,…,h1,n (1≤h1,i≤1091≤h1,i≤109), where h1,ih1,i is the height of the ii-th student in the first row.

The third line of the input contains nn integers h2,1,h2,2,…,h2,nh2,1,h2,2,…,h2,n (1≤h2,i≤1091≤h2,i≤109), where h2,ih2,i is the height of the ii-th student in the second row.

Output

Print a single integer — the maximum possible total height of players in a team Demid can choose.

Examples
input

Copy
5
9 3 5 7 3
5 8 1 4 5
output

Copy
29
input

Copy
3
1 2 9
10 1 1
output

Copy
19
input

Copy
1
7
4
output

Copy
7
Note

In the first example Demid can choose the following team as follows:

In the second example Demid can choose the following team as follows:

题意:每行输入n个数,一共两行,取过一个数之后,不能再取和它相邻的数(不包括对角相邻),问取数总和最大为多少

题解:状态转移方程:dp[0][i]=max( dp[0][i] , dp[1][i-1]+a[i] );

dp[1][i]=max( dp[1][i] , dp[0][i-1]+b[i] );

#include<iostream>
#include<algorithm>
#include<math.h>
#define ll long long
using namespace std;
ll dp[][],a[],b[];
ll n;
int main()
{
ll n;
cin>>n;
for(int i=;i<n;i++)
scanf("%lld",&a[i]);
for(int i=;i<n;i++)
scanf("%lld",&b[i]);
dp[][]=a[];
dp[][]=b[];
for(int i=;i<n;i++)
{
dp[][i]=max(dp[][i-],dp[][i-]+a[i]);
dp[][i]=max(dp[][i-],dp[][i-]+b[i]);
}
ll ans=max(dp[][n-],dp[][n-]);
printf("%lld\n",ans );
return ;
}

C. Basketball Exercise dp的更多相关文章

  1. Codeforces Round #304 (Div. 2) C. Basketball Exercise (DP)

    题意:给你两个长度相同的数组,每次从两个数组中选数(也可以不选),但是不可以在同一个数组中连续选两次,问能选的最大值是多少? 题解:dp,\(dp[i][0]\)表示第\(i\)个位置不选,\(dp[ ...

  2. CF1195C Basketball Exercise (dp + 贪心)

    题解出处:https://www.luogu.org/problemnew/solution/CF1195C 很水的一道C题……目测难度在黄~绿左右.请各位切题者合理评分. 注意到可以选择的球员编号是 ...

  3. Codeforces Round #574 (Div. 2)——C. Basketball Exercise(简单DP)

    题目传送门 题意: 输入n,给出两组均为 n个数字的数组a和b,轮流从a和b数组中取出一个数字,要求严格按照当前所选数字的数组下标比上一个所选数字的数组下标更大,计算能够取出的数字加起来的总和最大能为 ...

  4. Codeforces Round #574 (Div. 2)补题

    A. Drinks Choosing 统计每种酒有多少人偏爱他们. ki 为每种酒的偏爱人数. 输出ans = (n + 1)/2 >  Σki / 2 ? (n + 1)/2 - Σki / ...

  5. 第9周cf刷题(dp)

    Problems(1300-1600) an ac a day keeps the doctor away Gas Pipeline (1500) 2019.10.28 题意: 管道工人需要在一段凹凸 ...

  6. Codeforce Round #574(Div.2)

                                                                                                        ...

  7. Codeforces Round #574 (Div. 2)

    目录 Contest Info Solutions A. Drinks Choosing B. Sport Mafia C. Basketball Exercise D1. Submarine in ...

  8. Codeforces Round #574 (Div. 2) A~E Solution

    A. Drinks Choosing 有 $n$ 个人,每个人各有一种最喜欢的饮料,但是买饮料的时候只能同一种的两个两个买(两个一对) 学校只打算卖 $\left \lceil \frac{n}{2} ...

  9. BZOJ_2097_[Usaco2010 Dec]Exercise 奶牛健美操_二分答案+树形DP

    BZOJ_2097_[Usaco2010 Dec]Exercise 奶牛健美操_二分答案+树形DP Description Farmer John为了保持奶牛们的健康,让可怜的奶牛们不停在牧场之间 的 ...

随机推荐

  1. 外部IC寄存器的位定义

    宏定义法:直接就是常量操作 方法1:用#define来定义,方便省事,缺点:系统不做检查 方法2:用enum来定义,可以像#define一样定义常量,同时系统做检查.既可以定义某个位也可以定义几个位的 ...

  2. 【转】ERP系统测试方法

    问题: 1.如何进行ERP系统测试用例设计? 2.ERP系统测试用例设计过程? 3.ERP系统测试用例设计的方法?    ERP系统本身是一种业务流程很复杂,单据报表众多,逻辑性很强的系统,质量保证方 ...

  3. 解决IE打开时,弹出的提示调用active的问题,阻止js运行。

    在html和head中间加上: <!-- saved from url=(0014)about:internet -->

  4. SignalR Connection has not been fully initialized

    在使用 SignalR 过程中遇到 SignalR: Connection has not been fully initialized. Use .start().done() or .start( ...

  5. Codeforces 1304C. Air Conditioner

    本题直接对每个区间取并,若出现非法区间就是No 否则就是Yes #include<bits/stdc++.h> using namespace std; #define lowbit(x) ...

  6. sql数据库的基本操作

    命令行 1.显示当前数据库服务器中的数据库列表:mysql> SHOW DATABASES;2.建立数据库:mysql> CREATE DATABASE 库名;3.建立数据表:mysql& ...

  7. Django学习之ORM练习题

    一.表关系 创建表关系,并创建约束 班级表:class 学生表: student cid caption grade_id sid sname gender class_id 1 一年一班 1 1 乔 ...

  8. ping命令工具:同时ping多个IP

    检测多个ip在同一时间点的响应状态,通过对比来判断哪个ip异常. 下载地址:https://share.weiyun.com/5XCkypG

  9. java实现邮箱发送邮件

    第一步:封装发件人账号密码 import javax.mail.Authenticator;import javax.mail.PasswordAuthentication; /** * 发件人账号密 ...

  10. 【快学springboot】2.Restful简介,SpringBoot构建Restful接口

    Restful简介 Restful一种软件架构风格.设计风格,而不是标准,只是提供了一组设计原则和约束条件.它主要用于客户端和服务器交互类的软件.基于这个风格设计的软件可以更简洁,更有层次,更易于实现 ...