Tautology
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 10453   Accepted: 3967

Description

WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some subset of the possible symbols K, A, N, C, E, p, q, r, s, t. A Well-formed formula (WFF) is any string of these symbols obeying the following rules:

  • p, q, r, s, and t are WFFs
  • if w is a WFF, Nw is a WFF
  • if w and x are WFFs, Kwx, Awx, Cwx, and Ewx are WFFs.

The meaning of a WFF is defined as follows:

  • p, q, r, s, and t are logical variables that may take on the value 0 (false) or 1 (true).
  • K, A, N, C, E mean and, or, not, implies, and equals as defined in the truth table below.
Definitions of K, A, N, C, and E
     w  x   Kwx   Awx    Nw   Cwx   Ewx
  1  1   1   1    0   1   1
  1  0   0   1    0   0   0
  0  1   0   1    1   1   0
  0  0   0   0    1   1   1

A tautology is a WFF that has value 1 (true) regardless of the values of its variables. For example, ApNp is a tautology because it is true regardless of the value of p. On the other hand, ApNq is not, because it has the value 0 for p=0, q=1.

You must determine whether or not a WFF is a tautology.

Input

Input consists of several test cases. Each test case is a single line containing a WFF with no more than 100 symbols. A line containing 0 follows the last case.

Output

For each test case, output a line containing tautology or not as appropriate.

Sample Input

ApNp
ApNq
0

Sample Output

tautology
not

Source

 
 
 
 
 
 
 
 
 
代码
#include<stdio.h>
#include<string.h>
#include<stack>
#include<iostream>
#include<algorithm>
using namespace std;
char str[200];
int p,q,r,s,t;
 stack<int>Q;
void instack(char c){
       if(c=='p')
       Q.push(p);
       else if(c=='q')
       Q.push(q);
       else  if(c=='r')
       Q.push(r);
       else  if(c=='s')
       Q.push(s);
       else  if(c=='t')
       Q.push(t);
       else
       return;
}
void calculate(char c){
    int a,b,temp;
     if(c=='K'){
         a=Q.top();
         Q.pop();
         b=Q.top();
         Q.pop();
         temp=a&b;
         Q.push(temp);
     }
     else  if(c=='A'){
         a=Q.top();
         Q.pop();
         b=Q.top();
         Q.pop();
         temp=a||b;
         Q.push(temp);
     }
     else  if(c=='E'){
        a=Q.top();
         Q.pop();
         b=Q.top();
         Q.pop();
         temp=(a==b);
         Q.push(temp);
     }
     else  if(c=='C'){
      a=Q.top();
         Q.pop();
         b=Q.top();
         Q.pop();
         temp=(!a)||b;
         Q.push(temp);
     }
     else  if(c=='N'){
         a=Q.top();
         Q.pop();
         temp=!a;
         Q.push(temp);
     }
     else
     return ;
}
int  main(){
    while(scanf("%s",str)!=EOF){
        getchar();
       if(strcmp(str,"0")==0)
       break;
       int len=strlen(str);
       int flag;
       for( p=0;p<=1;p++){
           for( q=0;q<=1;q++){
               for(r=0;r<=1;r++){
                   for( s=0;s<=1;s++){
                       for( t=0;t<=1;t++){
                            flag=0;
                           for(int i=len-1;i>=0;i--){
                               if(str[i]=='p'||str[i]=='q'||str[i]=='r'||str[i]=='s'||str[i]=='t')
                                  instack(str[i]);
                                  else
                                  calculate(str[i]);
                           }
                           int ans=Q.top();
                           Q.pop();
                           if(ans==0){
                              flag=1;
                              break;
                           }

}
                       if(flag) break;
                   }
                    if(flag) break;
               }
                if(flag) break;
           }
            if(flag) break;
       }
       if(flag)
       printf("not\n");
       else
       printf("tautology\n");
       memset(str,0,sizeof(str));
    }
    return 0;
}

poj3295的更多相关文章

  1. [POJ3295]Tautology

    [POJ3295]Tautology 试题描述 WFF 'N PROOF is a logic game played with dice. Each die has six faces repres ...

  2. POJ-3295 Tautology---栈+表达式求值

    题目链接: https://vjudge.net/problem/POJ-3295 题目大意: 输入由p.q.r.s.t.K.A.N.C.E共10个字母组成的逻辑表达式WFF      其中      ...

  3. POJ-3295 Tautology (构造)

    https://vjudge.net/problem/POJ-3295 题意 有五种运算符和五个参数,现在给你一个不超过100字符的算式,问最后结果是否恒为1? 分析 首先明确各运算符的意义,K(&a ...

  4. poj3295 Tautology —— 构造法

    题目链接:http://poj.org/problem?id=3295 题意: 输入由p.q.r.s.t.K.A.N.C.E共10个字母组成的逻辑表达式, 其中p.q.r.s.t的值为1(true)或 ...

  5. poj3295解题报告(构造、算术表达式运算)

    POJ 3952,题目链接http://poj.org/problem?id=3295 题意: 输入由p.q.r.s.t.K.A.N.C.E共10个字母组成的逻辑表达式, 其中p.q.r.s.t的值为 ...

  6. POJ3295——Tautology

    Tautology Description WFF 'N PROOF is a logic game played with dice. Each die has six faces represen ...

  7. POJ3295 Tautology(枚举)

    题目链接. 分析: 最多有五个变量,所以枚举所有的真假值,从后向前借助于栈验证是否为永真式. #include <iostream> #include <cstring> #i ...

  8. poj3295 Tautology , 计算表达式的值

    给你一个表达式,其包括一些0,1变量和一些逻辑运算法,让你推断其是否为永真式. 计算表达式的经常使用两种方法:1.递归: 2.利用栈. code(递归实现) #include <cstdio&g ...

  9. POJ3295 Tautology(栈+枚举)

    Description WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some ...

随机推荐

  1. C#基础知识系列六(静态类和静态类成员)

    静态类 静态类与非静态类基本相同,但存在一个区别:静态类不能实例化. 也就是说,不能使用 new 关键字创建静态类类型的变量. 因为没有实例变量,所以要使用类名本身访问静态类的成员. 例如,如果名为 ...

  2. Daily Scrum – 1/7

    Meeting Minutes 搞定了一个bug,单词面板滚动条的bug: 在电脑屏幕上的屏幕适配有了新思路: Progress   part 组员 今日工作 Time (h) 明日计划 Time ( ...

  3. python 2.7的安装

    最近准备入手学习python 这里我是按照:http://blog.csdn.net/jcjc918/article/details/11022345 来的 我在安装python 3 的时候发现上下左 ...

  4. jdownload的使用

    <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <m ...

  5. BZOJ2120 数颜色

    Description 墨墨购买了一套N支彩色画笔(其中有些颜色可能相同),摆成 一排,你需要回答墨墨的提问.墨墨会像你发布如下指令: 1. Q L R代表询问你从第L支画笔到第R支画笔中共有几种不同 ...

  6. groovy-运算符

    算术和条件运算符 Groovy支”!”操作符,例如: 1 def expression = false 2 assert !expression 基于集合的运算符: Spread Operator ( ...

  7. HD1385Minimum Transport Cost(Floyd + 输出路径)

    Minimum Transport Cost Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/O ...

  8. idea修改运行内存

    安装目录下的bin 找到idea.exe.vmoptions 最大的修改下-Xmx1024m 找到idea64.exe.vmoptions 最大的修改下-Xmx1024m

  9. Servlet之Filter详细讲解

    Filter,过滤器,顾名思义,即是对数据等的过滤,预处理过程.为什么要引入过滤器呢?在平常访问网站的时候,有时候发一些敏感的信息,发出后显示时 就会将敏感信息用*等字符替代,这就是用过滤器对信息进行 ...

  10. 浏览器的中的 XMLHttpRequest 对象的使用

    使用XMLHttpRequest浏览器对象(IE5.IE6中是ActiveXObject对象)可以实现异步请求,Ajax就是以此为基础进行的封装. 1.同步与异步: <script type=& ...