js开发相关

获取url中的参数

(function ($) {
  $.getUrlParam = function (name) {
    var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)");
    var r = decodeURI(location.search).substr(1).match(reg);
    if (r != null) return unescape(r[2]); return null;
  }
})(jQuery);