LeetCode(56)-Add Binary
题目:
Given two binary strings, return their sum (also a binary string).
For example,
a = "11"
b = "1"
Return "100".
思路:
- 题意:对字符串的二进制数字,计算
- 把二进制转化为整数,设置变量carry位进位,sum%2,是相应的数字,carry = sum/2
-
代码:
public class Solution {
public String addBinary(String a, String b) {
if(a.length() < b.length()){
String tmp = a;
a = b;
b = tmp;
}
int lengthA = a.length()-1;
int lengthB = b.length()-1;
int carry = 0;
String all = "";
while(lengthB >= 0){
int num = (int)(a.charAt(lengthA)-'0')+(int)(b.charAt(lengthB)-'0')+carry;
int k = num%2;
carry = num/2;
all = String.valueOf(k)+all;
lengthA--;
lengthB--;
}
while(lengthA >= 0){
int num = (int)(a.charAt(lengthA)-'0')+carry;
int k = num%2;
carry = num/2;
all = String.valueOf(k)+all;
lengthA--;
}
if(carry == 1){
all = "1"+all;
}
return all;
}
}
LeetCode(56)-Add Binary的更多相关文章
- LeetCode 面试:Add Binary
1 题目 Given two binary strings, return their sum (also a binary string). For example,a = "11&quo ...
- LeetCode 67. Add Binary (二进制相加)
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = ...
- [LeetCode] 67. Add Binary 二进制数相加
Given two binary strings, return their sum (also a binary string). The input strings are both non-em ...
- 【leetcode】Add Binary
题目简述: Given two binary strings, return their sum (also a binary string). For example, a = "11&q ...
- Java for LeetCode 067 Add Binary
Given two binary strings, return their sum (also a binary string). For example, a = "11" b ...
- LeetCode 67. Add Binary
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = ...
- Java [Leetcode 67]Add Binary
题目描述: Given two binary strings, return their sum (also a binary string). For example,a = "11&qu ...
- (String) leetcode 67. Add Binary
Given two binary strings, return their sum (also a binary string). The input strings are both non-em ...
- [leetcode]67. Add Binary 二进制加法
Given two binary strings, return their sum (also a binary string). The input strings are both non-em ...
随机推荐
- iOS开发之*.a静态库注意事项
以*.a静态库的形式引入工程的(比如:libUploadLib.a),*.a里面的class有category形式实现时,除了在工程Target的 Build Phases里面的 Link Binar ...
- <<精通iOS开发>>第14章例子代码小缺陷的修复
大熊猫猪·侯佩原创或翻译作品.欢迎转载,转载请注明出处. 如果觉得写的不好请多提意见,如果觉得不错请多多支持点赞.谢谢! hopy ;) 首先推荐大家看这本书,整本书逻辑非常清晰,代码如何从无到有,到 ...
- android自定义View-继承
介绍anroid通过继承系统的控件自定义view 方法是通过对OnDraw()方法进行复写来实现的 举例继承TextView 在textView的背景加上矩形的效果 代码实现 testView的代码 ...
- 04 Spinner 列表选中
<span style="font-size:18px;"> <?xml version="1.0" encoding="utf-8 ...
- 深入浅出Java Dom4j读取XML
在以前自己使用的xml较少,只是了解其很强大,现在可算是在DRP中,真正的开始使用它了,以前只是简单的理解xml,xml即可扩展标记语言,简单的使用,具体是什么?怎么用?还是一直让自己期待的. 首先来 ...
- [GitHub]第三讲:简单分支操作
Git 最核心的操作对象是版本( commit ),最核心的操作技巧就是分支. 什么是分支? 仓库创建后,一旦有了新 commit,默认就会放到一个分支上,名字叫 master.前面咱们一直看到的多个 ...
- Android学习笔记之AppWidget
什么是AppWidget?AppWidget就是我们平常在桌面上见到的那种一个个的小窗口,利用这个小窗口可以给用户提供一些方便快捷的操作. 今天的目标就是怎么创建一个简单的AppWidget. 首先我 ...
- UNIX环境高级编程——线程同步之互斥锁、读写锁和条件变量(小结)
一.使用互斥锁 1.初始化互斥量 pthread_mutex_t mutex =PTHREAD_MUTEX_INITIALIZER;//静态初始化互斥量 int pthread_mutex_init( ...
- 解决 RtlCreateActivationContext() failed 0xc000000d
gtest 示例的Debug版启动报错: Debug输出如下: 'sample1_unittest.exe': Loaded 'D:\LibSrc\gtest_1.7.0_build\Debug\sa ...
- Linux Shell -- 无网不利
这篇文章中我介绍几个非常实用的和网络相关的命令 一.ifconfig 这个命令在Windows下被"翻译为ipconfig",它用于显示网络接口,子网掩码等详细信息. 注:在每个系 ...