HDUOJ-----Robot Motion
Robot Motion
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 5011 Accepted Submission(s): 2321
A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are
N north (up the page)
S south (down the page)
E east (to the right on the page)
W west (to the left on the page)
For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid.
Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits.
You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around.
#include<cstdio>
#include<cstring>
const int maxn=;
char maze[][maxn];
int record[][maxn];
int main()
{
int r,c,pos,i,j;
while(scanf("%d%d",&r,&c),r+c)
{
scanf("%d",&pos);
memset(maze,'\0',sizeof maze);
memset(record,,sizeof record);
for( i=;i<r;i++)
{
scanf("%s",maze[i]);
}
int newr=,newc=pos-;
bool judge=true;
while(newc>=&&newr>=&&maze[newr][newc]!=)
{
record[newr][newc]++;
if(record[newr][newc]==)
{
judge=false;
break;
} switch(maze[newr][newc])
{
case 'N': newr--; break; //up
case 'S': newr++; break; //down
case 'E': newc++; break; //right
case 'W': newc--; break; //left }
}
int step=,circle=;
for( i=;i<r;i++)
{
for( j=;j<c;j++)
{
if(record[i][j]==)
step++;
else
if(record[i][j]!=)
circle++; }
} if(judge)
printf("%d step(s) to exit\n",step);
else
printf("%d step(s) before a loop of %d step(s)\n",step,circle);
}
return ;
}
HDUOJ-----Robot Motion的更多相关文章
- poj1573 Robot Motion
Robot Motion Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 12507 Accepted: 6070 Des ...
- Robot Motion(imitate)
Robot Motion Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 11065 Accepted: 5378 Des ...
- 模拟 POJ 1573 Robot Motion
题目地址:http://poj.org/problem?id=1573 /* 题意:给定地图和起始位置,robot(上下左右)一步一步去走,问走出地图的步数 如果是死循环,输出走进死循环之前的步数和死 ...
- POJ 1573 Robot Motion(BFS)
Robot Motion Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 12856 Accepted: 6240 Des ...
- Robot Motion 分类: POJ 2015-06-29 13:45 11人阅读 评论(0) 收藏
Robot Motion Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 11262 Accepted: 5482 Descrip ...
- POJ 1573 Robot Motion
Robot Motion Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 12978 Accepted: 6290 Des ...
- Poj OpenJudge 百练 1573 Robot Motion
1.Link: http://poj.org/problem?id=1573 http://bailian.openjudge.cn/practice/1573/ 2.Content: Robot M ...
- POJ1573——Robot Motion
Robot Motion Description A robot has been programmed to follow the instructions in its path. Instruc ...
- hdoj 1035 Robot Motion
Robot Motion Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Tota ...
- HDU-1035 Robot Motion
http://acm.hdu.edu.cn/showproblem.php?pid=1035 Robot Motion Time Limit: 2000/1000 MS (Java/Others) ...
随机推荐
- Reverse Words in a String leetcode java
题目: Given an input string, reverse the string word by word. For example, Given s = "the sky is ...
- Gridview 单选效果实现,且用且珍惜
Gridview 单选效果,在androidapp中实现非常频繁,我这里提供我的一种思路,这是我的思维导图: 怎么样将这样的思维导图翻译成java代码了,请看下面的代码了: // 电子产品的图片列表信 ...
- python2.7 调用 .net的webservice asmx
首先安装pip install suds 或下载:https://pypi.org/project/suds-jurko/0.6/#files 这个是最新版本 由于不支持python3.6, 所以只能 ...
- LAMP架构之PHP-FPM 服务器
PHP简介 安装PHP 解决依赖关系 # 请配置好yum源(系统安装源及epel源)后执行如下命令: yum -y groupinstall "Desktop Platform Develo ...
- javascript——获取列表选择行的列值
表格布局 方法 代码 $("#send").click(function(){ //获取选择的行号 n= $('input:radio[name="radio" ...
- JAVA-开发IDE版本
Eclipse发布的完整列表包括: Neon, June 22, 2016 Mars, June 24, 2015 Luna, June 25, 2014 Kepler, June 26, 2013 ...
- Git直接拉取远程分支
用Git,一直有个疑惑,可不可以不拉取远程Origin主干,我直接pull一个分支下来 今天想了一下,找到了一个办法 本地分支关联 // 0.新建一个文件夹,然后初始化git git init // ...
- Python标准库:内置函数type(object)
type(object) type(name, bases, dict) 本函数是返回对象的类型对象.仅仅有一个參数object时,直接返回对象的类型对象.假设仅仅是想推断一个对象是否属于某一个类的对 ...
- .Net 泛型约束
本文内容 使用泛型约束的原因 未绑定的类型参数 作为约束的类型参数 参考资料 当"设计模式"出现时,人们提"用接口编程":后来,有了泛型,人们提"用泛 ...
- javascript64位加密
var base64 = new Object(); base64.settings = { char: "+/", pad: "=", ascii: fals ...