区间dp 51nod1021

题目链接：https://www.51nod.com/Challenge/ProblemSubmitDetail.html#!#judgeId=673021

代码：

参考博客：https://blog.csdn.net/qq_40772692/article/details/80183248

#include<iostream>
#include<cstring>
#include<algorithm>
#include<queue>
#include<map>
#include<stack>
#include<cmath>
#include<vector>
#include<set>
#include<cstdio>
#include<string>
#include<deque>
using namespace std;
typedef long long LL;
#define eps 1e-8
#define INF 0x3f3f3f3f
#define maxn 105
/*struct point{
    int u,w;
};
bool operator <(const point &s1,const point &s2)
{
    if(s1.w!=s2.w)
    return s1.w>s2.w;
    else
    return s1.u>s2.u;
}*/
int n,m,k,t;
int dp[maxn][maxn],value[maxn];
int main()
{
    while(scanf("%d",&n)!=EOF){
        for(int i=;i<=maxn-;i++){
            for(int j=;j<=maxn-;j++){
                dp[i][j]=INF;//初始化
            }
        }
        memset(value,,sizeof(value));
        for(int i=;i<=n;i++){
            scanf("%d",&dp[i][i]);//这里偷懒了，用dp[i][i]这是存了一下输入的值
            value[i]=value[i-]+dp[i][i];//前缀和
            dp[i][i]=;//自己合并自己代价为0
        }
        dp[][]=;
        for(int len=;len<=n;len++){//枚举长度
            for(int i=;i+len-<=n;i++){//枚举起点
            int ends=i+len-;//终点
                for(int j=i;j<=ends;j++){//枚举切割点
                    dp[i][ends]=min(dp[i][ends],dp[i][j]+dp[j+][ends]+value[ends]-value[i-]);
                }
            }
        }
        printf("%d\n",dp[][n]);
    }
    return ;
}