http://acm.hdu.edu.cn/showproblem.php?pid=1398

Square Coins

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6697    Accepted Submission(s): 4521

Problem Description
People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (=17^2), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.
There are four combinations of coins to pay ten credits:

ten 1-credit coins,
one 4-credit coin and six 1-credit coins,
two 4-credit coins and two 1-credit coins, and
one 9-credit coin and one 1-credit coin.

Your mission is to count the number of ways to pay a given amount using coins of Silverland.

 
Input
The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.
 
Output
For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.
 
Sample Input
2 10 30 0
 
Sample Output
1 4 27
 
Source
 
Recommend
Ignatius.L
 母函数.......
 #include<iostream>
using namespace std;
int main()
{
int n,i,j,k;
while(cin>>n,n)
{
int c1[]={},c2[]={};
for(j=;j<=n;j++)
{
c1[j]=;
}
for(i=;i*i<=n;i++)
{
for(j=;j<=n;j++)
{
for(k=;k+j<=n;k+=i*i)
{
c2[k+j]+=c1[j];
}
}
for(j=;j<=n;j++)
{
c1[j]=c2[j];
c2[j]=;
}
}
cout<<c1[n]<<endl;
}
return ;
}

HDUOJ ------1398的更多相关文章

  1. hduoj 1455 && uva 243 E - Sticks

    http://acm.hdu.edu.cn/showproblem.php?pid=1455 http://uva.onlinejudge.org/index.php?option=com_onlin ...

  2. hduoj 4712 Hamming Distance 2013 ACM/ICPC Asia Regional Online —— Warmup

    http://acm.hdu.edu.cn/showproblem.php?pid=4712 Hamming Distance Time Limit: 6000/3000 MS (Java/Other ...

  3. hduoj 4706 Herding 2013 ACM/ICPC Asia Regional Online —— Warmup

    hduoj 4706 Children's Day 2013 ACM/ICPC Asia Regional Online —— Warmup Herding Time Limit: 2000/1000 ...

  4. hdu 1398 Square Coins(生成函数,完全背包)

    pid=1398">链接:hdu 1398 题意:有17种货币,面额分别为i*i(1<=i<=17),都为无限张. 给定一个值n(n<=300),求用上述货币能使价值 ...

  5. hdu-oj 1874 畅通工程续

    最短路基础 这个题目hdu-oj 1874可以用来练习最短路的一些算法. Dijkstra 无优化版本 #include<cstdio> #include<iostream> ...

  6. C#版 - HDUoj 5391 - Zball in Tina Town(素数) - 题解

    版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. HDUoj 5 ...

  7. C++版 - HDUoj 2010 3阶的水仙花数 - 牛客网

    版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C++版 - ...

  8. 【BZOJ 1398】 1398: Vijos1382寻找主人 Necklace (最小表示法)

    1398: Vijos1382寻找主人 Necklace Time Limit: 5 Sec  Memory Limit: 128 MBSubmit: 308  Solved: 129 Descrip ...

  9. [hdu 1398]简单dp

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1398 看到网上的题解都是说母函数……为什么我觉得就是一个dp就好了,dp[i][j]表示只用前i种硬币 ...

随机推荐

  1. Android图片加载框架最全解析(七),实现带进度的Glide图片加载功能

    我们的Glide系列文章终于要进入收尾篇了.从我开始写这个系列的第一篇文章时,我就知道这会是一个很长的系列,只是没有想到竟然会写这么久. 在前面的六篇文章中,我们对Glide的方方面面都进行了学习,包 ...

  2. 终端控制类getopt isatty select ttyname

    getopt(分析命令行参数) 相关函数 表头文件 #include<unistd.h> 定义函数 int getopt(int argc,char * const argv[ ],con ...

  3. Android DiskLruCache 源代码解析 硬盘缓存的绝佳方案

    转载请标明出处: http://blog.csdn.net/lmj623565791/article/details/47251585: 本文出自:[张鸿洋的博客] 一.概述 依然是整理东西.所以最近 ...

  4. UVA 10194 (13.08.05)

    :W Problem A: Football (aka Soccer)  The Problem Football the most popular sport in the world (ameri ...

  5. AS .ignore插件 忽略文件

    AS自带的.ignore文件 在AS中新建项目时,默认会创建一个.ignore文件,其中默认忽略的是 *.iml .gradle /local.properties /.idea/workspace. ...

  6. 敏捷方法之极限编程(XP)和 Scrum区别

    敏捷(Agile)作为一种开发流程, 目前为各大公司所采用, 敏捷流程的具体实践有XP 和Scrum, 似乎很少有文章介绍这两者的区别, 发现一篇外文, 见解非常深刻, 特将其翻译一把. 原文(DIF ...

  7. 导出DLLRegisterServer接口遇到的问题

    I'm trying to add DLLRegisterServer and DLLUnregisterServer entry points to an existing DLL that is ...

  8. [React] Simplify and Convert a Traditional React Form to Formik

    Forms in React are not easy. T render() { return ( <React.Fragment> <h2>Regular Maintena ...

  9. windows 用户变量和系统变量的差别

    点击"我的电脑→属性→高级系统设置"标签的"环境变量"button,出现"环境变量"对话框,假设当前是以Administrator登录系统的 ...

  10. 利用js_API 执行对html文档元素的属性的CRUD操作

    转自:http://my.oschina.net/felay/blog/303470 <!DOCTYPE html> <html> <head> <meta ...