POJ2533Longest Ordered Subsequence(DP)
http://poj.org/problem?id=2533
在经典不过的DP题目了。。。。

#include <map>
#include <set>
#include <stack>
#include <queue>
#include <cmath>
#include <ctime>
#include <vector>
#include <cstdio>
#include <cctype>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;
#define INF 0x3f3f3f3f
#define MAX(a,b) (a > b ? a : b)
#define MIN(a,b) (a < b ? a : b)
#define mem0(a) memset(a,0,sizeof(a)) typedef long long LL;
const double eps = 1e-;
const int MAXN = ;
const int MAXM = ; int DP[], a[], N; int BinarySearch(int low, int high, int val)
{
while(low < high)
{
int mid = (low + high) >> ;
if(DP[mid] < val) low = mid +;
else high = mid;
}
return low;
} int main()
{
while(~scanf("%d", &N))
{
for(int i=;i<=N;i++)
{
scanf("%d", &a[i]);
}
DP[] = a[];
int len = ;
for(int i=;i<=N;i++)
{
int id = BinarySearch(, len+, a[i]);
DP[id] = a[i];
if(id > len) ++len;
}
printf("%d\n", len);
}
return ;
}
POJ2533Longest Ordered Subsequence(DP)的更多相关文章
- poj2533--Longest Ordered Subsequence(dp:最长上升子序列)
Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 33943 Acc ...
- POJ 2533-Longest Ordered Subsequence(DP)
Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 34454 Acc ...
- POJ 2533——Longest Ordered Subsequence(DP)
链接:http://poj.org/problem?id=2533 题解 #include<iostream> using namespace std; ]; //存放数列 ]; //b[ ...
- POJ 2533 Longest Ordered Subsequence(DP 最长上升子序列)
Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 38980 Acc ...
- POJ 2533 Longest Ordered Subsequence(dp LIS)
Language: Default Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submis ...
- Poj 2533 Longest Ordered Subsequence(LIS)
一.Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequenc ...
- poj-2533 longest ordered subsequence(动态规划)
Time limit2000 ms Memory limit65536 kB A numeric sequence of ai is ordered if a1 < a2 < ... &l ...
- HPU第三次积分赛-D:Longest Increasing Subsequence(DP)
Longest Increasing Subsequence 描述 给出一组长度为n的序列,a1,a2,a3,a4...an, 求出这个序列长度为k的严格递增子序列的个数 输入 第一行输入T ...
- HDU 1159 Common Subsequence (dp)
题目链接 Problem Description A subsequence of a given sequence is the given sequence with some elements ...
随机推荐
- [转][TFS] 禁止默认允许多人签出和强制解除签入签出锁
转自:http://blog.xieyc.com/tfs-disable-multiple-check-out-and-force-to-undo-locking/ | 小谢的小站 [TFS] 禁止默 ...
- PHP学习笔记06——面向对象版图形计算器
index.php 用于显示页面 <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "h ...
- 【Python】控制流语句、函数、模块、数据结构
1.三种控制流语句:if\for\while 2.每句后都要加冒号 3.有elif语句=else后加一个if 注意使用变量名! 注意缩进! 注意控制流语句后面要加冒号! 4.for i in rang ...
- Android 自定义RadioButton的样式
Android 自定义RadioButton的样式 我们知道Android控件里的button,listview可以用xml的样式自定义成自己希望的漂亮样式. 最近用到RadioButton,利用xm ...
- Android 开源项目DiskLruCache 详解
有兴趣的同学可以读完这篇文章以后 可以看看这个硬盘缓存和volley 或者是其他 图片缓存框架中使用的硬盘缓存有什么异同点. 讲道理的话,其实硬盘缓存这个模块并不难写,难就难在 你要考虑到百分之0.1 ...
- GenericRepository
public interface IGenericRepository<TEntity> where TEntity : class { IQueryable<TEntity> ...
- php5.2转向 PHP 5.3 的 PHP 开发
PHP 5.3 开始,为了更好的向 PHP 的未来版本(PHP6) 过渡,将未来不再支持的函数标记为 DEPRECATED.在代码中使用这些函数,将毫不留情的在页面中显示警告信息:“使用了过时的函数… ...
- oracle sql语句跟踪
select b.SQL_TEXT,b.FIRST_LOAD_TIME,b.SQL_FULLTEXT from v$sqlarea b order by b.FIRST_LOAD_TIM ...
- .net core学习
http://www.cnblogs.com/artech/ http://www.blogs8.cn/posts/AA0E630 http://pan.baidu.com/s/1bo4fJ47 ht ...
- SoapUI中Groovy的实用方法
1.依照上次结果判断下步是否执行: import com.eviware.soapui.model.testsuite.TestStepResult.TestStepStatus myTestStep ...