【HDOJ】1058 Humble Numbers

简单题，注意打表，以及输出格式。这里使用了可变参数。

 #include <stdio.h>

 #define MAXNUM 5845
 #define ANS    2000000000

 int buf[MAXNUM];
 int min(int a, int b) {
     return a<b ? a:b;
 }

 int minn(int argc, ...) {
     int i, tmp;
     int *arg = &argc + ;

     tmp = *arg;
     for (i=; i<argc; ++i)
         tmp = min(tmp, *++arg);

     return tmp;
 }

 int main() {
     int i;
     int a, b, c, d;
     int ia, ib, ic, id;
     ia = ib = ic = id = ;

     i = ;
     buf[] = ;

     a =  * buf[ia];
     b =  * buf[ib];
     c =  * buf[ic];
     d =  * buf[id];
     while (buf[i] < ANS) {
         buf[++i] = minn(, a,b,c,d);
         if (buf[i] == a)  a = *buf[++ia];
         if (buf[i] == b)  b = *buf[++ib];
         if (buf[i] == c)  c = *buf[++ic];
         if (buf[i] == d)  d = *buf[++id];
     }

     while (scanf("%d", &i)!=EOF && i) {
         if (i%== && i%!=)
             printf("The %dst humble number is %d.\n", i, buf[i]);
         else if (i%== && i%!=)
             printf("The %dnd humble number is %d.\n", i, buf[i]);
         else if (i%== && i%!=)
             printf("The %drd humble number is %d.\n", i, buf[i]);
         else
             printf("The %dth humble number is %d.\n", i, buf[i]);
     }

     return ;
 }