LeetCode 181. Employees Earning More Than Their Managers (超过经理收入的员工)
题目标签:
题目给了我们一个 员工表,包括经理。员工会有经理的id。
这里可以重复 利用两次 表格,表格a, 表格b,当a 员工的经理id 等于 b员工时候,在从中找到员工工资大于经理的。具体看code。
Java Solution:
Runtime: 312 ms, faster than 65 %
Memory Usage: N/A
完成日期:05/22/2019
关键点:From 员工表a,b
# Write your MySQL query statement below
SELECT a.Name AS Employee
FROM Employee a, Employee b
WHERE a.ManagerId = b.Id AND a.Salary > b.Salary
参考资料:LeetCode Solution
LeetCode 题目列表 - LeetCode Questions List
题目来源:https://leetcode.com/
LeetCode 181. Employees Earning More Than Their Managers (超过经理收入的员工)的更多相关文章
- Leetcode 181. Employees Earning More Than Their Managers
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- leetcode 181 Employees Earning More Than Their Managers 不会分析的数据库复杂度
https://leetcode.com/problems/employees-earning-more-than-their-managers/description/ 老师上课没分析这些的复杂度, ...
- 181. 超过经理收入的员工 + join + MySql
181. 超过经理收入的员工 LeetCode_MySql_181 题目描述 方法一:笛卡尔积 # Write your MySQL query statement below select e1.N ...
- LeetCode:181.超过经理收入的员工
题目链接:https://leetcode-cn.com/problems/employees-earning-more-than-their-managers/ 题目 Employee 表包含所有员 ...
- [LeetCode] 181. Employees Earning More Than Their Managers_Easy tag: SQL
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- 【SQL】181. Employees Earning More Than Their Managers
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- 181. Employees Earning More Than Their Managers
The Employee table holds all employees including their managers. Every employee has an Id, and there ...
- LeetCode SQL:Employees Earning More Than Their Managers
# Write your MySQL query statement below SELECT a.Name FROM Employee AS a INNER JOIN Employee AS b O ...
- [SQL]LeetCode181. 超过经理收入的员工 | Employees Earning More Than Their Managers
SQL架构 Create table If Not Exists Employee (Id ), Salary int, ManagerId int) Truncate table Employee ...
随机推荐
- Android中的隐藏API和Internal包的使用之获取应用电量排行
今天老大安排一个任务叫我获取手机中应用耗电排行(时间是前天晚上7点到第二天早上10点),所以在网上各种搜索,没想到这种资料还是很多的,发现了一个主要的类:PowerProfile,但是可以的是,这个类 ...
- bzoj1072题解
[解题思路] 状压DP.f[i][j][k]表示当前DP到第i位,模d意义下余数为j,状态为k的方案数.其中状态k表示每个数字还剩多少个没取,状态数最多210. 于是有递推式转移方程:f[i+1][( ...
- 离线+生成树+并查集——cf1213G
#include<bits/stdc++.h> using namespace std; #define N 200005 #define ll long long struct Edge ...
- UDP 协议解析 - 1
目录 1. 概述 2. UDP 的主要特点 3. UDP 的首部格式 3. UDP 校验和 3.1 伪首部 3.2 UDP 校验和计算方法 [参考文献] 1. 概述 用户数据报协议(UDP,User ...
- 词表征 1:WordNet、0-1表征、共现矩阵、SVD
原文地址:https://www.jianshu.com/p/c1e4f42b78d7 一.基于知识的表征 参见图1.1,WordNet中包含同义词集(synonym sets)和上位词(hypern ...
- C++ 操作json文件
一.环境搭建: 参考文章:https://blog.csdn.net/fakine/article/details/79272090 二.创建实例: #include <stdio.h> ...
- hadoop命令行
持续更新中................ 1. 设置目录配额 命令:hadoop dfsadmin -setSpaceQuota 样例:hadoop dfsadmin -setSpaceQuota ...
- C# WinfForm 控件之dev报表 XtraReport (七)报表合并
这个不是太难,新建两个报表 一个form窗体 窗体上放个documentView 代码如下 XtraReport2 xr2 = new XtraReport2(); xr2.CreateDocume ...
- 匈牙利算法实战codevs1022覆盖
1022 覆盖 时间限制: 1 s 空间限制: 128000 KB 题目等级 : 大师 Master 题解 查看运行结果 题目描述 Description 有一个N×M的单位方格中 ...
- js drag drop 收藏夹拖拽移除的简单例子
代码 <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title& ...